我看到了一些不同的方法来迭代C#中的字典。有标准的方法吗?


当前回答

从C#7开始,您可以将对象分解为变量。我认为这是遍历字典的最佳方式。

例子:

在KeyValuePair<TKey,TVal>上创建一个扩展方法,对其进行解构:

public static void Deconstruct<TKey, TVal>(this KeyValuePair<TKey, TVal> pair, out TKey key, out TVal value)
{
   key = pair.Key;
   value = pair.Value;
}

按以下方式遍历任何字典<TKey,TVal>

// Dictionary can be of any types, just using 'int' and 'string' as examples.
Dictionary<int, string> dict = new Dictionary<int, string>();

// Deconstructor gets called here.
foreach (var (key, value) in dict)
{
   Console.WriteLine($"{key} : {value}");
}

其他回答

如果您希望在默认情况下迭代值集合,我相信您可以实现IEnumerable<>,其中T是字典中值对象的类型,“this”是字典。

public new IEnumerator<T> GetEnumerator()
{
   return this.Values.GetEnumerator();
}

取决于你是在寻找关键点还是值。。。

来自MSDN Dictionary(TKey,TValue)类描述:

// When you use foreach to enumerate dictionary elements,
// the elements are retrieved as KeyValuePair objects.
Console.WriteLine();
foreach( KeyValuePair<string, string> kvp in openWith )
{
    Console.WriteLine("Key = {0}, Value = {1}", 
        kvp.Key, kvp.Value);
}

// To get the values alone, use the Values property.
Dictionary<string, string>.ValueCollection valueColl =
    openWith.Values;

// The elements of the ValueCollection are strongly typed
// with the type that was specified for dictionary values.
Console.WriteLine();
foreach( string s in valueColl )
{
    Console.WriteLine("Value = {0}", s);
}

// To get the keys alone, use the Keys property.
Dictionary<string, string>.KeyCollection keyColl =
    openWith.Keys;

// The elements of the KeyCollection are strongly typed
// with the type that was specified for dictionary keys.
Console.WriteLine();
foreach( string s in keyColl )
{
    Console.WriteLine("Key = {0}", s);
}

我写了一个扩展来遍历字典。

public static class DictionaryExtension
{
    public static void ForEach<T1, T2>(this Dictionary<T1, T2> dictionary, Action<T1, T2> action) {
        foreach(KeyValuePair<T1, T2> keyValue in dictionary) {
            action(keyValue.Key, keyValue.Value);
        }
    }
}

然后你可以打电话

myDictionary.ForEach((x,y) => Console.WriteLine(x + " - " + y));

有时,如果只需要枚举值,请使用字典的值集合:

foreach(var value in dictionary.Values)
{
    // do something with entry.Value only
}

本帖报道称,这是最快的方法:http://alexpinsker.blogspot.hk/2010/02/c-fastest-way-to-iterate-over.html

我将利用.NET 4.0+的优势,为最初接受的问题提供更新的答案:

foreach(var entry in MyDic)
{
    // do something with entry.Value or entry.Key
}