是否存在在一次操作中截断数据库中所有表的查询(命令)?我想知道我是否可以用一个查询做到这一点。


当前回答

溶液(1)

mysql> select group_concat('truncate',' ',table_name,';') from information_schema.tables where table_schema="db_name" into outfile '/tmp/a.txt';
mysql> /tmp/a.txt;

溶液2)

- Export only structure of a db
- drop the database
- import the .sql of structure 

——编辑----

earlier in solution 1, i had mentioned concat() instead of group_concat() which would have not returned the desired result

其他回答

TB=$( mysql -Bse "show tables from DATABASE" );
for i in ${TB};
    do echo "Truncating table ${i}";
    mysql -e "set foreign_key_checks=0; set unique_checks=0;truncate table DATABASE.${i}; set foreign_key_checks=1; set unique_checks=1";
    sleep 1;
done

--

大卫,

感谢您花时间格式化代码,但这是它应该如何应用。

库尔特

在UNIX或Linux机器上:

确保您处于bash shell中。从命令行运行这些命令,如下所示。

注意:

我将凭据存储在~/.my.cnf文件中,因此不需要在命令行上提供凭据。

注意:

CPM是数据库名称

我只展示了来自每个命令的结果的一小部分示例。

找到你的外键约束:

klarsen@Chaos:~$ mysql -Bse "select concat(table_name, ' depends on ', referenced_table_name)
             from information_schema.referential_constraints
             where constraint_schema = 'cpm'
             order by referenced_table_name"

Approval_external_system依赖于approval_request 地址视客户而定 Customer_identification取决于客户 External_id取决于客户 凭证取决于客户 Email_address取决于客户 Approval_request取决于客户 Customer_status取决于客户 Customer_image取决于客户

列出表和行数:

klarsen@Chaos:~$ mysql -Bse "SELECT table_name, table_rows FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = 'cpm'" | cat -n

 1  address 297
 2  approval_external_system    0
 3  approval_request    0
 4  country 189
 5  credential  468
 6  customer    6776
 7  customer_identification 5631
 8  customer_image  2
 9  customer_status 13639

截断你的表:

klarsen@Chaos:~$ TB=$( mysql -Bse "show tables from cpm" ); for i in ${TB}; do echo "Truncating table ${i}"; mysql -e "set foreign_key_checks=0; set unique_checks=0;truncate table cpm.${i}; set foreign_key_checks=1; set unique_checks=1"; sleep 1; done

截断表地址 截断表approval_external_system 截断表approval_request 截断表国家 截断表凭据 截断表客户 截断表customer_identification 截断表customer_image 截断表customer_status

验证它是否有效:

klarsen@Chaos:~$ mysql -Bse "SELECT table_name, table_rows FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA = 'cpm'" | cat -n

 1  address 0
 2  approval_external_system    0
 3  approval_request    0
 4  country 0
 5  credential  0
 6  customer    0
 7  customer_identification 0
 8  customer_image  0
 9  customer_status 0
10  email_address   0

在Windows机器上:

注意:

CPM是数据库名称

C:\>for /F "tokens=*" %a IN ('mysql -Bse "show tables" cpm') do mysql -e "set foreign_key_checks=0; set unique_checks=0; truncate table %a; foreign_key_checks=1; set unique_checks=1" cpm
<?php
// connect to database
$conn=mysqli_connect("localhost","user","password","database");

// check connection
if (mysqli_connect_errno()) {
  exit('Connect failed: '. mysqli_connect_error());
}

// sql query
$sql =mysqli_query($conn,"TRUNCATE " . TABLE_NAME);


// Print message
if ($sql === TRUE) {
  echo 'data delete successfully';
}
else {
 echo 'Error: '. $conn->error;
}

$conn->close();

?>

这是我用来清除一个表的代码片段。只需更改$conn info和TABLE_NAME。

我发现最简单的方法是像下面这样做,只需用自己的表名替换表名。重要的是确保最后一行永远是 设置FOREIGN_KEY_CHECKS = 1;

SET FOREIGN_KEY_CHECKS=0;
TRUNCATE `table1`;
TRUNCATE `table2`;
TRUNCATE `table3`;
TRUNCATE `table4`;
TRUNCATE `table5`;
TRUNCATE `table6`;
TRUNCATE `table7`;
SET FOREIGN_KEY_CHECKS=1;

我发现TRUNCATE表..外键约束有问题,即使在NOCHECK约束ALL之后,所以我使用DELETE FROM语句代替。这意味着身份种子不会被重置,你总是可以添加一个DBCC CHECKIDENT来实现这一点。

我使用下面的代码打印到消息窗口的sql截断数据库中的所有表,然后运行它。这只会让犯错变得更难。

EXEC sp_MSforeachtable 'PRINT ''ALTER TABLE ? NOCHECK CONSTRAINT ALL'''
EXEC sp_MSforeachtable 'print ''DELETE FROM ?'''
EXEC sp_MSforeachtable 'print ''ALTER TABLE ? WITH CHECK CHECK CONSTRAINT all'''

删除(即删除表格)

mysql -Nse 'show tables' DATABASE_NAME | while read table; do mysql -e "drop table $table" DATABASE_NAME; done

截断(即空表)

mysql -Nse 'show tables' DATABASE_NAME | while read table; do mysql -e "truncate table $table" DATABASE_NAME; done