以下是软件版本号:

"1.0", "1.0.1", "2.0", "2.0.0.1", "2.0.1"

我怎么比较呢?

假设正确的顺序是:

"1.0", "1.0.1", "2.0", "2.0.0.1", "2.0.1"

想法很简单… 读第一个数字,然后,第二个,第三个… 但是我不能将版本号转换为浮点数… 你也可以像这样看到版本号:

"1.0.0.0", "1.0.1.0", "2.0.0.0", "2.0.0.1", "2.0.1.0"

这样可以更清楚地看到背后的想法。 但是,我怎样才能把它转换成计算机程序呢?


当前回答

function compare(versionA: string | undefined, versionB: string | undefined, operator: string = '>') {
    if (versionA === undefined || versionB === undefined) {
        return false
    }
    const listA = versionA.split('.')
    const listB = versionB.split('.')
    let a = []
    let b = []
    for (let i = 0; i < listA.length; i++) {
        a.push(parseInt(listA[i].replace(/\D/g, ''), 10))
        b.push(parseInt(listB[i].replace(/\D/g, ''), 10))
    }

    for (let i = 0; i < listA.length; i++) {
        switch (operator) {
            case '>':
            case '>=':
                if (a[i] === b[i]) {
                    continue
                }
                if (a[i] > b[i]) {
                    return true
                }
                if (a[i] < b[i]) {
                    return false
                }
                break
            case '<':
            case '<=':
                if (a[i] === b[i]) {
                    continue
                }
                if (a[i] > b[i]) {
                    return false
                }
                if (a[i] < b[i]) {
                    return true
                }
                break
            case '=':
               if (a[i] > b[i]) {
                   return false
               }
               if (a[i] < b[i]) {
                   return false
               }
               break
        }
    }
    switch (operator) {
        case '>':
            return false
        case '<':
            return false
        case '=':
        case '>=':
        case '<=':
            return true
    }
}

其他回答

看看这篇博客文章。此函数适用于数字版本号。

function compVersions(strV1, strV2) {
  var nRes = 0
    , parts1 = strV1.split('.')
    , parts2 = strV2.split('.')
    , nLen = Math.max(parts1.length, parts2.length);

  for (var i = 0; i < nLen; i++) {
    var nP1 = (i < parts1.length) ? parseInt(parts1[i], 10) : 0
      , nP2 = (i < parts2.length) ? parseInt(parts2[i], 10) : 0;

    if (isNaN(nP1)) { nP1 = 0; }
    if (isNaN(nP2)) { nP2 = 0; }

    if (nP1 != nP2) {
      nRes = (nP1 > nP2) ? 1 : -1;
      break;
    }
  }

  return nRes;
};

compVersions('10', '10.0'); // 0
compVersions('10.1', '10.01.0'); // 0
compVersions('10.0.1', '10.0'); // 1
compVersions('10.0.1', '10.1'); // -1

两个版本比较

const val = '1.2.3 5.4.3';
const arr = val.split(' ');
let obj = {};
for(let i = 0; i<2; i++) {
    const splitArr = arr[i].split('.')
    const reduced = splitArr.reduce((pre, 
    curr)=>parseInt(pre)+parseInt(curr));
    obj[i] = reduced;
}
if(obj[0]>obj[1]) {
    console.log(arr[0]);
} else {
    console.log(arr[1]);
}

这是另一种递归算法。

这段代码只使用了Array。shift和递归,这意味着它可以在Internet Explorer 6+中运行。如果你有任何疑问,你可以访问我的GitHub页面。

(function(root, factory) {
  if (typeof exports === 'object') {
    return module.exports = factory();
  } else if (typeof define === 'function' && define.amd) {
    return define(factory);
  } else {
    return root.compareVer = factory();
  }
})(this, function() {
  'use strict';
  var _compareVer;
  _compareVer = function(newVer, oldVer) {
    var VER_RE, compareNum, isTrue, maxLen, newArr, newLen, newMatch, oldArr, oldLen, oldMatch, zerofill;
    VER_RE = /(\d+\.){1,9}\d+/;
    if (arguments.length !== 2) {
      return -100;
    }
    if (typeof newVer !== 'string') {
      return -2;
    }
    if (typeof oldVer !== 'string') {
      return -3;
    }
    newMatch = newVer.match(VER_RE);
    if (!newMatch || newMatch[0] !== newVer) {
      return -4;
    }
    oldMatch = oldVer.match(VER_RE);
    if (!oldMatch || oldMatch[0] !== oldVer) {
      return -5;
    }
    newVer = newVer.replace(/^0/, '');
    oldVer = oldVer.replace(/^0/, '');
    if (newVer === oldVer) {
      return 0;
    } else {
      newArr = newVer.split('.');
      oldArr = oldVer.split('.');
      newLen = newArr.length;
      oldLen = oldArr.length;
      maxLen = Math.max(newLen, oldLen);
      zerofill = function() {
        newArr.length < maxLen && newArr.push('0');
        oldArr.length < maxLen && oldArr.push('0');
        return newArr.length !== oldArr.length && zerofill();
      };
      newLen !== oldLen && zerofill();
      if (newArr.toString() === oldArr.toString()) {
        if (newLen > oldLen) {
          return 1;
        } else {
          return -1;
        }
      } else {
        isTrue = -1;
        compareNum = function() {
          var _new, _old;
          _new = ~~newArr.shift();
          _old = ~~oldArr.shift();
          _new > _old && (isTrue = 1);
          return _new === _old && newArr.length > 0 && compareNum();
        };
        compareNum();
        return isTrue;
      }
    }
  };
  return _compareVer;
});

