那么递归呢:

private static string ReturnSize(double size, string sizeLabel)
{
  if (size > 1024)
  {
    if (sizeLabel.Length == 0)
      return ReturnSize(size / 1024, "KB");
    else if (sizeLabel == "KB")
      return ReturnSize(size / 1024, "MB");
    else if (sizeLabel == "MB")
      return ReturnSize(size / 1024, "GB");
    else if (sizeLabel == "GB")
      return ReturnSize(size / 1024, "TB");
    else
      return ReturnSize(size / 1024, "PB");
  }
  else
  {
    if (sizeLabel.Length > 0)
      return string.Concat(size.ToString("0.00"), sizeLabel);
    else
      return string.Concat(size.ToString("0.00"), "Bytes");
  }
}

然后你称之为:

return ReturnSize(size, string.Empty);

下面是一个自动确定单位的简明答案。

public static string ToBytesCount(this long bytes)
{
    int unit = 1024;
    string unitStr = "B";
    if (bytes < unit)
    {
        return string.Format("{0} {1}", bytes, unitStr);
    }
    int exp = (int)(Math.Log(bytes) / Math.Log(unit));
    return string.Format("{0:##.##} {1}{2}", bytes / Math.Pow(unit, exp), "KMGTPEZY"[exp - 1], unitStr);
}

“b”代表bit，“b”代表Byte，“KMGTPEZY”分别代表kilo, mega, giga, tera, peta, exa, zetta和yotta

可以将ISO/IEC80000纳入考虑范围:

public static string ToBytesCount(this long bytes, bool isISO = true)
{
    int unit = isISO ? 1024 : 1000;
    string unitStr = "B";
    if (bytes < unit)
    {
        return string.Format("{0} {1}", bytes, unitStr);
    }
    int exp = (int)(Math.Log(bytes) / Math.Log(unit));
    return string.Format("{0:##.##} {1}{2}{3}", bytes / Math.Pow(unit, exp), "KMGTPEZY"[exp - 1], isISO ? "i" : "", unitStr);
}

int size = new FileInfo( filePath ).Length / 1024;
string humanKBSize = string.Format( "{0} KB", size );
string humanMBSize = string.Format( "{0} MB", size / 1024 );
string humanGBSize = string.Format( "{0} GB", size / 1024 / 1024 );

我猜你要找的是“1.4 MB”而不是“1468006字节”?

我不认为在。net中有内置的方法来做到这一点。你只需要找出哪个单元是合适的，然后格式化它。

编辑:这里有一些示例代码来做到这一点:

http://www.codeproject.com/KB/cpp/formatsize.aspx

比如@NET3的解决方案。使用shift而不是除法来测试字节的范围，因为除法占用更多的CPU成本。

private static readonly string[] UNITS = new string[] { "B", "KB", "MB", "GB", "TB", "PB", "EB" };

public static string FormatSize(ulong bytes)
{
    int c = 0;
    for (c = 0; c < UNITS.Length; c++)
    {
        ulong m = (ulong)1 << ((c + 1) * 10);
        if (bytes < m)
            break;
    }

    double n = bytes / (double)((ulong)1 << (c * 10));
    return string.Format("{0:0.##} {1}", n, UNITS[c]);
}

那么递归呢:

private static string ReturnSize(double size, string sizeLabel)
{
  if (size > 1024)
  {
    if (sizeLabel.Length == 0)
      return ReturnSize(size / 1024, "KB");
    else if (sizeLabel == "KB")
      return ReturnSize(size / 1024, "MB");
    else if (sizeLabel == "MB")
      return ReturnSize(size / 1024, "GB");
    else if (sizeLabel == "GB")
      return ReturnSize(size / 1024, "TB");
    else
      return ReturnSize(size / 1024, "PB");
  }
  else
  {
    if (sizeLabel.Length > 0)
      return string.Concat(size.ToString("0.00"), sizeLabel);
    else
      return string.Concat(size.ToString("0.00"), "Bytes");
  }
}

然后你称之为:

return ReturnSize(size, string.Empty);