那么递归呢:

private static string ReturnSize(double size, string sizeLabel)
{
  if (size > 1024)
  {
    if (sizeLabel.Length == 0)
      return ReturnSize(size / 1024, "KB");
    else if (sizeLabel == "KB")
      return ReturnSize(size / 1024, "MB");
    else if (sizeLabel == "MB")
      return ReturnSize(size / 1024, "GB");
    else if (sizeLabel == "GB")
      return ReturnSize(size / 1024, "TB");
    else
      return ReturnSize(size / 1024, "PB");
  }
  else
  {
    if (sizeLabel.Length > 0)
      return string.Concat(size.ToString("0.00"), sizeLabel);
    else
      return string.Concat(size.ToString("0.00"), "Bytes");
  }
}

然后你称之为:

return ReturnSize(size, string.Empty);

1-liner(加上前缀常量)

const String prefixes = " KMGTPEY";
/// <summary> Returns the human-readable file size for an arbitrary, 64-bit file size. </summary>
public static String HumanSize(UInt64 bytes)
    => Enumerable
    .Range(0, prefixes.Length)
    .Where(i => bytes < 1024U<<(i*10))
    .Select(i => $"{(bytes>>(10*i-10))/1024:0.###} {prefixes[i]}B")
    .First();

或者，如果你想减少LINQ对象的分配，使用相同的for循环变量:

/// <summary>
/// Returns the human-readable file size for an arbitrary, 64-bit file size.
/// </summary>
public static String HumanSize(UInt64 bytes)
{
    const String prefixes = " KMGTPEY";
    for (var i = 0; i < prefixes.Length; i++)
        if (bytes < 1024U<<(i*10))
            return $"{(bytes>>(10*i-10))/1024:0.###} {prefixes[i]}B";

    throw new ArgumentOutOfRangeException(nameof(bytes));
}

比如@NET3的解决方案。使用shift而不是除法来测试字节的范围，因为除法占用更多的CPU成本。

private static readonly string[] UNITS = new string[] { "B", "KB", "MB", "GB", "TB", "PB", "EB" };

public static string FormatSize(ulong bytes)
{
    int c = 0;
    for (c = 0; c < UNITS.Length; c++)
    {
        ulong m = (ulong)1 << ((c + 1) * 10);
        if (bytes < m)
            break;
    }

    double n = bytes / (double)((ulong)1 << (c * 10));
    return string.Format("{0:0.##} {1}", n, UNITS[c]);
}

为了获得人类可读的字符串，就像用户在Windows环境中习惯的那样，你应该使用StrFormatByteSize():

using System.Runtime.InteropServices;

...

private long mFileSize;

[DllImport("Shlwapi.dll", CharSet = CharSet.Auto)]
public static extern int StrFormatByteSize(
    long fileSize,
    [MarshalAs(UnmanagedType.LPTStr)] StringBuilder buffer,
    int bufferSize);
    
public string HumanReadableFileSize
{
    get
    {
        var sb = new StringBuilder(20);
        StrFormatByteSize(mFileSize, sb, 20);
        return sb.ToString();
    }
}

我在这里找到了这个: http://csharphelper.com/blog/2014/07/format-file-sizes-in-kb-mb-gb-and-so-forth-in-c/

这可能不是最有效或最优化的方法，但如果您不熟悉对数数学，它更容易阅读，并且对于大多数情况来说应该足够快。

string[] sizes = { "B", "KB", "MB", "GB", "TB" };
double len = new FileInfo(filename).Length;
int order = 0;
while (len >= 1024 && order < sizes.Length - 1) {
    order++;
    len = len/1024;
}

// Adjust the format string to your preferences. For example "{0:0.#}{1}" would
// show a single decimal place, and no space.
string result = String.Format("{0:0.##} {1}", len, sizes[order]);

我猜你要找的是“1.4 MB”而不是“1468006字节”?

我不认为在。net中有内置的方法来做到这一点。你只需要找出哪个单元是合适的，然后格式化它。

编辑:这里有一些示例代码来做到这一点:

http://www.codeproject.com/KB/cpp/formatsize.aspx