好吧,我希望这段代码能帮助到一些人。

下面是测试。

console.log(compareVer("0.0.2","0.0.1"));//1
console.log(compareVer("0.0.10","0.0.1")); //1
console.log(compareVer("0.0.10","0.0.2")); //1
console.log(compareVer("0.9.0","0.9")); //1
console.log(compareVer("0.10.0","0.9.0")); //1
console.log(compareVer("1.7", "1.07")); //1
console.log(compareVer("1.0.07", "1.0.007")); //1

console.log(compareVer("0.3","0.3")); //0
console.log(compareVer("0.0.3","0.0.3")); //0
console.log(compareVer("0.0.3.0","0.0.3.0")); //0
console.log(compareVer("00.3","0.3")); //0
console.log(compareVer("00.3","00.3")); //0
console.log(compareVer("01.0.3","1.0.3")); //0
console.log(compareVer("1.0.3","01.0.3")); //0

console.log(compareVer("0.2.0","1.0.0")); //-1
console.log(compareVer('0.0.2.2.0',"0.0.2.3")); //-1
console.log(compareVer('0.0.2.0',"0.0.2")); //-1
console.log(compareVer('0.0.2',"0.0.2.0")); //-1
console.log(compareVer("1.07", "1.7")); //-1
console.log(compareVer("1.0.007", "1.0.07")); //-1

console.log(compareVer()); //-100
console.log(compareVer("0.0.2")); //-100
console.log(compareVer("0.0.2","0.0.2","0.0.2")); //-100
console.log(compareVer(1212,"0.0.2")); //-2
console.log(compareVer("0.0.2",1212)); //-3
console.log(compareVer('1.abc.2',"1.0.2")); //-4
console.log(compareVer('1.0.2',"1.abc.2")); //-5

你可以遍历每个以句点分隔的字符并将其转换为int类型:

var parts = versionString.split('.');

for (var i = 0; i < parts.length; i++) {
  var value = parseInt(parts[i]);
  // do stuffs here.. perhaps build a numeric version variable?
}

这里找不到我想要的函数。所以我自己写了。这就是我的贡献。我希望有人觉得它有用。

优点:

处理任意长度的版本字符串。'1'或'1.1.1.1.1'。 如果没有指定,则默认为0。仅仅因为字符串更长并不意味着它是一个更大的版本。(“1”应与“1.0”和“1.0.0.0”相同。) 比较数字而不是字符串。('3'<'21'应为真。不是假的。) 不要把时间浪费在无用的比较上。(比较for ==) 你可以选择你自己的比较器。

缺点:

它不处理版本字符串中的字母。(我不知道这是怎么回事?)

我的代码,类似于Jon接受的答案:

function compareVersions(v1, comparator, v2) {
    "use strict";
    var comparator = comparator == '=' ? '==' : comparator;
    if(['==','===','<','<=','>','>=','!=','!=='].indexOf(comparator) == -1) {
        throw new Error('Invalid comparator. ' + comparator);
    }
    var v1parts = v1.split('.'), v2parts = v2.split('.');
    var maxLen = Math.max(v1parts.length, v2parts.length);
    var part1, part2;
    var cmp = 0;
    for(var i = 0; i < maxLen && !cmp; i++) {
        part1 = parseInt(v1parts[i], 10) || 0;
        part2 = parseInt(v2parts[i], 10) || 0;
        if(part1 < part2)
            cmp = 1;
        if(part1 > part2)
            cmp = -1;
    }
    return eval('0' + comparator + cmp);
}

例子:

compareVersions('1.2.0', '==', '1.2'); // true
compareVersions('00001', '==', '1.0.0'); // true
compareVersions('1.2.0', '<=', '1.2'); // true
compareVersions('2.2.0', '<=', '1.2'); // false