如何在SQL Server 2005+中获得所有索引和索引列的列表?我能想到的最接近的是:
select s.name, t.name, i.name, c.name from sys.tables t
inner join sys.schemas s on t.schema_id = s.schema_id
inner join sys.indexes i on i.object_id = t.object_id
inner join sys.index_columns ic on ic.object_id = t.object_id
inner join sys.columns c on c.object_id = t.object_id and
ic.column_id = c.column_id
where i.index_id > 0
and i.type in (1, 2) -- clustered & nonclustered only
and i.is_primary_key = 0 -- do not include PK indexes
and i.is_unique_constraint = 0 -- do not include UQ
and i.is_disabled = 0
and i.is_hypothetical = 0
and ic.key_ordinal > 0
order by ic.key_ordinal
这可不是我想要的。
我想要的是，列出所有用户定义的索引，(这意味着不支持唯一约束和主键的索引)与所有列(按它们在索引定义中的出现方式排序)以及尽可能多的元数据。
根据Tim Ford的代码，这是正确答案:
select tab.[name] as [table_name],
idx.[name] as [index_name],
allc.[name] as [column_name],
idx.[type_desc],
idx.[is_unique],
idx.[data_space_id],
idx.[ignore_dup_key],
idx.[is_primary_key],
idx.[is_unique_constraint],
idx.[fill_factor],
idx.[is_padded],
idx.[is_disabled],
idx.[is_hypothetical],
idx.[allow_row_locks],
idx.[allow_page_locks],
idxc.[is_descending_key],
idxc.[is_included_column],
idxc.[index_column_id]
from sys.[tables] as tab
inner join sys.[indexes] idx on tab.[object_id] = idx.[object_id]
inner join sys.[index_columns] idxc on idx.[object_id] = idxc.[object_id] and idx.[index_id] = idxc.[index_id]
inner join sys.[all_columns] allc on tab.[object_id] = allc.[object_id] and idxc.[column_id] = allc.[column_id]
where tab.[name] Like '%table_name%'
and idx.[name] Like '%index_name%'
order by tab.[name], idx.[index_id], idxc.[index_column_id]
我更新了KFD9的答案。
我调整了他们的版本，以支持include-specification，而不使用已弃用的indexkey_property
这为索引和约束提供了create和drop语句。
with indexes as (
SELECT
schema_name(schema_id) as SchemaName, OBJECT_NAME(si.object_id) as TableName, si.name as IndexName,
(CASE is_primary_key WHEN 1 THEN 'PK' ELSE '' END) as PK,
(CASE is_unique WHEN 1 THEN '1' ELSE '0' END)+' '+
(CASE si.type WHEN 1 THEN 'C' WHEN 3 THEN 'X' ELSE 'B' END)+' ' as 'Type', -- B=basic, C=Clustered, X=XML
(select string_agg(CAST('[' + c.name + ']' + case when is_descending_key = 1 then ' DESC' else '' end AS NVARCHAR(MAX)), ',') within group (order by index_column_id)
from sys.index_columns ic JOIN sys.columns c on ic.column_id = c.column_id and ic.object_id = c.object_id where ic.index_id = si.index_id and ic.object_id = si.object_id and ic.is_included_column = 0) Cols,
(select string_agg(CAST('[' + c.name + ']' + case when is_descending_key = 1 then ' DESC' else '' end AS NVARCHAR(MAX)), ',') within group (order by index_column_id)
from sys.index_columns ic JOIN sys.columns c on ic.column_id = c.column_id and ic.object_id = c.object_id where ic.index_id = si.index_id and ic.object_id = si.object_id and ic.is_included_column = 1) IncludedCols,
(select count(*) from sys.index_columns ic where ic.index_id = si.index_id and ic.object_id = si.object_id) IndexColsCount
FROM sys.indexes as si
LEFT JOIN sys.objects as so on so.object_id=si.object_id
WHERE index_id>0 -- omit the default heap
and OBJECTPROPERTY(si.object_id,'IsMsShipped')=0 -- omit system tables
