如何检查给定的字符串是否是有效的URL地址?
我对正则表达式的知识是基本的,不允许我从我已经在网上看到的数百个正则表达式中进行选择。
如何检查给定的字符串是否是有效的URL地址?
我对正则表达式的知识是基本的,不允许我从我已经在网上看到的数百个正则表达式中进行选择。
当前回答
就我所知,这个表达对我有好处-
(https?:\/\/(?:www\.|(?!www))[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9]\.[^\s]{2,}|https?:\/\/(?:www\.|(?!www))[a-zA-Z0-9]\.[^\s]{2,}|www\.[a-zA-Z0-9]\.[^\s]{2,})
工作示例,
function RegExForUrlMatch() { var expression = /(https?:\/\/(?:www\.|(?!www))[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9]\.[^\s]{2,}|https?:\/\/(?:www\.|(?!www))[a-zA-Z0-9]\.[^\s]{2,}|www\.[a-zA-Z0-9]\.[^\s]{2,})/g; var regex = new RegExp(expression); var t = document.getElementById("url").value; if (t.match(regex)) { document.getElementById("demo").innerHTML = "Successful match"; } else { document.getElementById("demo").innerHTML = "No match"; } } <input type="text" id="url" placeholder="url" onkeyup="RegExForUrlMatch()"> <p id="demo">Please enter a URL to test</p>
其他回答
Regardless the broad question asked, I post this for anyone in the future who is looking for something simple... as I think validating a URL has no perfect regular expression that fit all needs, it depends on your requirements, i.e: in my case, I just needed to verify if a URL is in the form of domain.extension and I wanted to allow the www or any other subdomain like blog.domain.extension I don't care about http(s) as in my app I have a field which says "enter the URL" so it's obvious what that entered string is.
这是regEx:
/^(www\.|[a-zA-Z0-9](.*[a-zA-Z0-9])?\.)?((?!www)[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9])\.[a-z]{2,5}(:[0-9]{1,5})?$/i
这个regExp中的第一个块是:
(www \ | [a-zA-Z0-9] (. * [a-zA-Z0-9]) ? \。)?——>我们开始检查URL是否以www开头。[a-zA-Z0-9]或[a-zA-Z0-9] (. *) ?这意味着一个字母或数字+ (anyCharacter(0或多次)+另一个字母或数字),然后是一个点
注意(.*[a-zA-Z0-9])?\.)?我们翻译由(anyCharacter(0或多次)+另一个字母或数字) 是可选的(可以是或不是)这就是为什么我们将它分组在括号之间,后面跟着问号?
到目前为止我们讨论的整个块也放在括号之间,后面跟着?这意味着WWW或任何其他词(表示子域)都是可选的。
第二部分是:((? ! www) [a-zA-Z0-9] [a-zA-Z0-9 -] + [a-zA-Z0-9]) \。——>表示“域”部分,它可以是任何单词(www除外),以字母或数字开头+任何其他字母(包括破折号“-”)重复一次或多次,以任何字母或数字结尾,后面跟一个点。
最后一部分是[a-z]{2,}——>,它代表“扩展名”,它可以是任何字母重复2次或更多次,所以它可以是com, net, org, art基本上任何扩展名
黑(http / \ /处事之道会(s) ?):地球,随便(www。)? a-zA-Z0-9 @:%._\+~#=]{ 地球,随便2,256出于美观。黑a-z铝可不,2、6出于美观\ b(黑-a-zA-Z0-9 @:%_\+.~#?&//=]*)
非验证uri引用解析器
为了便于参考,这里是IETF规范:(TXT | HTML)。特别地,附录b用正则表达式解析URI引用演示了如何解析有效的正则表达式。这被描述为,
这是一个非验证URI引用解析器的例子,它将接受任何给定的字符串并提取URI组件。
下面是它们提供的正则表达式:
^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?
正如其他人所说,最好将此留给您已经在使用的库/框架。
我试着制定我的url版本。我的需求是在一个字符串中捕获实例,其中可能的url可以是cse.uom.ac.mu -注意它的前面没有http或www
String regularExpression = "((((ht{2}ps?://)?)((w{3}\\.)?))?)[^.&&[a-zA-Z0-9]][a-zA-Z0-9.-]+[^.&&[a-zA-Z0-9]](\\.[a-zA-Z]{2,3})";
assertTrue("www.google.com".matches(regularExpression));
assertTrue("www.google.co.uk".matches(regularExpression));
assertTrue("http://www.google.com".matches(regularExpression));
assertTrue("http://www.google.co.uk".matches(regularExpression));
assertTrue("https://www.google.com".matches(regularExpression));
assertTrue("https://www.google.co.uk".matches(regularExpression));
assertTrue("google.com".matches(regularExpression));
assertTrue("google.co.uk".matches(regularExpression));
assertTrue("google.mu".matches(regularExpression));
assertTrue("mes.intnet.mu".matches(regularExpression));
assertTrue("cse.uom.ac.mu".matches(regularExpression));
//cannot contain 2 '.' after www
assertFalse("www..dr.google".matches(regularExpression));
//cannot contain 2 '.' just before com
assertFalse("www.dr.google..com".matches(regularExpression));
// to test case where url www must be followed with a '.'
assertFalse("www:google.com".matches(regularExpression));
// to test case where url www must be followed with a '.'
