cron is clearly a great choice for many purposes. However it doesn't create a service or daemon as you requested in the OP. cron just runs jobs periodically (meaning the job starts and stops), and no more often than once / minute. There are issues with cron -- for example, if a prior instance of your script is still running the next time the cron schedule comes around and launches a new instance, is that OK? cron doesn't handle dependencies; it just tries to start a job when the schedule says to.

如果您发现确实需要一个守护进程(一个永不停止运行的进程)，请查看一下监控器。它提供了一种简单的方法来包装普通的、非守护进程化的脚本或程序，并使其像守护进程一样运行。这比创建本地Python守护进程好得多。

这是一个很好的类，从这里采取:

#!/usr/bin/env python

import sys, os, time, atexit
from signal import SIGTERM

class Daemon:
        """
        A generic daemon class.

        Usage: subclass the Daemon class and override the run() method
        """
        def __init__(self, pidfile, stdin='/dev/null', stdout='/dev/null', stderr='/dev/null'):
                self.stdin = stdin
                self.stdout = stdout
                self.stderr = stderr
                self.pidfile = pidfile

        def daemonize(self):
                """
                do the UNIX double-fork magic, see Stevens' "Advanced
                Programming in the UNIX Environment" for details (ISBN 0201563177)
                http://www.erlenstar.demon.co.uk/unix/faq_2.html#SEC16
                """
                try:
                        pid = os.fork()
                        if pid > 0:
                                # exit first parent
                                sys.exit(0)
                except OSError, e:
                        sys.stderr.write("fork #1 failed: %d (%s)\n" % (e.errno, e.strerror))
                        sys.exit(1)

                # decouple from parent environment
                os.chdir("/")
                os.setsid()
                os.umask(0)

                # do second fork
                try:
                        pid = os.fork()
                        if pid > 0:
                                # exit from second parent
                                sys.exit(0)
                except OSError, e:
                        sys.stderr.write("fork #2 failed: %d (%s)\n" % (e.errno, e.strerror))
                        sys.exit(1)

                # redirect standard file descriptors
                sys.stdout.flush()
                sys.stderr.flush()
                si = file(self.stdin, 'r')
                so = file(self.stdout, 'a+')
                se = file(self.stderr, 'a+', 0)
                os.dup2(si.fileno(), sys.stdin.fileno())
                os.dup2(so.fileno(), sys.stdout.fileno())
                os.dup2(se.fileno(), sys.stderr.fileno())

                # write pidfile
                atexit.register(self.delpid)
                pid = str(os.getpid())
                file(self.pidfile,'w+').write("%s\n" % pid)

        def delpid(self):
                os.remove(self.pidfile)

        def start(self):
                """
                Start the daemon
                """
                # Check for a pidfile to see if the daemon already runs
                try:
                        pf = file(self.pidfile,'r')
                        pid = int(pf.read().strip())
                        pf.close()
                except IOError:
                        pid = None

                if pid:
                        message = "pidfile %s already exist. Daemon already running?\n"
                        sys.stderr.write(message % self.pidfile)
                        sys.exit(1)

                # Start the daemon
                self.daemonize()
                self.run()

        def stop(self):
                """
                Stop the daemon
                """
                # Get the pid from the pidfile
                try:
                        pf = file(self.pidfile,'r')
                        pid = int(pf.read().strip())
                        pf.close()
                except IOError:
                        pid = None

                if not pid:
                        message = "pidfile %s does not exist. Daemon not running?\n"
                        sys.stderr.write(message % self.pidfile)
                        return # not an error in a restart

                # Try killing the daemon process       
                try:
                        while 1:
                                os.kill(pid, SIGTERM)
                                time.sleep(0.1)
                except OSError, err:
                        err = str(err)
                        if err.find("No such process") > 0:
                                if os.path.exists(self.pidfile):
                                        os.remove(self.pidfile)
                        else:
                                print str(err)
                                sys.exit(1)

        def restart(self):
                """
                Restart the daemon
                """
                self.stop()
                self.start()

        def run(self):
                """
                You should override this method when you subclass Daemon. It will be called after the process has been
                daemonized by start() or restart().
                """

