我使用上面“创建自定义脚本”方法的变体解决了这个问题。是这样的:

FROM hairyhenderson/figlet
ENV GREETING="Hello"
RUN printf '#!/bin/sh\nfiglet -W \${GREETING} \$@\n' > /runme && chmod +x /runme
ENTRYPOINT ["/runme"]
CMD ["World"]

像

docker container run -it --rm -e GREETING="G'Day" dockerfornovices/figlet-greeter Alec

我使用上面“创建自定义脚本”方法的变体解决了这个问题。是这样的:

FROM hairyhenderson/figlet
ENV GREETING="Hello"
RUN printf '#!/bin/sh\nfiglet -W \${GREETING} \$@\n' > /runme && chmod +x /runme
ENTRYPOINT ["/runme"]
CMD ["World"]

像

docker container run -it --rm -e GREETING="G'Day" dockerfornovices/figlet-greeter Alec

在我的案例中，工作方式是这样的:(用于docker中的Spring引导应用程序)

ENTRYPOINT java -DidMachine=${IDMACHINE} -jar my-app-name

并在docker运行时传递参数

docker run --env IDMACHINE=Idmachine -p 8383:8383 my-app-name

You're using the exec form of ENTRYPOINT. Unlike the shell form, the exec form does not invoke a command shell. This means that normal shell processing does not happen. For example, ENTRYPOINT [ "echo", "$HOME" ] will not do variable substitution on $HOME. If you want shell processing then either use the shell form or execute a shell directly, for example: ENTRYPOINT [ "sh", "-c", "echo $HOME" ]. When using the exec form and executing a shell directly, as in the case for the shell form, it is the shell that is doing the environment variable expansion, not docker.(from Dockerfile reference)

在你的例子中，我会用壳层形式

ENTRYPOINT ./greeting --message "Hello, $ADDRESSEE\!"

以下是对我有效的方法:

ENTRYPOINT [ "/bin/bash", "-c", "source ~/.bashrc && ./entrypoint.sh ${@}", "--" ]

现在您可以向docker run命令提供任何参数，同时仍然可以读取所有环境变量。

我试图用建议的答案来解决问题，但仍然遇到了一些问题……

这是我问题的解决方案:

ARG APP_EXE="AppName.exe"
ENV _EXE=${APP_EXE}

# Build a shell script because the ENTRYPOINT command doesn't like using ENV
RUN echo "#!/bin/bash \n mono ${_EXE}" > ./entrypoint.sh
RUN chmod +x ./entrypoint.sh

# Run the generated shell script.
ENTRYPOINT ["./entrypoint.sh"]

特别针对你的问题:

RUN echo "#!/bin/bash \n ./greeting --message ${ADDRESSEE}" > ./entrypoint.sh
RUN chmod +x ./entrypoint.sh
ENTRYPOINT ["./entrypoint.sh"]