将Throwable.getStackTrace()的结果转换为描述堆栈跟踪的字符串最简单的方法是什么?


当前回答

下面是一个可以直接复制到代码中的版本:

import java.io.StringWriter; 
import java.io.PrintWriter;

//Two lines of code to get the exception into a StringWriter
StringWriter sw = new StringWriter();
new Throwable().printStackTrace(new PrintWriter(sw));

//And to actually print it
logger.info("Current stack trace is:\n" + sw.toString());

或者,在捕捉块中

} catch (Throwable t) {
    StringWriter sw = new StringWriter();
    t.printStackTrace(new PrintWriter(sw));
    logger.info("Current stack trace is:\n" + sw.toString());
}

其他回答

Scala版本

def stackTraceToString(e: Exception): String = {
  import java.io.PrintWriter
  val sw = new StringWriter()
  e.printStackTrace(new PrintWriter(sw))
  sw.toString
}
Arrays.toString(thrown.getStackTrace())

是将结果转换为字符串的最简单方法我在程序中使用这个来打印堆栈跟踪

LOGGER.log(Level.SEVERE, "Query Builder Issue Stack Trace : {0} ,Message : {1} objid {2}", new Object[]{Arrays.toString(e.getStackTrace()), e.getMessage(),objId});
public static String getStackTrace(Throwable t) {
    StringWriter sw = new StringWriter();
    t.printStackTrace(new PrintWriter(sw));
    return sw.toString();
}
 import java.io.PrintWriter;
import java.io.StringWriter;

public class PrintStackTrace {

    public static void main(String[] args) {

        try {
            int division = 0 / 0;
        } catch (ArithmeticException e) {
            StringWriter sw = new StringWriter();
            e.printStackTrace(new PrintWriter(sw));
            String exceptionAsString = sw.toString();
            System.out.println(exceptionAsString);
        }
    }
}

运行程序时,输出将类似:

java.lang.ArithmeticException: / by zero
at PrintStackTrace.main(PrintStackTrace.java:9)

选项很少

StringWriter sw=新StringWriter();e.printStackTrace(新的PrintWriter(sw));字符串异常AsString=sw.toString();使用Google Guava libString stackTrace=Throwables.getStackTraceAsString(myException);org.apache.commons.lang.exception.ExceptionUtils.getStackTrace(可丢弃)