你应该使用python-daemon库，它会处理所有的事情。

从PyPI:库实现一个行为良好的Unix守护进程。

Ubuntu有一个非常简单的方法来管理服务。 对于python来说，不同之处在于所有依赖项(包)都必须在运行主文件的同一目录中。

我只是设法创建了这样一个服务，为我的客户提供天气信息。 步骤:

Create your python application project as you normally do. Install all dependencies locally like: sudo pip3 install package_name -t . Create your command line variables and handle them in code (if you need any) Create the service file. Something (minimalist) like: [Unit] Description=1Droid Weather meddleware provider [Service] Restart=always User=root WorkingDirectory=/home/ubuntu/weather ExecStart=/usr/bin/python3 /home/ubuntu/weather/main.py httpport=9570 provider=OWMap [Install] WantedBy=multi-user.target Save the file as myweather.service (for example) Make sure that your app runs if started in the current directory python3 main.py httpport=9570 provider=OWMap The service file produced above and named myweather.service (important to have the extension .service) will be treated by the system as the name of your service. That is the name that you will use to interact with your service. Copy the service file: sudo cp myweather.service /lib/systemd/system/myweather.service Refresh demon registry: sudo systemctl daemon-reload Stop the service (if it was running) sudo service myweather stop Start the service: sudo service myweather start Check the status (log file with where your print statements go): tail -f /var/log/syslog Or check the status with: sudo service myweather status Back to the start with another iteration if needed

此服务现在正在运行，即使您退出也不会受到影响。 如果主机关闭并重新启动，则此服务将重新启动…

要创建一些像service一样运行的东西，你可以使用这个东西:

你必须做的第一件事是安装水泥框架: 水泥框架是一个CLI框架，您可以在其上部署应用程序。

app命令行界面:

interface.py

 from cement.core.foundation import CementApp
 from cement.core.controller import CementBaseController, expose
 from YourApp import yourApp

 class Meta:
    label = 'base'
    description = "your application description"
    arguments = [
        (['-r' , '--run'],
          dict(action='store_true', help='Run your application')),
        (['-v', '--version'],
          dict(action='version', version="Your app version")),
        ]
        (['-s', '--stop'],
          dict(action='store_true', help="Stop your application")),
        ]

    @expose(hide=True)
    def default(self):
        if self.app.pargs.run:
            #Start to running the your app from there !
            YourApp.yourApp()
        if self.app.pargs.stop:
            #Stop your application
            YourApp.yourApp.stop()

 class App(CementApp):
       class Meta:
       label = 'Uptime'
       base_controller = 'base'
       handlers = [MyBaseController]

 with App() as app:
       app.run()

YourApp.py类:

 import threading

 class yourApp:
     def __init__:
        self.loger = log_exception.exception_loger()
        thread = threading.Thread(target=self.start, args=())
        thread.daemon = True
        thread.start()

     def start(self):
        #Do every thing you want
        pass
     def stop(self):
        #Do some things to stop your application

请记住，你的应用程序必须运行在一个线程作为守护进程

要运行应用程序，只需在命令行中这样做

Python interface.py——help

你有两个选择。

Make a proper cron job that calls your script. Cron is a common name for a GNU/Linux daemon that periodically launches scripts according to a schedule you set. You add your script into a crontab or place a symlink to it into a special directory and the daemon handles the job of launching it in the background. You can read more at Wikipedia. There is a variety of different cron daemons, but your GNU/Linux system should have it already installed. Use some kind of python approach (a library, for example) for your script to be able to daemonize itself. Yes, it will require a simple event loop (where your events are timer triggering, possibly, provided by sleep function).

我不建议你选择2。，因为您实际上是在重复cron功能。Linux系统范例是让多个简单工具交互并解决您的问题。除非有其他原因需要创建守护进程(除了定期触发之外)，否则选择其他方法。

此外，如果你使用daemonize进行循环并且发生了崩溃，那么没有人会在那之后检查邮件(正如Ivan Nevostruev在回答的评论中指出的那样)。而如果脚本作为cron作业添加，它将再次触发。