如何在ImageView中使用URL引用的图像?
当前回答
你必须先下载图像
public static Bitmap loadBitmap(String url) {
Bitmap bitmap = null;
InputStream in = null;
BufferedOutputStream out = null;
try {
in = new BufferedInputStream(new URL(url).openStream(), IO_BUFFER_SIZE);
final ByteArrayOutputStream dataStream = new ByteArrayOutputStream();
out = new BufferedOutputStream(dataStream, IO_BUFFER_SIZE);
copy(in, out);
out.flush();
final byte[] data = dataStream.toByteArray();
BitmapFactory.Options options = new BitmapFactory.Options();
//options.inSampleSize = 1;
bitmap = BitmapFactory.decodeByteArray(data, 0, data.length,options);
} catch (IOException e) {
Log.e(TAG, "Could not load Bitmap from: " + url);
} finally {
closeStream(in);
closeStream(out);
}
return bitmap;
}
然后使用Imageview。setImageBitmap将位图设置为ImageView
其他回答
public class LoadWebImg extends Activity {
String image_URL=
"http://java.sogeti.nl/JavaBlog/wp-content/uploads/2009/04/android_icon_256.png";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
ImageView bmImage = (ImageView)findViewById(R.id.image);
BitmapFactory.Options bmOptions;
bmOptions = new BitmapFactory.Options();
bmOptions.inSampleSize = 1;
Bitmap bm = LoadImage(image_URL, bmOptions);
bmImage.setImageBitmap(bm);
}
private Bitmap LoadImage(String URL, BitmapFactory.Options options)
{
Bitmap bitmap = null;
InputStream in = null;
try {
in = OpenHttpConnection(URL);
bitmap = BitmapFactory.decodeStream(in, null, options);
in.close();
} catch (IOException e1) {
}
return bitmap;
}
private InputStream OpenHttpConnection(String strURL) throws IOException{
InputStream inputStream = null;
URL url = new URL(strURL);
URLConnection conn = url.openConnection();
try{
HttpURLConnection httpConn = (HttpURLConnection)conn;
httpConn.setRequestMethod("GET");
httpConn.connect();
if (httpConn.getResponseCode() == HttpURLConnection.HTTP_OK) {
inputStream = httpConn.getInputStream();
}
}
catch (Exception ex)
{
}
return inputStream;
}
}
private Bitmap getImageBitmap(String url) {
Bitmap bm = null;
try {
URL aURL = new URL(url);
URLConnection conn = aURL.openConnection();
conn.connect();
InputStream is = conn.getInputStream();
BufferedInputStream bis = new BufferedInputStream(is);
bm = BitmapFactory.decodeStream(bis);
bis.close();
is.close();
} catch (IOException e) {
Log.e(TAG, "Error getting bitmap", e);
}
return bm;
}
这里有很多好的信息…我最近发现了一个叫SmartImageView的类,到目前为止它似乎工作得很好。非常容易合并和使用。
http://loopj.com/android-smart-image-view/
https://github.com/loopj/android-smart-image-view
更新:我最后写了一篇关于这个的博客文章,所以看看它对使用SmartImageView的帮助。
第二次更新:我现在总是用毕加索做这个(见上文),强烈推荐它。:)
你必须先下载图像
public static Bitmap loadBitmap(String url) {
Bitmap bitmap = null;
InputStream in = null;
BufferedOutputStream out = null;
try {
in = new BufferedInputStream(new URL(url).openStream(), IO_BUFFER_SIZE);
final ByteArrayOutputStream dataStream = new ByteArrayOutputStream();
out = new BufferedOutputStream(dataStream, IO_BUFFER_SIZE);
copy(in, out);
out.flush();
final byte[] data = dataStream.toByteArray();
BitmapFactory.Options options = new BitmapFactory.Options();
//options.inSampleSize = 1;
bitmap = BitmapFactory.decodeByteArray(data, 0, data.length,options);
} catch (IOException e) {
Log.e(TAG, "Could not load Bitmap from: " + url);
} finally {
closeStream(in);
closeStream(out);
}
return bitmap;
}
然后使用Imageview。setImageBitmap将位图设置为ImageView
这是一个迟到的回复,正如上面所建议的AsyncTask将会和谷歌一点后,我发现了一个解决这个问题的方法。
Drawable Drawable = Drawable. createfromstream ((InputStream) new URL(" URL ").getContent(), "src");
imageView.setImageDrawable(可拉的);
这是完整的功能:
public void loadMapPreview () {
//start a background thread for networking
new Thread(new Runnable() {
public void run(){
try {
//download the drawable
final Drawable drawable = Drawable.createFromStream((InputStream) new URL("url").getContent(), "src");
//edit the view in the UI thread
imageView.post(new Runnable() {
public void run() {
imageView.setImageDrawable(drawable);
}
});
} catch (IOException e) {
e.printStackTrace();
}
}
}).start();
}
不要忘记在你的AndroidManifest.xml中添加以下权限来访问互联网。
< uses-permission android: name = " android.permission。互联网" / >
我自己也试过,还没有遇到任何问题。
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