我有一个onActivityResult从一个mediastore图像选择返回，我可以获得一个图像使用以下URI:
Uri selectedImage = data.getData();
将this转换为字符串会得到:
content://media/external/images/media/47
或路径给出:
/external/images/media/47
然而，我似乎找不到一种方法将其转换为绝对路径，因为我想将图像加载到位图中，而不必复制到某个地方。我知道这可以使用URI和内容解析器来完成，但这似乎在重新启动手机时中断，我猜MediaStore在重新启动之间没有保持其编号相同。
当前回答
如果你的系统版本在19以上，这对我来说是完美的，希望这能帮助你。
@TargetApi(Build.VERSION_CODES.KITKAT)
public static String getPath(final Context context, final Uri uri) {
final boolean isOverKitKat = Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT;
// DocumentProvider
if (isOverKitKat && DocumentsContract.isDocumentUri(context, uri)) {
// ExternalStorageProvider
if (isExternalStorageDocument(uri)) {
final String docId = DocumentsContract.getDocumentId(uri);
final String[] split = docId.split(":");
final String type = split[0];
if ("primary".equalsIgnoreCase(type)) {
return Environment.getExternalStorageDirectory() + "/"
+ split[1];
}
}
// DownloadsProvider
else if (isDownloadsDocument(uri)) {
final String id = DocumentsContract.getDocumentId(uri);
final Uri contentUri = ContentUris.withAppendedId(
Uri.parse("content://downloads/public_downloads"),
Long.valueOf(id));
return getDataColumn(context, contentUri, null, null);
}
// MediaProvider
else if (isMediaDocument(uri)) {
final String docId = DocumentsContract.getDocumentId(uri);
final String[] split = docId.split(":");
final String type = split[0];
Uri contentUri = null;
if ("image".equals(type)) {
contentUri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI;
} else if ("video".equals(type)) {
contentUri = MediaStore.Video.Media.EXTERNAL_CONTENT_URI;
} else if ("audio".equals(type)) {
contentUri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
}
final String selection = "_id=?";
final String[] selectionArgs = new String[]{split[1]};
return getDataColumn(context, contentUri, selection,
selectionArgs);
}
}
// MediaStore (and general)
else if ("content".equalsIgnoreCase(uri.getScheme())) {
// Return the remote address
if (isGooglePhotosUri(uri))
return uri.getLastPathSegment();
return getDataColumn(context, uri, null, null);
}
// File
else if ("file".equalsIgnoreCase(uri.getScheme())) {
return uri.getPath();
}
return null;
}
其他回答
像下面这样获取Uri。
//* get cursor like normal
Then
while (cursor.moveToNext()) {
Uri uri = ContentUris.withAppendedId(
MediaStore.Images.Media.EXTERNAL_CONTENT_URI, id);
}
这是我的例子获取文件名，从URI file://…内容://... .这是为我工作，不仅与Android MediaStore，而且与第三方应用程序，如EzExplorer。
public static String getFileNameByUri(Context context, Uri uri)
{
String fileName="unknown";//default fileName
Uri filePathUri = uri;
if (uri.getScheme().toString().compareTo("content")==0)
{
Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
if (cursor.moveToFirst())
{
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);//Instead of "MediaStore.Images.Media.DATA" can be used "_data"
filePathUri = Uri.parse(cursor.getString(column_index));
fileName = filePathUri.getLastPathSegment().toString();
}
}
else if (uri.getScheme().compareTo("file")==0)
{
fileName = filePathUri.getLastPathSegment().toString();
}
else
{
fileName = fileName+"_"+filePathUri.getLastPathSegment();
}
return fileName;
}
不要尝试在文件系统中查找uri，那样在数据库中查找东西会很慢。
你可以通过给工厂一个输入流来从uri中获得位图，就像给工厂一个文件一样:
InputStream is = getContentResolver().openInputStream(uri);
Bitmap bitmap = BitmapFactory.decodeStream(is);
is.close();
如果你的系统版本在19以上，这对我来说是完美的，希望这能帮助你。
@TargetApi(Build.VERSION_CODES.KITKAT)
public static String getPath(final Context context, final Uri uri) {
final boolean isOverKitKat = Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT;
// DocumentProvider
if (isOverKitKat && DocumentsContract.isDocumentUri(context, uri)) {
// ExternalStorageProvider
if (isExternalStorageDocument(uri)) {
final String docId = DocumentsContract.getDocumentId(uri);
final String[] split = docId.split(":");
final String type = split[0];
if ("primary".equalsIgnoreCase(type)) {
return Environment.getExternalStorageDirectory() + "/"
+ split[1];
}
}
// DownloadsProvider
else if (isDownloadsDocument(uri)) {
final String id = DocumentsContract.getDocumentId(uri);
final Uri contentUri = ContentUris.withAppendedId(
Uri.parse("content://downloads/public_downloads"),
Long.valueOf(id));
return getDataColumn(context, contentUri, null, null);
}
// MediaProvider
else if (isMediaDocument(uri)) {
final String docId = DocumentsContract.getDocumentId(uri);
final String[] split = docId.split(":");
final String type = split[0];
Uri contentUri = null;
if ("image".equals(type)) {
contentUri = MediaStore.Images.Media.EXTERNAL_CONTENT_URI;
} else if ("video".equals(type)) {
contentUri = MediaStore.Video.Media.EXTERNAL_CONTENT_URI;
} else if ("audio".equals(type)) {
contentUri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI;
}
final String selection = "_id=?";
final String[] selectionArgs = new String[]{split[1]};
return getDataColumn(context, contentUri, selection,
selectionArgs);
}
}
// MediaStore (and general)
else if ("content".equalsIgnoreCase(uri.getScheme())) {
// Return the remote address
if (isGooglePhotosUri(uri))
return uri.getLastPathSegment();
return getDataColumn(context, uri, null, null);
}
// File
else if ("file".equalsIgnoreCase(uri.getScheme())) {
return uri.getPath();
}
return null;
}
在这里，我将向您展示如何创建一个BROWSE按钮，当您单击它时，它将打开SD卡，您将选择一个文件，结果您将获得所选文件的文件名和文件路径:
一个你要按的按钮
browse.setOnClickListener(new OnClickListener()
{
public void onClick(View v)
{
Intent intent = new Intent();
intent.setAction(Intent.ACTION_PICK);
Uri startDir = Uri.fromFile(new File("/sdcard"));
startActivityForResult(intent, PICK_REQUEST_CODE);
}
});
获取结果文件名和文件路径的函数
protected void onActivityResult(int requestCode, int resultCode, Intent intent)
{
if (requestCode == PICK_REQUEST_CODE)
{
if (resultCode == RESULT_OK)
{
Uri uri = intent.getData();
if (uri.getScheme().toString().compareTo("content")==0)
{
Cursor cursor =getContentResolver().query(uri, null, null, null, null);
if (cursor.moveToFirst())
{
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);//Instead of "MediaStore.Images.Media.DATA" can be used "_data"
Uri filePathUri = Uri.parse(cursor.getString(column_index));
String file_name = filePathUri.getLastPathSegment().toString();
String file_path=filePathUri.getPath();
Toast.makeText(this,"File Name & PATH are:"+file_name+"\n"+file_path, Toast.LENGTH_LONG).show();
}
}
}
}
}
