我正在寻找一种方法来确定用户是否有,通过设置,启用或禁用他们的推送通知我的应用程序。
当前回答
re:
这是正确的
if (types & UIRemoteNotificationTypeAlert)
但是下面也是正确的!(因为UIRemoteNotificationTypeNone是0)
if (types == UIRemoteNotificationTypeNone)
参见以下内容
NSLog(@"log:%d",0 & 0); ///false
NSLog(@"log:%d",1 & 1); ///true
NSLog(@"log:%d",1<<1 & 1<<1); ///true
NSLog(@"log:%d",1<<2 & 1<<2); ///true
NSLog(@"log:%d",(0 & 0) && YES); ///false
NSLog(@"log:%d",(1 & 1) && YES); ///true
NSLog(@"log:%d",(1<<1 & 1<<1) && YES); ///true
NSLog(@"log:%d",(1<<2 & 1<<2) && YES); ///true
其他回答
iOS8+ (OBJECTIVE C)
#import <UserNotifications/UserNotifications.h>
[[UNUserNotificationCenter currentNotificationCenter]getNotificationSettingsWithCompletionHandler:^(UNNotificationSettings * _Nonnull settings) {
switch (settings.authorizationStatus) {
case UNAuthorizationStatusNotDetermined:{
break;
}
case UNAuthorizationStatusDenied:{
break;
}
case UNAuthorizationStatusAuthorized:{
break;
}
default:
break;
}
}];
在最新版本的iOS中,这种方法已被弃用。支持iOS 7和iOS 8使用:
UIApplication *application = [UIApplication sharedApplication];
BOOL enabled;
// Try to use the newer isRegisteredForRemoteNotifications otherwise use the enabledRemoteNotificationTypes.
if ([application respondsToSelector:@selector(isRegisteredForRemoteNotifications)])
{
enabled = [application isRegisteredForRemoteNotifications];
}
else
{
UIRemoteNotificationType types = [application enabledRemoteNotificationTypes];
enabled = types & UIRemoteNotificationTypeAlert;
}
为了完成这个答案,它可以这样工作……
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
switch (types) {
case UIRemoteNotificationTypeAlert:
case UIRemoteNotificationTypeBadge:
// For enabled code
break;
case UIRemoteNotificationTypeSound:
case UIRemoteNotificationTypeNone:
default:
// For disabled code
break;
}
编辑:这是不对的。因为这些是位智慧的东西,它不会与开关工作,所以我结束使用这个:
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
UIRemoteNotificationType typesset = (UIRemoteNotificationTypeAlert | UIRemoteNotificationTypeBadge);
if((types & typesset) == typesset)
{
CeldaSwitch.chkSwitch.on = true;
}
else
{
CeldaSwitch.chkSwitch.on = false;
}
re:
这是正确的
if (types & UIRemoteNotificationTypeAlert)
但是下面也是正确的!(因为UIRemoteNotificationTypeNone是0)
if (types == UIRemoteNotificationTypeNone)
参见以下内容
NSLog(@"log:%d",0 & 0); ///false
NSLog(@"log:%d",1 & 1); ///true
NSLog(@"log:%d",1<<1 & 1<<1); ///true
NSLog(@"log:%d",1<<2 & 1<<2); ///true
NSLog(@"log:%d",(0 & 0) && YES); ///false
NSLog(@"log:%d",(1 & 1) && YES); ///true
NSLog(@"log:%d",(1<<1 & 1<<1) && YES); ///true
NSLog(@"log:%d",(1<<2 & 1<<2) && YES); ///true
在尝试同时支持iOS8和更低版本时,我并没有像Kevin建议的那样使用isregisteredforremotenotifations。相反,我使用了currentUserNotificationSettings,它在我的测试中工作得很好。
+ (BOOL)notificationServicesEnabled {
BOOL isEnabled = NO;
if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]){
UIUserNotificationSettings *notificationSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];
if (!notificationSettings || (notificationSettings.types == UIUserNotificationTypeNone)) {
isEnabled = NO;
} else {
isEnabled = YES;
}
} else {
UIRemoteNotificationType types = [[UIApplication sharedApplication] enabledRemoteNotificationTypes];
if (types & UIRemoteNotificationTypeAlert) {
isEnabled = YES;
} else{
isEnabled = NO;
}
}
return isEnabled;
}
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