我发现下面的正则表达式的url，测试成功与500+ url:

/\b(?:(?:https?|ftp):\/\/)(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)(?:\.(?:[a-z\x{00a1}-\x{ffff}0-9]+-?)*[a-z\x{00a1}-\x{ffff}0-9]+)*(?:\.(?:[a-z\x{00a1}-\x{ffff}]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?\b/gi

我知道这看起来很丑，但好处是它很有效。：）

regex101上581个随机url的解释和演示。

来源:在搜索完美的URL验证正则表达式

Javascript现在有一个名为new URL()的URL构造函数。它允许您完全跳过REGEX。

/** * * The URL() constructor returns a newly created URL object representing * the URL defined by the parameters. * * https://developer.mozilla.org/en-US/docs/Web/API/URL/URL * */ let requestUrl = new URL('https://username:password@developer.mozilla.org:8080/en-US/docs/search.html?par1=abc&par2=123&par3=true#Recent'); let urlParts = { origin: requestUrl.origin, href: requestUrl.href, protocol: requestUrl.protocol, username: requestUrl.username, password: requestUrl.password, host: requestUrl.host, hostname: requestUrl.hostname, port: requestUrl.port, pathname: requestUrl.pathname, search: requestUrl.search, searchParams: { par1: String(requestUrl.searchParams.get('par1')), par2: Number(requestUrl.searchParams.get('par2')), par3: Boolean(requestUrl.searchParams.get('par3')), }, hash: requestUrl.hash }; console.log(urlParts);

非验证uri引用解析器

为了便于参考，这里是IETF规范:(TXT | HTML)。特别地，附录b用正则表达式解析URI引用演示了如何解析有效的正则表达式。这被描述为，

这是一个非验证URI引用解析器的例子，它将接受任何给定的字符串并提取URI组件。

下面是它们提供的正则表达式:

 ^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?

正如其他人所说，最好将此留给您已经在使用的库/框架。

下面的正则表达式适用于我:

(http(s)?:\/\/.)?(ftp(s)?:\/\/.)?(www\.)?[-a-zA-Z0-9@:%._\+~#=]{0,256}\.[a-z] 
{2,6}\b([-a-zA-Z0-9@:%_\+.~#?&//=]*)

匹配:

https://google.com t.me https://t.me ftp://google.com http://sm.tj http://bro.tj t.me/rshss https:google.com www.cool.com.au http://www.cool.com.au http://www.cool.com.au/ersdfs http://www.cool.com.au/ersdfs?dfd=dfgd@s=1 http://www.cool.com:81/index.html

/^(http|HTTP)+(s|S)?:\/\/[\w.-]+(?:\.[\w\.-]+)+[\w\-\._\$\(\)/]+$/g

使用测试检查演示:

https://regexr.com/5cedu

下面是针对这种情况的最佳和最匹配的正则表达式

^(?:http(?:s)?:\/\/)?(?:www\.)?(?:[\w-]*)\.\w{2,}$