我的活动中有一些碎片

[1], [2], [3], [4], [5], [6]

如果当前活动片段是[2],那么在返回按钮上按下我必须从[2]返回到[1],否则什么也不做。

最好的做法是什么?

编辑:应用程序不能从[3]…[6]返回[2]


当前回答

对于那些谁使用静态片段

在这种情况下,如果你有一个静态片段,那么它会更可取。 为片段创建一个实例对象

private static MyFragment instance=null;

在MyFragment的onCreate()中初始化该实例

  instance=this;

也可以创建一个函数来获取Instance

 public static MyFragment getInstance(){
   return instance;
}

也可以创建函数

public boolean allowBackPressed(){
    if(allowBack==true){
        return true;
    }
    return false;
}


 //allowBack is a boolean variable that will be set to true at the action 
 //where you want that your backButton should not close activity. In my case I open 
 //Navigation Drawer then I set it to true. so when I press backbutton my 
 //drawer should be get closed

public void performSomeAction(){
    //.. Your code
    ///Here I have closed my drawer
}

在你能做的活动中

@Override
public void onBackPressed() {

    if (MyFragment.getInstance().allowBackPressed()) { 
        MyFragment.getInstance().performSomeAction();
    }
    else{
        super.onBackPressed();
    }
}

其他回答

创建接口:

后退按钮处理程序接口

public interface BackButtonHandlerInterface {
    void addBackClickListener (OnBackClickListener onBackClickListener);
    void removeBackClickListener (OnBackClickListener onBackClickListener);
}

OnBackClickListener

public interface OnBackClickListener {
     boolean onBackClick();
}

在活动:

public class MainActivity extends AppCompatActivity implements BackButtonHandlerInterface {

    private ArrayList<WeakReference<OnBackClickListener>> backClickListenersList = new ArrayList<>();

    @Override
    public void addBackClickListener(OnBackClickListener onBackClickListener) {
        backClickListenersList.add(new WeakReference<>(onBackClickListener));
    }

    @Override
    public void removeBackClickListener(OnBackClickListener onBackClickListener) {
        for (Iterator<WeakReference<OnBackClickListener>> iterator = backClickListenersList.iterator();
         iterator.hasNext();){
            WeakReference<OnBackClickListener> weakRef = iterator.next();
            if (weakRef.get() == onBackClickListener){
                iterator.remove();
            }
        }
    }

    @Override
    public void onBackPressed() {
        if(!fragmentsBackKeyIntercept()){
            super.onBackPressed();
        }
    }

    private boolean fragmentsBackKeyIntercept() {
        boolean isIntercept = false;
        for (WeakReference<OnBackClickListener> weakRef : backClickListenersList) {
            OnBackClickListener onBackClickListener = weakRef.get();
            if (onBackClickListener != null) {
                boolean isFragmIntercept = onBackClickListener.onBackClick();
                if (!isIntercept) isIntercept = isFragmIntercept;
            }
        }
        return isIntercept;
    }
}

在片段:

public class MyFragment extends Fragment implements OnBackClickListener{

    private BackButtonHandlerInterface backButtonHandler;

    @Override
    public void onAttach(Activity activity) {
        super.onAttach(activity);
        backButtonHandler = (BackButtonHandlerInterface) activity;
        backButtonHandler.addBackClickListener(this);
    }

    @Override
    public void onDetach() {
        super.onDetach();
        backButtonHandler.removeBackClickListener(this);
        backButtonHandler = null;
    }

    @Override
    public boolean onBackClick() {
        //This method handle onBackPressed()! return true or false
        return false;
    }

}

更新

提供自定义向后导航

class MyFragment : Fragment() {

    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)

        // This callback will only be called when MyFragment is at least Started.
        val callback = requireActivity().onBackPressedDispatcher.addCallback(this) {
            // Handle the back button event
        }

        // The callback can be enabled or disabled here or in the lambda
    }

}
            rootView.setFocusableInTouchMode(true);
            rootView.requestFocus();
            rootView.setOnKeyListener(new View.OnKeyListener() {
            @Override
            public boolean onKey(View v, int keyCode, KeyEvent event)   {
            if (keyCode == KeyEvent.KEYCODE_BACK) {


                Fragment NameofFragment = new NameofFragment;

                FragmentTransaction  transaction=getFragmentManager().beginTransaction();
                transaction.replace(R.id.frame_container,NameofFragment);

                transaction.commit();

                return true;
            }
            return false;
        }
    });

    return rootView;

在您的活动中添加此代码

@Override

public void onBackPressed() {
    if (getFragmentManager().getBackStackEntryCount() == 0) {
        super.onBackPressed();
    } else {
        getFragmentManager().popBackStack();
    }
}

并在commit()之前在Fragment中添加这一行

ft.addToBackStack(任何名称);

将addToBackStack()添加到片段事务中,然后使用下面的代码为片段实现反向导航

getSupportFragmentManager().addOnBackStackChangedListener(
    new FragmentManager.OnBackStackChangedListener() {
        public void onBackStackChanged() {
            // Update your UI here.
        }
    });

我认为最简单的方法是创建一个接口,并在Activity中检查片段是否属于接口类型,如果是,则调用它的方法来处理弹出。下面是要在片段中实现的接口。

public interface BackPressedFragment {

    // Note for this to work, name AND tag must be set anytime the fragment is added to back stack, e.g.
    // getActivity().getSupportFragmentManager().beginTransaction()
    //                .replace(R.id.fragment_container, MyFragment.newInstance(), "MY_FRAG_TAG")
    //                .addToBackStack("MY_FRAG_TAG")
    //                .commit();
    // This is really an override. Should call popBackStack itself.
    void onPopBackStack();
}

下面是如何实现它。

public class MyFragment extends Fragment implements BackPressedFragment
    @Override
    public void onPopBackStack() {
        /* Your code goes here, do anything you want. */
        getActivity().getSupportFragmentManager().popBackStack();
}

在你的Activity中,当你处理弹出时(可能在onBackPressed和onOptionsItemSelected中),使用这个方法弹出backstack:

public void popBackStack() {
    FragmentManager fm = getSupportFragmentManager();
    // Call current fragment's onPopBackStack if it has one.
    String fragmentTag = fm.getBackStackEntryAt(fm.getBackStackEntryCount() - 1).getName();
    Fragment currentFragment = getSupportFragmentManager().findFragmentByTag(fragmentTag);
    if (currentFragment instanceof BackPressedFragment)
        ((BackPressedFragment)currentFragment).onPopBackStack();
    else
        fm.popBackStack();
}