and not (schema_name(schema_id)='dbo' and OBJECT_NAME(si.object_id)='sysdiagrams') -- omit sysdiagrams
)
SELECT SchemaName, TableName, IndexName,
(CASE pk
WHEN 'PK' THEN 'ALTER '+
'TABLE ['+SchemaName+'].['+TableName+'] ADD CONSTRAINT ['+IndexName+'] PRIMARY KEY'+
(CASE substring(Type,3,1) WHEN 'C' THEN ' CLUSTERED' ELSE '' END)
ELSE 'CREATE '+
(CASE substring(Type,1,1) WHEN '1' THEN 'UNIQUE ' ELSE '' END)+
(CASE substring(Type,3,1) WHEN 'C' THEN 'CLUSTERED ' ELSE '' END)+
'INDEX ['+IndexName+'] ON ['+SchemaName+'].['+TableName+']'
END)+
' ('+Cols+')'+
isnull(' include ('+IncludedCols+')', '')+
'' as CreateIndex,
CASE pk
WHEN 'PK' THEN 'ALTER '+
'TABLE ['+SchemaName+'].['+TableName+'] DROP CONSTRAINT ['+IndexName+'] '
ELSE 'DROP INDEX ['+IndexName+'] ON ['+SchemaName+'].['+TableName + ']'
END AS DropIndex,
IndexColsCount
FROM indexes
ORDER BY SchemaName,TableName,IndexName
select i.object_id, i.name as [index] , STRING_AGG(c.name,', ') as [column], o.name as [table] from sys.indexes i
INNER join sys.index_columns ic on ic.object_id = i.object_id and ic.index_id = i.index_id
INNER join sys.columns c on c.object_id = ic.object_id and ic.column_id = c.column_id
INNER JOIN sys.objects o on o.object_id = i.object_id
where i.object_id > 100 and i.is_primary_key = 0 and i.is_unique = 0 and o.is_ms_shipped <> 1
group by i.object_id, i.name, o.name
order by i.name
将此用于sql 2016及更高级别，它会显示object_id, indexname，列和表名为非唯一的，没有主键
——简短而甜蜜:
SELECT OBJECT_SCHEMA_NAME(T.[object_id],DB_ID()) AS [Schema],
T.[name] AS [table_name], I.[name] AS [index_name], AC.[name] AS [column_name],
I.[type_desc], I.[is_unique], I.[data_space_id], I.[ignore_dup_key], I.[is_primary_key],
I.[is_unique_constraint], I.[fill_factor], I.[is_padded], I.[is_disabled], I.[is_hypothetical],
I.[allow_row_locks], I.[allow_page_locks], IC.[is_descending_key], IC.[is_included_column]
FROM sys.[tables] AS T
INNER JOIN sys.[indexes] I ON T.[object_id] = I.[object_id]
INNER JOIN sys.[index_columns] IC ON I.[object_id] = IC.[object_id]
INNER JOIN sys.[all_columns] AC ON T.[object_id] = AC.[object_id] AND IC.[column_id] = AC.[column_id]
WHERE T.[is_ms_shipped] = 0 AND I.[type_desc] <> 'HEAP'
ORDER BY T.[name], I.[index_id], IC.[key_ordinal]
根据Tim Ford的代码，这是正确答案:
select tab.[name] as [table_name],
idx.[name] as [index_name],
allc.[name] as [column_name],
idx.[type_desc],
idx.[is_unique],
idx.[data_space_id],
idx.[ignore_dup_key],
idx.[is_primary_key],
idx.[is_unique_constraint],
idx.[fill_factor],
idx.[is_padded],
idx.[is_disabled],
idx.[is_hypothetical],
idx.[allow_row_locks],
idx.[allow_page_locks],
idxc.[is_descending_key],
idxc.[is_included_column],
idxc.[index_column_id]
from sys.[tables] as tab
inner join sys.[indexes] idx on tab.[object_id] = idx.[object_id]
inner join sys.[index_columns] idxc on idx.[object_id] = idxc.[object_id] and idx.[index_id] = idxc.[index_id]
inner join sys.[all_columns] allc on tab.[object_id] = allc.[object_id] and idxc.[column_id] = allc.[column_id]
where tab.[name] Like '%table_name%'
and idx.[name] Like '%index_name%'
order by tab.[name], idx.[index_id], idxc.[index_column_id]
