我想知道在我的c++程序中某个函数在Linux上执行需要多少时间。之后,我想做一个速度比较。我看到了几个时间函数,但最终从boost。空间:

process_user_cpu_clock, captures user-CPU time spent by the current process

现在,我不清楚如果我使用上述函数,我会得到哪个CPU在该函数上花费的唯一时间吗?

其次,我找不到任何使用上述功能的例子。请问有谁能告诉我如何使用上面的功能?

p.s.:现在,我使用std::chrono::system_clock::now()以秒为单位获得时间,但这给了我不同的结果,因为不同的CPU负载每次。


当前回答

这是一个非常基本的定时器类,你可以根据自己的需要进行扩展。我想要一些直接的东西,可以在代码中干净地使用。你可以通过这个链接来修改代码:http://tpcg.io/nd47hFqr。

class local_timer {
    private:
        std::chrono::_V2::system_clock::time_point start_time;
        std::chrono::_V2::system_clock::time_point stop_time;
        std::chrono::_V2::system_clock::time_point stop_time_temp;
        std::chrono::microseconds most_recent_duration_usec_chrono;
        double most_recent_duration_sec;
    public:

        local_timer() {

        };

        ~local_timer() {

        };

        void start() {
            this->start_time = std::chrono::high_resolution_clock::now();
        };

        void stop() {
            this->stop_time = std::chrono::high_resolution_clock::now();
        };

        double get_time_now() {
            this->stop_time_temp = std::chrono::high_resolution_clock::now();
            this->most_recent_duration_usec_chrono = std::chrono::duration_cast<std::chrono::microseconds>(stop_time_temp-start_time);
            this->most_recent_duration_sec = (long double)most_recent_duration_usec_chrono.count()/1000000;
            return this->most_recent_duration_sec;
        };

        double get_duration() {
            this->most_recent_duration_usec_chrono = std::chrono::duration_cast<std::chrono::microseconds>(stop_time-start_time);
            this->most_recent_duration_sec = (long double)most_recent_duration_usec_chrono.count()/1000000;
            return this->most_recent_duration_sec;
        };


};

这个存在的用处

#include <iostream>
#include "timer.hpp" //if kept in an hpp file in the same folder, can also before your main function

int main() {
    //create two timers
    local_timer timer1 = local_timer();
    local_timer timer2 = local_timer();
    
    //set start time for timer1
    timer1.start();
    //wait 1 second
    while(timer1.get_time_now() < 1.0) {
    }
    //save time
    timer1.stop();
    //print time
    std::cout << timer1.get_duration() << " seconds, timer 1\n" << std::endl;

    timer2.start();
    for(long int i = 0; i < 100000000; i++) {
        //do something
        if(i%1000000 == 0) { 
            //return time since loop started
            std::cout << timer2.get_time_now() << " seconds, timer 2\n"<< std::endl;
        }
        
    }
    return 0;
}

其他回答

如果你想要安全的时间和代码行,你可以用一行宏来测量函数的执行时间:

a)实现如上所述的时间测量类(这是我的android实现):

class MeasureExecutionTime{
private:
    const std::chrono::steady_clock::time_point begin;
    const std::string caller;
public:
    MeasureExecutionTime(const std::string& caller):caller(caller),begin(std::chrono::steady_clock::now()){}
    ~MeasureExecutionTime(){
        const auto duration=std::chrono::steady_clock::now()-begin;
        LOGD("ExecutionTime")<<"For "<<caller<<" is "<<std::chrono::duration_cast<std::chrono::milliseconds>(duration).count()<<"ms";
    }
};

b)添加一个方便的宏,它使用当前函数名作为TAG(在这里使用宏很重要,否则__FUNCTION__将计算为MeasureExecutionTime而不是你想测量的函数

#ifndef MEASURE_FUNCTION_EXECUTION_TIME
#define MEASURE_FUNCTION_EXECUTION_TIME const MeasureExecutionTime measureExecutionTime(__FUNCTION__);
#endif

c)在你想要测量的函数的开头写你的宏。例子:

 void DecodeMJPEGtoANativeWindowBuffer(uvc_frame_t* frame_mjpeg,const ANativeWindow_Buffer& nativeWindowBuffer){
        MEASURE_FUNCTION_EXECUTION_TIME
        // Do some time-critical stuff 
}

