谁能告诉我一些代码,以确定一个数字在JavaScript是偶数还是奇数?


当前回答

刚刚在adobedreamweaver中执行了这个,它工作得很完美。 i using if (isNaN(mynmb))

检查给定的值是否为数字, 我还使用Math.abs(mynmb%2)将负数转换为正数并计算

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>

</head>
<body bgcolor = "#FFFFCC">
    <h3 align ="center"> ODD OR EVEN </h3><table cellspacing = "2" cellpadding = "5" bgcolor="palegreen">
        <form name = formtwo>
            <td align = "center">
                <center><BR />Enter a number: 
                    <input type=text id="enter" name=enter maxlength="10" />
                    <input type=button name = b3 value = "Click Here" onClick = compute() />
                      <b>is<b> 
                <input type=text id="outtxt" name=output size="5" value="" disabled /> </b></b></center><b><b>
                <BR /><BR />
            </b></b></td></form>
        </table>

    <script type='text/javascript'>

        function compute()
        {
          var enter = document.getElementById("enter");
          var outtxt = document.getElementById("outtxt");

          var mynmb = enter.value;
          if (isNaN(mynmb)) 
          { 
            outtxt.value = "error !!!"; 
            alert( 'please enter a valid number');
            enter.focus();
            return;
          }
          else 
          { 
             if ( mynmb%2 == 0 ) { outtxt.value = "Even"; }  
             if ( Math.abs(mynmb%2) == 1 ) { outtxt.value = "Odd"; }
          }
        }

    </script>
</body>
</html>

其他回答

像许多语言一样,Javascript有一个模运算符%,用于查找除法的余数。如果数除2后无余数,则该数为偶数:

// this expression is true if "number" is even, false otherwise
(number % 2 == 0)

同理,若2除后余数为1,则该数为奇数:

// this expression is true if "number" is odd, false otherwise
(number % 2 == 1)

这是测试偶数的一个非常常见的习惯用法。

这适用于数组:

function evenOrOdd(numbers) {
  const evenNumbers = [];
  const oddNumbers = [];
  numbers.forEach(number => {
    if (number % 2 === 0) {
      evenNumbers.push(number);
    } else {
      oddNumbers.push(number);
    }
  });

  console.log("Even: " + evenNumbers + "\nOdd: " + oddNumbers);
}

evenOrOdd([1, 4, 9, 21, 41, 92]);

这应该注销: 4, 92 1、9、21日,41岁

对于一个数字:

function evenOrOdd(number) {
  if (number % 2 === 0) {
    return "even";
  }

  return "odd";
}

console.log(evenOrOdd(4));

这甚至应该输出到控制台

ES6中的一行代码,因为它很干净。

const isEven = (num) => num % 2 == 0;

一个方法来知道数字是否为奇数

Let numbers = [11,20,2,5,17,10]; 让n = numbers.filter((ele) => ele % 2 != 0); console.log (n);

另一个使用filter()方法的例子:

let even = arr.filter(val => {
  return val % 2 === 0;
});
// even = [2,4,6]