如何将字节数组转换为十六进制字符串,反之亦然?
当前回答
为了方便以后复制和粘贴,将几个答案合并到一个类中:
/// <summary>
/// Extension methods to quickly convert byte array to string and back.
/// </summary>
public static class HexConverter
{
/// <summary>
/// Map values to hex digits
/// </summary>
private static readonly char[] HexDigits =
{
'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'
};
/// <summary>
/// Map 56 characters between ['0', 'F'] to their hex equivalents, and set invalid characters
/// such that they will overflow byte to fail conversion.
/// </summary>
private static readonly ushort[] HexValues =
{
0x0000, 0x0001, 0x0002, 0x0003, 0x0004, 0x0005, 0x0006, 0x0007, 0x0008, 0x0009, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
0x000A, 0x000B, 0x000C, 0x000D, 0x000E, 0x000F, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x000A, 0x000B,
0x000C, 0x000D, 0x000E, 0x000F
};
/// <summary>
/// Empty byte array
/// </summary>
private static readonly byte[] Empty = new byte[0];
/// <summary>
/// Convert a byte array to a hexadecimal string.
/// </summary>
/// <param name="bytes">
/// The input byte array.
/// </param>
/// <returns>
/// A string of hexadecimal digits.
/// </returns>
public static string ToHexString(this byte[] bytes)
{
var c = new char[bytes.Length * 2];
for (int i = 0, j = 0; i < bytes.Length; i++)
{
c[j++] = HexDigits[bytes[i] >> 4];
c[j++] = HexDigits[bytes[i] & 0x0F];
}
return new string(c);
}
/// <summary>
/// Parse a string of hexadecimal digits into a byte array.
/// </summary>
/// <param name="hexadecimalString">
/// The hexadecimal string.
/// </param>
/// <returns>
/// The parsed <see cref="byte[]"/> array.
/// </returns>
/// <exception cref="ArgumentException">
/// The input string either contained invalid characters, or was of an odd length.
/// </exception>
public static byte[] ToByteArray(string hexadecimalString)
{
if (!TryParse(hexadecimalString, out var value))
{
throw new ArgumentException("Invalid hexadecimal string", nameof(hexadecimalString));
}
return value;
}
/// <summary>
/// Parse a hexadecimal string to bytes
/// </summary>
/// <param name="hexadecimalString">
/// The hexadecimal string, which must be an even number of characters.
/// </param>
/// <param name="value">
/// The parsed value if successful.
/// </param>
/// <returns>
/// True if successful.
/// </returns>
public static bool TryParse(string hexadecimalString, out byte[] value)
{
if (hexadecimalString.Length == 0)
{
value = Empty;
return true;
}
if (hexadecimalString.Length % 2 != 0)
{
value = Empty;
return false;
}
try
{
value = new byte[hexadecimalString.Length / 2];
for (int i = 0, j = 0; j < hexadecimalString.Length; i++)
{
value[i] = (byte)((HexValues[hexadecimalString[j++] - '0'] << 4)
| HexValues[hexadecimalString[j++] - '0']);
}
return true;
}
catch (OverflowException)
{
value = Empty;
return false;
}
}
}
其他回答
您可以使用BitConverter.ToString方法:
byte[] bytes = {0, 1, 2, 4, 8, 16, 32, 64, 128, 256}
Console.WriteLine( BitConverter.ToString(bytes));
输出:
00-01-02-04-08-10-20-40-80-FF
更多信息:BitConverter.ToString方法(Byte[])
对于插入SQL字符串(如果不使用命令参数):
public static String ByteArrayToSQLHexString(byte[] Source)
{
return = "0x" + BitConverter.ToString(Source).Replace("-", "");
}
为什么要让它变得复杂?这在Visual Studio 2008中很简单:
C#:
string hex = BitConverter.ToString(YourByteArray).Replace("-", "");
VB:
Dim hex As String = BitConverter.ToString(YourByteArray).Replace("-", "")
具有扩展支持的基本解决方案
public static class Utils
{
public static byte[] ToBin(this string hex)
{
int NumberChars = hex.Length;
byte[] bytes = new byte[NumberChars / 2];
for (int i = 0; i < NumberChars; i += 2)
bytes[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
return bytes;
}
public static string ToHex(this byte[] ba)
{
return BitConverter.ToString(ba).Replace("-", "");
}
}
并像下面那样使用这个类
byte[] arr1 = new byte[] { 1, 2, 3 };
string hex1 = arr1.ToHex();
byte[] arr2 = hex1.ToBin();
这里不想赘述很多答案,但我发现了一个十六进制字符串解析器的相当优化(比公认的好4.5倍)、简单的实现。首先,我的测试输出(第一批是我的实现):
Give me that string:
04c63f7842740c77e545bb0b2ade90b384f119f6ab57b680b7aa575a2f40939f
Time to parse 100,000 times: 50.4192 ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
Accepted answer: (StringToByteArray)
Time to parse 100000 times: 233.1264ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
With Mono's implementation:
Time to parse 100000 times: 777.2544ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
With SoapHexBinary:
Time to parse 100000 times: 845.1456ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
base64和“BitConverter'd”行用于测试正确性。请注意,它们是相等的。
实施:
public static byte[] ToByteArrayFromHex(string hexString)
{
if (hexString.Length % 2 != 0) throw new ArgumentException("String must have an even length");
var array = new byte[hexString.Length / 2];
for (int i = 0; i < hexString.Length; i += 2)
{
array[i/2] = ByteFromTwoChars(hexString[i], hexString[i + 1]);
}
return array;
}
private static byte ByteFromTwoChars(char p, char p_2)
{
byte ret;
if (p <= '9' && p >= '0')
{
ret = (byte) ((p - '0') << 4);
}
else if (p <= 'f' && p >= 'a')
{
ret = (byte) ((p - 'a' + 10) << 4);
}
else if (p <= 'F' && p >= 'A')
{
ret = (byte) ((p - 'A' + 10) << 4);
} else throw new ArgumentException("Char is not a hex digit: " + p,"p");
if (p_2 <= '9' && p_2 >= '0')
{
ret |= (byte) ((p_2 - '0'));
}
else if (p_2 <= 'f' && p_2 >= 'a')
{
ret |= (byte) ((p_2 - 'a' + 10));
}
else if (p_2 <= 'F' && p_2 >= 'A')
{
ret |= (byte) ((p_2 - 'A' + 10));
} else throw new ArgumentException("Char is not a hex digit: " + p_2, "p_2");
return ret;
}
我尝试了一些不安全的东西,并将(显然是冗余的)字符移动到另一个方法来蚕食if序列,但这是最快的。
(我承认这回答了一半的问题。我觉得字符串->字节[]转换不足,而字节[]->字符串角度似乎被很好地覆盖了。因此,这个答案。)
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