...
    gradle.taskGraph.beforeTask { Task task ->
        if (task.name ==~ /process.*GoogleServices/) {
            android.applicationVariants.all { variant ->
                if (task.name ==~ /(?i)process${variant.flavorName}(Debug|Release)GoogleServices/) {
                    copy {
                        from "src/tenants/${variant.flavorName}"
                        include 'google-services.json'
                        into '.'
                    }
                }
            }
        }
    }

    gradle.taskGraph.afterTask { Task task ->
        if (task.name ==~ /process.*GoogleServices/) {
            android.applicationVariants.all { variant ->
                if (task.name ==~ /(?i)process${variant.flavorName}(Debug|Release)GoogleServices/) {
                    delete fileTree(".").matching {
                        include 'google-services.json'
                    }
                }
            }
        }
    }

根据@ZakTaccardi的回答，并且假设您不想在两个版本中都使用一个项目，请将此添加到构建的末尾。gradle文件:

def appModuleRootFolder = '.'
def srcDir = 'src'
def googleServicesJson = 'google-services.json'

task switchToStaging(type: Copy) {
    outputs.upToDateWhen { false }
    def flavor = 'staging'
    description = "Switches to $flavor $googleServicesJson"
    delete "$appModuleRootFolder/$googleServicesJson"
    from "${srcDir}/$flavor/"
    include "$googleServicesJson"
    into "$appModuleRootFolder"
}

task switchToProduction(type: Copy) {
    outputs.upToDateWhen { false }
    def flavor = 'production'
    description = "Switches to $flavor $googleServicesJson"
    from "${srcDir}/$flavor/"
    include "$googleServicesJson"
    into "$appModuleRootFolder"
}

afterEvaluate {
    processStagingDebugGoogleServices.dependsOn switchToStaging
    processStagingReleaseGoogleServices.dependsOn switchToStaging
    processProductionDebugGoogleServices.dependsOn switchToProduction
    processProductionReleaseGoogleServices.dependsOn switchToProduction
}

你需要src/staging/google-services文件。Json和src/production/google-services.json。替换您所使用的风味名称。

只需在同一个项目中添加调味应用程序id和口味的名称，下载google-service。Json文件，它将在客户端数组[]中包含所有口味，这将适用于所有口味。

我目前在同一个应用程序包中使用两个GCM项目Id。我加入了谷歌服务。我的第一个GCM项目的json，但我从第一个切换到第二个只改变SENDER_ID:

    String token = instanceID.getToken(SENDER_ID,GoogleCloudMessaging.INSTANCE_ID_SCOPE, null);

(在这一点上，我认为谷歌的服务。Json不是强制性的)

    ...
    gradle.taskGraph.beforeTask { Task task ->
        if (task.name ==~ /process.*GoogleServices/) {
            android.applicationVariants.all { variant ->
                if (task.name ==~ /(?i)process${variant.flavorName}(Debug|Release)GoogleServices/) {
                    copy {
                        from "src/tenants/${variant.flavorName}"
                        include 'google-services.json'
                        into '.'
                    }
                }
            }
        }
    }

    gradle.taskGraph.afterTask { Task task ->
        if (task.name ==~ /process.*GoogleServices/) {
            android.applicationVariants.all { variant ->
                if (task.name ==~ /(?i)process${variant.flavorName}(Debug|Release)GoogleServices/) {
                    delete fileTree(".").matching {
                        include 'google-services.json'
                    }
                }
            }
        }
    }

根据Firebase文档，你也可以使用字符串资源来代替google-services.json。

因为这个提供者只是读取已知名称的资源，另一种选择是直接将字符串资源添加到应用程序中，而不是使用谷歌Services gradle插件。你可以这样做: 从根build.gradle中移除google-services插件 删除google服务。来自项目的Json 直接添加字符串资源 删除应用插件:'com.google.gms。你的应用build.gradle中的Google-services

示例strings.xml:

<string name="google_client_id">XXXXXXXXX.apps.googleusercontent.com</string>
<string name="default_web_client_id">XXXX-XXXXXX.apps.googleusercontent.com</string>
<string name="gcm_defaultSenderId">XXXXXX</string>
<string name="google_api_key">AIzaXXXXXX</string>
<string name="google_app_id">1:XXXXXX:android:XXXXX</string>
<string name="google_crash_reporting_api_key">AIzaXXXXXXX</string>
<string name="project_id">XXXXXXX</string>