这将导致以下输出:

ExecutionTime: For DecodeMJPEGtoANativeWindowBuffer is 54ms

请注意,这(和所有其他建议的解决方案一样)将测量函数被调用和返回之间的时间,而不一定是CPU执行函数的时间。但是,如果您不给调度程序任何更改,通过调用sleep()或类似方法来挂起正在运行的代码,则两者之间没有区别。

在c++ 11中,这是一个非常容易使用的方法。你必须使用std::chrono::high_resolution_clock from <chrono>头。

像这样使用它:

#include <chrono>

/* Only needed for the sake of this example. */
#include <iostream>
#include <thread>
    
void long_operation()
{
    /* Simulating a long, heavy operation. */

    using namespace std::chrono_literals;
    std::this_thread::sleep_for(150ms);
}

int main()
{
    using std::chrono::high_resolution_clock;
    using std::chrono::duration_cast;
    using std::chrono::duration;
    using std::chrono::milliseconds;

    auto t1 = high_resolution_clock::now();
    long_operation();
    auto t2 = high_resolution_clock::now();

    /* Getting number of milliseconds as an integer. */
    auto ms_int = duration_cast<milliseconds>(t2 - t1);

    /* Getting number of milliseconds as a double. */
    duration<double, std::milli> ms_double = t2 - t1;

    std::cout << ms_int.count() << "ms\n";
    std::cout << ms_double.count() << "ms\n";
    return 0;
}

这将度量函数long_operation的持续时间。

可能的输出:

150ms
150.068ms

工作示例:https://godbolt.org/z/oe5cMd

下面是一个函数,它将测量作为参数传递的任何函数的执行时间:

#include <chrono>
#include <utility>

typedef std::chrono::high_resolution_clock::time_point TimeVar;

#define duration(a) std::chrono::duration_cast<std::chrono::nanoseconds>(a).count()
#define timeNow() std::chrono::high_resolution_clock::now()

template<typename F, typename... Args>
double funcTime(F func, Args&&... args){
    TimeVar t1=timeNow();
    func(std::forward<Args>(args)...);
    return duration(timeNow()-t1);
}

使用示例:

#include <iostream>
#include <algorithm>

typedef std::string String;

//first test function doing something
int countCharInString(String s, char delim){
    int count=0;
    String::size_type pos = s.find_first_of(delim);
    while ((pos = s.find_first_of(delim, pos)) != String::npos){
        count++;pos++;
    }
    return count;
}

//second test function doing the same thing in different way
int countWithAlgorithm(String s, char delim){
    return std::count(s.begin(),s.end(),delim);
}


int main(){
    std::cout<<"norm: "<<funcTime(countCharInString,"precision=10",'=')<<"\n";
    std::cout<<"algo: "<<funcTime(countWithAlgorithm,"precision=10",'=');
    return 0;
}

输出:

norm: 15555
algo: 2976

因为没有一个提供的答案是非常准确的或可复制的结果,我决定添加一个链接到我的代码,具有亚纳秒的精度和科学统计。

Note that this will only work to measure code that takes a (very) short time to run (aka, a few clock cycles to a few thousand): if they run so long that they are likely to be interrupted by some -heh- interrupt, then it is clearly not possible to give a reproducable and accurate result; the consequence of which is that the measurement never finishes: namely, it continues to measure until it is statistically 99.9% sure it has the right answer which never happens on a machine that has other processes running when the code takes too long.

https://github.com/CarloWood/cwds/blob/master/benchmark.h#L40

简单程序查找函数执行时间。

#include <iostream>
#include <ctime> // time_t
#include <cstdio>

void function()
{
     for(long int i=0;i<1000000000;i++)
     {
        // do nothing
     }
}

int main()
{

time_t begin,end; // time_t is a datatype to store time values.

time (&begin); // note time before execution
function();
time (&end); // note time after execution

double difference = difftime (end,begin);
printf ("time taken for function() %.2lf seconds.\n", difference );

return 0;
}