//assertFalse("http://wwwe.google.com".matches(regularExpression));
// to test case where www must be preceded with a '.'
assertFalse("https://www@.google.com".matches(regularExpression));
关于眼睑问题,他的回答是“这是基于我对URI规范的阅读。”谢谢眼睑,你的是我寻求的完美的解决方案,因为它是基于URI规范!出色的工作。:)
我不得不做了两个修改。第一个在PHP (v5.2.10)中使用preg_match()函数使regexp正确匹配IP地址url的方法。
我不得不在管道周围的“IP Address”上方的行中添加一组括号:
)|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}(?#
不知道为什么。
我还将顶级域名的最小长度从3个字母减少到2个字母,以支持.co。英国和类似国家。
最后的代码:
/^(https?|ftp):\/\/(?# protocol
)(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+(?# username
)(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?(?# password
)@)?(?# auth requires @
)((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*(?# domain segments AND
)[a-z][a-z0-9-]*[a-z0-9](?# top level domain OR
)|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}(?#
)(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])(?# IP address
))(:\d+)?(?# port
))(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*(?# path
)(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)(?# query string
)?)?)?(?# path and query string optional
)(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?(?# fragment
)$/i
这个修改后的版本没有根据URI规范进行检查,所以我不能保证它的合规性,它被修改为处理本地网络环境中的URL和两位tld以及其他类型的Web URL,并在我使用的PHP设置中更好地工作。
作为PHP代码:
define('URL_FORMAT',
'/^(https?):\/\/'. // protocol
'(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+'. // username
'(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?'. // password
'@)?(?#'. // auth requires @
')((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*'. // domain segments AND
'[a-z][a-z0-9-]*[a-z0-9]'. // top level domain OR
'|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}'.
'(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])'. // IP address
')(:\d+)?'. // port
')(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*'. // path
'(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)'. // query string
'?)?)?'. // path and query string optional
'(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?'. // fragment
'$/i');
下面是一个PHP测试程序,它使用正则表达式验证各种url:
<?php
define('URL_FORMAT',
'/^(https?):\/\/'. // protocol
'(([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+'. // username
'(:([a-z0-9$_\.\+!\*\'\(\),;\?&=-]|%[0-9a-f]{2})+)?'. // password
'@)?(?#'. // auth requires @
')((([a-z0-9]\.|[a-z0-9][a-z0-9-]*[a-z0-9]\.)*'. // domain segments AND
'[a-z][a-z0-9-]*[a-z0-9]'. // top level domain OR
'|((\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])\.){3}'.
'(\d|[1-9]\d|1\d{2}|2[0-4][0-9]|25[0-5])'. // IP address
')(:\d+)?'. // port
')(((\/+([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)*'. // path
'(\?([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)'. // query string
'?)?)?'. // path and query string optional
'(#([a-z0-9$_\.\+!\*\'\(\),;:@&=-]|%[0-9a-f]{2})*)?'. // fragment
'$/i');
/**
* Verify the syntax of the given URL.
*
* @access public
* @param $url The URL to verify.
* @return boolean
*/
function is_valid_url($url) {
if (str_starts_with(strtolower($url), 'http://localhost')) {
return true;
}
return preg_match(URL_FORMAT, $url);
}
/**
* String starts with something
*
* This function will return true only if input string starts with
* niddle
*
* @param string $string Input string
* @param string $niddle Needle string
* @return boolean
*/
function str_starts_with($string, $niddle) {
return substr($string, 0, strlen($niddle)) == $niddle;
}
/**
* Test a URL for validity and count results.
* @param url url
* @param expected expected result (true or false)
*/
$numtests = 0;
$passed = 0;
function test_url($url, $expected) {
global $numtests, $passed;
$numtests++;
$valid = is_valid_url($url);
echo "URL Valid?: " . ($valid?"yes":"no") . " for URL: $url. Expected: ".($expected?"yes":"no").". ";
if($valid == $expected) {
echo "PASS\n"; $passed++;
} else {
echo "FAIL\n";
}
}
echo "URL Tests:\n\n";
test_url("http://localserver/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", true);
test_url("http://www.google.com", true);
test_url("http://www.google.co.uk/projects/my%20folder/test.php", true);
test_url("https://myserver.localdomain", true);
test_url("http://192.168.1.120/projects/index.php", true);
test_url("http://192.168.1.1/projects/index.php", true);
test_url("http://projectpier-server.localdomain/projects/public/assets/javascript/widgets/UserBoxMenu/widget.css", true);
test_url("https://2.4.168.19/project-pier?c=test&a=b", true);
test_url("https://localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", true);
test_url("http://user:password@localhost/a/b/c/test.php?c=controller&arg1=20&arg2=20", true);
echo "\n$passed out of $numtests tests passed.\n\n";
?>
再次感谢regex的虚实!