我在JavaScript中有一个对象:

{
    abc: '...',
    bca: '...',
    zzz: '...',
    xxx: '...',
    ccc: '...',
    // ...
}

我想用一个for循环来获取它的属性。我想要迭代它的部分(不是所有的对象属性一次)。

对于一个简单的数组,我可以用一个标准的for循环来做:

for (i = 0; i < 100; i++) { ... } // first part
for (i = 100; i < 300; i++) { ... } // second
for (i = 300; i < arr.length; i++) { ... } // last

但是如何对对象进行处理呢?


当前回答

<script type="text/javascript">
// method 1
var images = {};
images['name'] = {};
images['family'] = {};
images[1] = {};
images['name'][5] = "Mehdi";
images['family'][8] = "Mohammadpour";
images['family']['ok'] = 123456;
images[1][22] = 2602;
images[1][22] = 2602;
images[1][22] = 2602;
images[1][22] = 2602;
images[1][23] = 2602;

for (const [key1, value1] of Object.entries(images)){
    for (const [key2, value2] of Object.entries(value1)){
        console.log(`${key1} => ${key2}: ${value2}`);
    }
}


console.log("=============================");

// method 2
var arr = [];
for(var x = 0; x < 5; x++){
     arr[x] = [];    
     for(var y = 0; y < 5; y++){ 
         arr[x][y] = x*y;    
     }    
 }

for(var i = 0; i < arr.length; i++) {
    var cube = arr[i];
    for(var j = 0; j < cube.length; j++) {
        console.log("cube[" + i + "][" + j + "] = " + cube[j]);
    }
}

</script>

其他回答

使用对象。你这样做。

 // array like object with random key ordering
 const anObj = { 100: 'a', 2: 'b', 7: 'c' };
 console.log(Object.entries(anObj)); // [ ['2', 'b'],['7', 'c'],['100', 'a'] ]

object .entries()方法返回给定对象自身可枚举属性[key, value]的数组。

你可以遍历对象每个对象都有键和值,得到这样的东西。

const anObj = { 100: 'a', 2: 'b', 7: 'c' };
Object.entries(anObj).map(obj => {
   const key   = obj[0];
   const value = obj[1];

   // do whatever you want with those values.
});

或者像这样

// Or, using array extras
Object.entries(obj).forEach(([key, value]) => {
  console.log(`${key} ${value}`); // "a 5", "b 7", "c 9"
});

参考MDN文档中的对象条目

下面是另一个针对现代浏览器的迭代解决方案:

Object.keys(obj)
  .filter((k, i) => i >= 100 && i < 300)
  .forEach(k => console.log(obj[k]));

或不带过滤功能:

Object.keys(obj).forEach((k, i) => {
    if (i >= 100 && i < 300) {
        console.log(obj[k]);
    }
});

但是你必须考虑到JavaScript对象中的属性是没有排序的,也就是说没有顺序。

这是一个手工制作的解决方案:

function iterationForObject() {
    let base = 0,
        Keys= Object.keys(this);
    return {
        next: () => {
            return {
                value: {
                    "key": Keys[base],
                    "value": this[Keys[base]]
                },
                done: !(base++ < Keys.length)
            };
        }
    };
}
Object.prototype[Symbol.iterator] = iterationForObject;

然后你可以循环任何对象:

for ( let keyAndValuePair of (Object Here) ) {
    console.log(`${keyAndValuePair.key} => ${keyAndValuePair.value}`);
}
<script type="text/javascript">
// method 1
var images = {};
images['name'] = {};
images['family'] = {};
images[1] = {};
images['name'][5] = "Mehdi";
images['family'][8] = "Mohammadpour";
images['family']['ok'] = 123456;
images[1][22] = 2602;
images[1][22] = 2602;
images[1][22] = 2602;
images[1][22] = 2602;
images[1][23] = 2602;

for (const [key1, value1] of Object.entries(images)){
    for (const [key2, value2] of Object.entries(value1)){
        console.log(`${key1} => ${key2}: ${value2}`);
    }
}


console.log("=============================");

// method 2
var arr = [];
for(var x = 0; x < 5; x++){
     arr[x] = [];    
     for(var y = 0; y < 5; y++){ 
         arr[x][y] = x*y;    
     }    
 }

for(var i = 0; i < arr.length; i++) {
    var cube = arr[i];
    for(var j = 0; j < cube.length; j++) {
        console.log("cube[" + i + "][" + j + "] = " + cube[j]);
    }
}

</script>

如果在迭代时需要键和值,可以使用for…使用Object.entries循环。

const myObj = {a: 1, b: 2}

for (let [key, value] of Object.entries(myObj)) {
    console.log(`key=${key} value=${value}`)
}

// output: 
// key=a value=1
// key=b value=2