从iOS 15开始，SwiftUI内置支持Markdown标记语言，因此Markdown中的文本:

Text("You can [click this link](https://www.example.com) to visit the website.")

或者作为一个使用SwiftUI的最简单的例子，你可以这样做:

        HStack() {
            Text("Open the")
                .foregroundColor(.black)
            Link(destination: URL(string: "https://www.example.com/TOS.html")!) {
                Text("link")
                    .foregroundColor(.blue)
                    .underline()
            }
            Text("in browser")
                .foregroundColor(.black)
        }

UITextView支持OS3.0中的数据检测器，而UILabel不支持。

如果你在UITextView上启用了数据检测器，并且你的文本包含url、电话号码等，它们将以链接的形式出现。

以下是基于@Luca Davanzo的回答，重写touchesBegan事件而不是轻触手势:

import UIKit

public protocol TapableLabelDelegate: NSObjectProtocol {
   func tapableLabel(_ label: TapableLabel, didTapUrl url: String, atRange range: NSRange)
}

public class TapableLabel: UILabel {

private var links: [String: NSRange] = [:]
private(set) var layoutManager = NSLayoutManager()
private(set) var textContainer = NSTextContainer(size: CGSize.zero)
private(set) var textStorage = NSTextStorage() {
    didSet {
        textStorage.addLayoutManager(layoutManager)
    }
}

public weak var delegate: TapableLabelDelegate?

public override var attributedText: NSAttributedString? {
    didSet {
        if let attributedText = attributedText {
            textStorage = NSTextStorage(attributedString: attributedText)
        } else {
            textStorage = NSTextStorage()
            links = [:]
        }
    }
}

public override var lineBreakMode: NSLineBreakMode {
    didSet {
        textContainer.lineBreakMode = lineBreakMode
    }
}

public override var numberOfLines: Int {
    didSet {
        textContainer.maximumNumberOfLines = numberOfLines
    }
}


public override init(frame: CGRect) {
    super.init(frame: frame)
    setup()
}

public required init?(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)
    setup()
}

public override func layoutSubviews() {
    super.layoutSubviews()
    textContainer.size = bounds.size
}


/// addLinks
///
/// - Parameters:
///   - text: text of link
///   - url: link url string
public func addLink(_ text: String, withURL url: String) {
    guard let theText = attributedText?.string as? NSString else {
        return
    }

    let range = theText.range(of: text)

    guard range.location !=  NSNotFound else {
        return
    }

    links[url] = range
}

private func setup() {
    isUserInteractionEnabled = true
    layoutManager.addTextContainer(textContainer)
    textContainer.lineFragmentPadding = 0
    textContainer.lineBreakMode = lineBreakMode
    textContainer.maximumNumberOfLines  = numberOfLines
}

public override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    guard let locationOfTouch = touches.first?.location(in: self) else {
        return
    }

    textContainer.size = bounds.size
    let indexOfCharacter = layoutManager.glyphIndex(for: locationOfTouch, in: textContainer)

    for (urlString, range) in links {
        if NSLocationInRange(indexOfCharacter, range), let url = URL(string: urlString) {
            delegate?.tapableLabel(self, didTapUrl: urlString, atRange: range)
        }
    }
}}

我强烈建议使用自动检测文本中的url并将其转换为链接的库。 试一试:

TTTAttributedLabel （pod） ZSWTappableLabel （under）.

两者都得到了麻省理工学院的许可。

就像在前面的回答中报告的那样，UITextView能够处理链接上的触摸。这可以通过将文本的其他部分作为链接来轻松扩展。AttributedTextView库是一个UITextView子类，它使得处理这些非常容易。更多信息请参见:https://github.com/evermeer/AttributedTextView

你可以让文本的任何部分像这样交互(其中textView1是一个UITextView IBOutlet):

textView1.attributer =
    "1. ".red
    .append("This is the first test. ").green
    .append("Click on ").black
    .append("evict.nl").makeInteract { _ in
        UIApplication.shared.open(URL(string: "http://evict.nl")!, options: [:], completionHandler: { completed in })
    }.underline
    .append(" for testing links. ").black
    .append("Next test").underline.makeInteract { _ in
        print("NEXT")
    }
    .all.font(UIFont(name: "SourceSansPro-Regular", size: 16))
    .setLinkColor(UIColor.purple) 

为了处理标签和提及，你可以使用这样的代码:

textView1.attributer = "@test: What #hashtags do we have in @evermeer #AtributedTextView library"
    .matchHashtags.underline
    .matchMentions
    .makeInteract { link in
        UIApplication.shared.open(URL(string: "https://twitter.com\(link.replacingOccurrences(of: "@", with: ""))")!, options: [:], completionHandler: { completed in })
    }

我遵循这个版本，

斯威夫特4:

import Foundation

class AELinkedClickableUILabel: UILabel {

    typealias YourCompletion = () -> Void

    var linkedRange: NSRange!
    var completion: YourCompletion?

    @objc func linkClicked(sender: UITapGestureRecognizer){

        if let completionBlock = completion {

            let textView = UITextView(frame: self.frame)
            textView.text = self.text
            textView.attributedText = self.attributedText
            let index = textView.layoutManager.characterIndex(for: sender.location(in: self),
                                                              in: textView.textContainer,
                                                              fractionOfDistanceBetweenInsertionPoints: nil)

            if linkedRange.lowerBound <= index && linkedRange.upperBound >= index {

                completionBlock()
            }
        }
    }

/**
 *  This method will be used to set an attributed text specifying the linked text with a
 *  handler when the link is clicked
 */
    public func setLinkedTextWithHandler(text:String, link: String, handler: @escaping ()->()) -> Bool {

        let attributextText = NSMutableAttributedString(string: text)
        let foundRange = attributextText.mutableString.range(of: link)

        if foundRange.location != NSNotFound {
            self.linkedRange = foundRange
            self.completion = handler
            attributextText.addAttribute(NSAttributedStringKey.link, value: text, range: foundRange)
            self.isUserInteractionEnabled = true
            self.addGestureRecognizer(UITapGestureRecognizer(target: self, action: #selector(linkClicked(sender:))))
            return true
        }
        return false
    }
}

电话的例子:

button.setLinkedTextWithHandler(text: "This website (stackoverflow.com) is awesome", link: "stackoverflow.com") 
{
    // show popup or open to link
}