在objective-c/cocoa中抛出异常的最佳方法是什么?


当前回答

可以使用两种方法在try catch块中引发异常

@throw[NSException exceptionWithName];

或者第二种方法

NSException e;
[e raise];

其他回答

我使用[NSException raise:format:]如下所示:

[NSException raise:@"Invalid foo value" format:@"foo of %d is invalid", foo];

@throw([NSException exceptionWithName:…

- (void)parseError:(NSError *)error
       completionBlock:(void (^)(NSString *error))completionBlock {


    NSString *resultString = [NSString new];

    @try {

    NSData *errorData = [NSData dataWithData:error.userInfo[@"SomeKeyForData"]];

    if(!errorData.bytes) {

        @throw([NSException exceptionWithName:@"<Set Yours exc. name: > Test Exc" reason:@"<Describe reason: > Doesn't contain data" userInfo:nil]);
    }


    NSDictionary *dictFromData = [NSJSONSerialization JSONObjectWithData:errorData
                                                                 options:NSJSONReadingAllowFragments
                                                                   error:&error];

    resultString = dictFromData[@"someKey"];
    ...


} @catch (NSException *exception) {

      NSLog( @"Caught Exception Name: %@", exception.name);
      NSLog( @"Caught Exception Reason: %@", exception.reason );

    resultString = exception.reason;

} @finally {

    completionBlock(resultString);
}

}

使用:

[self parseError:error completionBlock:^(NSString *error) {
            NSLog(@"%@", error);
        }];

另一个更高级的用例:

- (void)parseError:(NSError *)error completionBlock:(void (^)(NSString *error))completionBlock {

NSString *resultString = [NSString new];

NSException* customNilException = [NSException exceptionWithName:@"NilException"
                                                          reason:@"object is nil"
                                                        userInfo:nil];

NSException* customNotNumberException = [NSException exceptionWithName:@"NotNumberException"
                                                                reason:@"object is not a NSNumber"
                                                              userInfo:nil];

@try {

    NSData *errorData = [NSData dataWithData:error.userInfo[@"SomeKeyForData"]];

    if(!errorData.bytes) {

        @throw([NSException exceptionWithName:@"<Set Yours exc. name: > Test Exc" reason:@"<Describe reason: > Doesn't contain data" userInfo:nil]);
    }


    NSDictionary *dictFromData = [NSJSONSerialization JSONObjectWithData:errorData
                                                                 options:NSJSONReadingAllowFragments
                                                                   error:&error];

    NSArray * array = dictFromData[@"someArrayKey"];

    for (NSInteger i=0; i < array.count; i++) {

        id resultString = array[i];

        if (![resultString isKindOfClass:NSNumber.class]) {

            [customNotNumberException raise]; // <====== HERE is just the same as: @throw customNotNumberException;

            break;

        } else if (!resultString){

            @throw customNilException;        // <======

            break;
        }

    }

} @catch (SomeCustomException * sce) {
    // most specific type
    // handle exception ce
    //...
} @catch (CustomException * ce) {
    // most specific type
    // handle exception ce
    //...
} @catch (NSException *exception) {
    // less specific type

    // do whatever recovery is necessary at his level
    //...
    // rethrow the exception so it's handled at a higher level

    @throw (SomeCustomException * customException);

} @finally {
    // perform tasks necessary whether exception occurred or not

}

}

@throw([NSException exceptionWith…])

Xcode将@throw语句识别为函数出口点,就像return语句一样。使用@throw语法可以避免错误的“Control may reach end of non-void function”警告,你可能会从[NSException raise:…]得到这种警告。

同样,@throw也可以用来抛出不属于NSException类的对象。

可以使用两种方法在try catch块中引发异常

@throw[NSException exceptionWithName];

或者第二种方法

NSException e;
[e raise];

我认为为了保持一致性,最好在你自己的类中使用@throw,它扩展了NSException。然后使用相同的表示法try catch finally:

@try {
.....
}
@catch{
...
}
@finally{
...
}

Apple解释了如何抛出和处理异常:

捕获异常 抛出异常