我想创建一个随机字符串,由字母-数字字符组成。我希望能够指定字符串的长度。
如何在c++中做到这一点?
我想创建一个随机字符串,由字母-数字字符组成。我希望能够指定字符串的长度。
如何在c++中做到这一点?
当前回答
标准库中最合适的函数是std::sample:
#include <algorithm>
#include <iterator>
#include <random>
#include <string>
#include <iostream>
static const char charset[] =
"0123456789"
"ABCDEFGHIJKLMNOPQRSTUVWXYZ"
"abcdefghijklmnopqrstuvwxyz";
template<typename URBG>
std::string gen_string(std::size_t length, URBG&& g) {
std::string result;
result.resize(length);
std::sample(std::cbegin(charset),
std::cend(charset),
std::begin(result),
std::intptr_t(length),
std::forward<URBG>(g));
return result;
}
int main() {
std::mt19937 g;
std::cout << gen_string(10, g) << std::endl;
std::cout << gen_string(10, g) << std::endl;
}
随机数生成器的状态应该在调用之间保持在函数之外。
其他回答
#include <iostream>
#include <string>
#include <stdlib.h>
int main()
{
int size;
std::cout << "Enter size : ";
std::cin >> size;
std::string str;
for (int i = 0; i < size; i++)
{
auto d = rand() % 26 + 'a';
str.push_back(d);
}
for (int i = 0; i < size; i++)
{
std::cout << str[i] << '\t';
}
return 0;
}
Qt使用示例:
QString random_string(int length=32, QString allow_symbols=QString("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789")) {
QString result;
qsrand(QTime::currentTime().msec());
for (int i = 0; i < length; ++i) {
result.append(allow_symbols.at(qrand() % (allow_symbols.length())));
}
return result;
}
void gen_random(char *s, size_t len) {
for (size_t i = 0; i < len; ++i) {
int randomChar = rand()%(26+26+10);
if (randomChar < 26)
s[i] = 'a' + randomChar;
else if (randomChar < 26+26)
s[i] = 'A' + randomChar - 26;
else
s[i] = '0' + randomChar - 26 - 26;
}
s[len] = 0;
}
#include <iostream>
#include <string>
#include <random>
std::string generateRandomId(size_t length = 0)
{
static const std::string allowed_chars {"123456789BCDFGHJKLMNPQRSTVWXZbcdfghjklmnpqrstvwxz"};
static thread_local std::default_random_engine randomEngine(std::random_device{}());
static thread_local std::uniform_int_distribution<int> randomDistribution(0, allowed_chars.size() - 1);
std::string id(length ? length : 32, '\0');
for (std::string::value_type& c : id) {
c = allowed_chars[randomDistribution(randomEngine)];
}
return id;
}
int main()
{
std::cout << generateRandomId() << std::endl;
}
我的2p解:
#include <random>
#include <string>
std::string random_string(std::string::size_type length)
{
static auto& chrs = "0123456789"
"abcdefghijklmnopqrstuvwxyz"
"ABCDEFGHIJKLMNOPQRSTUVWXYZ";
thread_local static std::mt19937 rg{std::random_device{}()};
thread_local static std::uniform_int_distribution<std::string::size_type> pick(0, sizeof(chrs) - 2);
std::string s;
s.reserve(length);
while(length--)
s += chrs[pick(rg)];
return s;
}