用这个吧，它对我有用

function validUrl(Url) {
    var myRegExp  =/^(?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?$/i;

    if (!RegExp.test(Url.value)) {
        $("#urlErrorLbl").removeClass('highlightNew');
        return false;
    } 

    $("#urlErrorLbl").addClass('highlightNew'); 
    return true; 
}

我无法找到我正在寻找的正则表达式，所以我修改了一个正则表达式来满足我的要求，显然现在它似乎工作得很好。我的要求是:

匹配带有协议的url (www.gooogle.com) 使用查询参数和路径匹配url (http://subdomain.web-site.com/cgi-bin/perl.cgi?key1=value1&key2=value2e) 不要匹配有不可接受字符的url(例如。' '£)，例如:(www.google.com/somthing"/somethingmore)

以下是我的想法，任何建议都很感激:

@Test
    public void testWebsiteUrl(){
        String regularExpression = "((http|ftp|https):\\/\\/)?[\\w\\-_]+(\\.[\\w\\-_]+)+([\\w\\-\\.,@?^=%&:/~\\+#]*[\\w\\-\\@?^=%&/~\\+#])?";

        assertTrue("www.google.com".matches(regularExpression));
        assertTrue("www.google.co.uk".matches(regularExpression));
        assertTrue("http://www.google.com".matches(regularExpression));
        assertTrue("http://www.google.co.uk".matches(regularExpression));
        assertTrue("https://www.google.com".matches(regularExpression));
        assertTrue("https://www.google.co.uk".matches(regularExpression));
        assertTrue("google.com".matches(regularExpression));
        assertTrue("google.co.uk".matches(regularExpression));
        assertTrue("google.mu".matches(regularExpression));
        assertTrue("mes.intnet.mu".matches(regularExpression));
        assertTrue("cse.uom.ac.mu".matches(regularExpression));

        assertTrue("http://www.google.com/path".matches(regularExpression));
        assertTrue("http://subdomain.web-site.com/cgi-bin/perl.cgi?key1=value1&key2=value2e".matches(regularExpression));
        assertTrue("http://www.google.com/?queryparam=123".matches(regularExpression));
        assertTrue("http://www.google.com/path?queryparam=123".matches(regularExpression));

        assertFalse("www..dr.google".matches(regularExpression));

        assertFalse("www:google.com".matches(regularExpression));

        assertFalse("https://www@.google.com".matches(regularExpression));

        assertFalse("https://www.google.com\"".matches(regularExpression));
        assertFalse("https://www.google.com'".matches(regularExpression));

        assertFalse("http://www.google.com/path'".matches(regularExpression));
        assertFalse("http://subdomain.web-site.com/cgi-bin/perl.cgi?key1=value1&key2=value2e'".matches(regularExpression));
        assertFalse("http://www.google.com/?queryparam=123'".matches(regularExpression));
        assertFalse("http://www.google.com/path?queryparam=12'3".matches(regularExpression));

    }

如果你真的在搜索终极匹配，你可能会在“一个好的Url正则表达式?”

但是，一个真正匹配所有可能域并允许rfc允许的任何内容的正则表达式是可怕的长且不可读的，相信我;-)

我写了一个很棒的版本，你可以运行

它匹配以下url(这对我来说已经足够好了)

public static void main(args) {
    String url = "go to http://www.m.abut.ly/abc its awesome"
    url = url.replaceAll(/https?:\/\/w{0,3}\w*?\.(\w*?\.)?\w{2,3}\S*|www\.(\w*?\.)?\w*?\.\w{2,3}\S*|(\w*?\.)?\w*?\.\w{2,3}[\/\?]\S*/ , { it ->
        "woof${it}woof"
    })
    println url 
}

http://google.com
http://google.com/help.php
http://google.com/help.php?a=5

http://www.google.com
http://www.google.com/help.php
http://www.google.com?a=5

google.com?a=5
google.com/help.php
google.com/help.php?a=5

http://www.m.google.com/help.php?a=5 (and all its permutations)
www.m.google.com/help.php?a=5 (and all its permutations)
m.google.com/help.php?a=5 (and all its permutations)

对于任何不以http或www开头的url，重要的是它们必须包含/或?

我打赌这可以稍作调整，但它的工作非常好，因为它是如此简短和紧凑……因为你可以把它分成三份:

找到任何以http开头的内容:

https?:\/\/w{0,3}\w*?\.\w{2,3}\S*

找到任何以www开头的东西:

www\.\w*?\.\w{2,3}\S*

或者找到任何必须有一个文本，然后一个点，然后至少两个字母，然后一个?或/:

\w*?\.\w{2,3}[\/\?]\S*

这个怎么样:

^(https?:\/\/(?:www\.|(?!www))[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9]\.[^\s]{2,}|www\.[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9]\.[^\s]{2,}|https?:\/\/(?:www\.|(?!www))[a-zA-Z0-9]\.[^\s]{2,}|www\.[a-zA-Z0-9]\.[^\s]{2,})$

这些是测试用例:

你可以在这里试试:https://regex101.com/r/mS9gD7/41

下面的正则表达式适用于我:

(http(s)?:\/\/.)?(ftp(s)?:\/\/.)?(www\.)?[-a-zA-Z0-9@:%._\+~#=]{0,256}\.[a-z] 
{2,6}\b([-a-zA-Z0-9@:%_\+.~#?&//=]*)

匹配:

https://google.com t.me https://t.me ftp://google.com http://sm.tj http://bro.tj t.me/rshss https:google.com www.cool.com.au http://www.cool.com.au http://www.cool.com.au/ersdfs http://www.cool.com.au/ersdfs?dfd=dfgd@s=1 http://www.cool.com:81/index.html