什么是等价的UI_USER_INTERFACE_IDIOM()在Swift检测之间的iPhone和iPad?
我得到一个使用未解决的标识符错误时,在Swift编译。
什么是等价的UI_USER_INTERFACE_IDIOM()在Swift检测之间的iPhone和iPad?
我得到一个使用未解决的标识符错误时,在Swift编译。
当前回答
Swift 2.0 & iOS 7+ / iOS 8+ / iOS 9+
public class Helper {
public class var isIpad:Bool {
if #available(iOS 8.0, *) {
return UIScreen.mainScreen().traitCollection.userInterfaceIdiom == .Pad
} else {
return UIDevice.currentDevice().userInterfaceIdiom == .Pad
}
}
public class var isIphone:Bool {
if #available(iOS 8.0, *) {
return UIScreen.mainScreen().traitCollection.userInterfaceIdiom == .Phone
} else {
return UIDevice.currentDevice().userInterfaceIdiom == .Phone
}
}
}
使用:
if Helper.isIpad {
}
OR
guard Helper.isIpad else {
return
}
由于@user3378170
其他回答
如果你想检查当前设备是iPad还是iPhone,那么你可以使用这些代码行:
if(UIDevice.currentDevice().userInterfaceIdiom == .Pad){
}else if(UIDevice.currentDevice().userInterfaceIdiom == .Phone){
}
如果寇/换:
if UIDevice.current.userInterfaceIdiom == .pad {
// iPad
} else {
// not iPad (iPhone, mac, tv, carPlay, unspecified)
}
Swift 2.0 & iOS 9 & Xcode 7.1
// 1. request an UITraitCollection instance
let deviceIdiom = UIScreen.mainScreen().traitCollection.userInterfaceIdiom
// 2. check the idiom
switch (deviceIdiom) {
case .Pad:
print("iPad style UI")
case .Phone:
print("iPhone and iPod touch style UI")
case .TV:
print("tvOS style UI")
default:
print("Unspecified UI idiom")
}
Swift 3.0和Swift 4.0
// 1. request an UITraitCollection instance
let deviceIdiom = UIScreen.main.traitCollection.userInterfaceIdiom
// 2. check the idiom
switch (deviceIdiom) {
case .pad:
print("iPad style UI")
case .phone:
print("iPhone and iPod touch style UI")
case .tv:
print("tvOS style UI")
default:
print("Unspecified UI idiom")
}
使用UITraitCollection。 iOS trait环境是通过UITraitEnvironment协议的traitCollection属性公开的。以下类采用此协议:
UIScreen ui窗口 ui UIPresentationController UIView
Swift 2.0 & iOS 7+ / iOS 8+ / iOS 9+
public class Helper {
public class var isIpad:Bool {
if #available(iOS 8.0, *) {
return UIScreen.mainScreen().traitCollection.userInterfaceIdiom == .Pad
} else {
return UIDevice.currentDevice().userInterfaceIdiom == .Pad
}
}
public class var isIphone:Bool {
if #available(iOS 8.0, *) {
return UIScreen.mainScreen().traitCollection.userInterfaceIdiom == .Phone
} else {
return UIDevice.currentDevice().userInterfaceIdiom == .Phone
}
}
}
使用:
if Helper.isIpad {
}
OR
guard Helper.isIpad else {
return
}
由于@user3378170
从iOS 13开始,UI_USER_INTERFACE_IDIOM已经弃用。如果你的代码仍然是Obj-C,你可以使用以下代码:
if (UIDevice.currentDevice.userInterfaceIdiom == UIUserInterfaceIdiomPad) {
// device is iPad
}
地点:
typedef NS_ENUM(NSInteger, UIUserInterfaceIdiom) {
UIUserInterfaceIdiomUnspecified = -1,
UIUserInterfaceIdiomPhone API_AVAILABLE(ios(3.2)), // iPhone and iPod touch style UI
UIUserInterfaceIdiomPad API_AVAILABLE(ios(3.2)), // iPad style UI
UIUserInterfaceIdiomTV API_AVAILABLE(ios(9.0)), // Apple TV style UI
UIUserInterfaceIdiomCarPlay API_AVAILABLE(ios(9.0)), // CarPlay style UI
};