这是一种获取递增或递减数据值的简单方法。

const date = new Date()
const inc = 1000 * 60 * 60 // an hour
const dec = (1000 * 60 * 60) * -1 // an hour

const _date = new Date(date)
return new Date(_date.getTime() + inc)
return new Date(_date.getTime() + dec)

SPRBRN是正确的。为了解释月和年的开始/结束，您需要转换为Epoch和返回。

你可以这样做:

var milliseconds = 0;          //amount of time from current date/time
var sec = 0;                   //(+): future
var min = 0;                   //(-): past
var hours = 2;
var days = 0;

var startDate = new Date();     //start date in local time (we'll use current time as an example)

var time = startDate.getTime(); //convert to milliseconds since epoch

//add time difference
var newTime = time + milliseconds + (1000*sec) + (1000*60*min) + (1000*60*60*hrs) + (1000*60*60*24*days);

var newDate = new Date(newTime); //convert back to date; in this example: 2 hours from right now

或者在一行中完成(其中变量名与上面相同:

var newDate =
    new Date(startDate.getTime() + millisecond +
        1000 * (sec + 60 * (min + 60 * (hours + 24 * days))));

通过返回Date对象的副本而不是改变其参数，使addHours方法不可变可能会更好。

Date.prototype.addHours= function(h){
    var copiedDate = new Date(this.getTime());
    copiedDate.setHours(copiedDate.getHours()+h);
    return copiedDate;
}

通过这种方式，您可以将一堆方法调用链接起来，而不用担心状态。

有点乱，但很管用!

给出如下日期格式:2019-04-03T15:58

  //Get the start date.
  var start = $("#start_date").val();
  //Split the date and time.
  var startarray = start.split("T");
  var date = startarray[0];
  var time = startarray[1];

  //Split the hours and minutes.
  var timearray = time.split(":");

  var hour = timearray[0];
  var minute = timearray[1];
  //Add an hour to the hour.
  hour++;
  //$("#end_date").val = start;
  $("#end_date").val(""+date+"T"+hour+":"+minute+"");

您的输出将是:2019-04-03 t16 . 58

Date.prototype.addHours= function(h){
    this.setHours(this.getHours()+h);
    return this;
}

测试:

alert(new Date().addHours(4));

两小时后找个约会对象，一句话。

您需要向new Date传递毫秒数。

let expiryDate = new Date(new Date().setHours(new Date().getHours() + 2));

        or

let expiryDate2 = new Date(Date.now() + 2 * (60 * 60 * 1000) );

let nowDate = new Date(); let expiryDate = new Date(new Date()。setHours(new Date().getHours() + 2)); let expiryDate2 = new Date(Date.now() + 2 * (60 * 60 * 1000)); console.log(‘现在’,nowDate); console.log(“到期”,expiryDate); console.log('expiry 2'， expiryDate2);