我想要这样的东西:

public class Stream
{
    public startTime;
    public endTime;

    public getDuration()
    {
        return startTime - endTime;
    }
}

同样重要的是,例如,如果startTime是23:00,endTime是1:00,则持续时间为2:00。

为了在Java中实现这一点,应该使用哪些类型?


当前回答

为了在Java中实现这一点,应该使用哪些类型?

简短的回答是长。现在,更多关于如何衡量……

System.currentTimeMillis()

“传统”的方法是使用System.currentTimeMillis():

long startTime = System.currentTimeMillis();
// ... do something ...
long estimatedTime = System.currentTimeMillis() - startTime;

o.a.c.l.t.StopWatch

注意,Commons Lang有一个StopWatch类,可以用来测量以毫秒为单位的执行时间。它有split(), suspend(), resume()等方法,允许在执行的不同点采取措施,您可能会发现方便。看一看。

System.nanoTime()

如果您正在寻找运行时间的极其精确的度量,您可能更喜欢使用System.nanoTime()。从它的javadoc:

long startTime = System.nanoTime();    
// ... the code being measured ...    
long estimatedTime = System.nanoTime() - startTime;

Jamon

另一种选择是使用JAMon,这是一种收集start()和stop()方法之间任何代码的统计信息(执行时间、命中次数、平均执行时间、最小值、最大值等)的工具。下面是一个非常简单的例子:

import com.jamonapi.*;
...
Monitor mon=MonitorFactory.start("myFirstMonitor");
...Code Being Timed...
mon.stop();

查看www.javaperformancetunning.com上的这篇文章,有很好的介绍。

使用AOP

最后,如果您不想让这些度量使您的代码变得混乱(或者如果您不能更改现有的代码),那么AOP将是一个完美的武器。我不打算深入讨论这个问题但我至少想提一下。

下面是一个使用AspectJ和JAMon的非常简单的方面(这里,切入点的短名称将用于JAMon监视器,因此调用thisJoinPoint.toShortString()):

public aspect MonitorAspect {
    pointcut monitor() : execution(* *.ClassToMonitor.methodToMonitor(..));

    Object arround() : monitor() {
        Monitor monitor = MonitorFactory.start(thisJoinPoint.toShortString());
        Object returnedObject = proceed();
        monitor.stop();
        return returnedObject;
    }
}

切入点定义可以很容易地调整为基于类名、包名、方法名或它们的任何组合来监视任何方法。度量实际上是AOP的一个完美用例。

其他回答

如果您正在编写一个必须处理持续时间的应用程序,那么请查看Joda-Time,它有专门处理持续时间、间隔和周期的类。你的getDuration()方法看起来可以返回一个Joda-Time Interval:

DateTime start = new DateTime(2004, 12, 25, 0, 0, 0, 0);
DateTime end = new DateTime(2005, 1, 1, 0, 0, 0, 0);

public Interval getInterval() {
    Interval interval = new Interval(start, end);
}

如果你喜欢使用Java的日历API,你可以试试这个,

Date startingTime = Calendar.getInstance().getTime();
//later on
Date now = Calendar.getInstance().getTime();
long timeElapsed = now.getTime() - startingTime.getTime();

值得注意的是

System.currentTimeMillis() has only millisecond accuracy at best. At worth its can be 16 ms on some windows systems. It has a lower cost that alternatives < 200 ns. System.nanoTime() is only micro-second accurate on most systems and can jump on windows systems by 100 microseconds (i.e sometimes it not as accurate as it appears) Calendar is a very expensive way to calculate time. (i can think of apart from XMLGregorianCalendar) Sometimes its the most appropriate solution but be aware you should only time long intervals.

我发现这段代码在计时时很有用:

public class Et {
    public Et() {
    reset();
    }
    public void reset() {
    t0=System.nanoTime();
    }
    public long t0() {
        return t0;
    }
    public long dt() {
        return System.nanoTime()-t0();
    }
    public double etms() {
    return etms(dt());
    }
    @Override public String toString() {
        return etms()+" ms.";
    }
    public static double etms(long dt) {
        return dt/1000000.; // 1_000_000. breaks cobertura
    }
    private Long t0;
}

我建立了一个格式化函数,基于我偷来的东西。我需要一种方法来“分析”日志消息中的内容,所以我需要一个固定长度的持续时间消息。

public static String GetElapsed(long aInitialTime, long aEndTime, boolean aIncludeMillis)
{
  StringBuffer elapsed = new StringBuffer();

  Map<String, Long> units = new HashMap<String, Long>();

  long milliseconds = aEndTime - aInitialTime;

  long seconds = milliseconds / 1000;
  long minutes = milliseconds / (60 * 1000);
  long hours = milliseconds / (60 * 60 * 1000);
  long days = milliseconds / (24 * 60 * 60 * 1000);

  units.put("milliseconds", milliseconds);
  units.put("seconds", seconds);
  units.put("minutes", minutes);
  units.put("hours", hours);
  units.put("days", days);

  if (days > 0)
  {
    long leftoverHours = hours % 24;
    units.put("hours", leftoverHours);
  }

  if (hours > 0)
  {
    long leftoeverMinutes = minutes % 60;
    units.put("minutes", leftoeverMinutes);
  }

  if (minutes > 0)
  {
    long leftoverSeconds = seconds % 60;
    units.put("seconds", leftoverSeconds);
  }

  if (seconds > 0)
  {
    long leftoverMilliseconds = milliseconds % 1000;
    units.put("milliseconds", leftoverMilliseconds);
  }

  elapsed.append(PrependZeroIfNeeded(units.get("days")) + " days ")
      .append(PrependZeroIfNeeded(units.get("hours")) + " hours ")
      .append(PrependZeroIfNeeded(units.get("minutes")) + " minutes ")
      .append(PrependZeroIfNeeded(units.get("seconds")) + " seconds ")
      .append(PrependZeroIfNeeded(units.get("milliseconds")) + " ms");

  return elapsed.toString();

}

private static String PrependZeroIfNeeded(long aValue)
{
  return aValue < 10 ? "0" + aValue : Long.toString(aValue);
}

和一个测试类:

import java.util.Calendar;
import java.util.Date;
import java.util.GregorianCalendar;

import junit.framework.TestCase;

public class TimeUtilsTest extends TestCase
{

  public void testGetElapsed()
  {
    long start = System.currentTimeMillis();
    GregorianCalendar calendar = (GregorianCalendar) Calendar.getInstance();
    calendar.setTime(new Date(start));

    calendar.add(Calendar.MILLISECOND, 610);
    calendar.add(Calendar.SECOND, 35);
    calendar.add(Calendar.MINUTE, 5);
    calendar.add(Calendar.DAY_OF_YEAR, 5);

    long end = calendar.getTimeInMillis();

    assertEquals("05 days 00 hours 05 minutes 35 seconds 610 ms", TimeUtils.GetElapsed(start, end, true));

  }

}