在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
在Java中,数组可以这样初始化:
int numbers[] = new int[] {10, 20, 30, 40, 50}
Kotlin的数组初始化是怎样的?
当前回答
I think one thing that is worth mentioning and isn't intuitive enough from the documentation is that, when you use a factory function to create an array and you specify it's size, the array is initialized with values that are equal to their index values. For example, in an array such as this: val array = Array(5, { i -> i }), the initial values assigned are [0,1,2,3,4] and not say, [0,0,0,0,0]. That is why from the documentation, val asc = Array(5, { i -> (i * i).toString() }) produces an answer of ["0", "1", "4", "9", "16"]
其他回答
在Kotlin中,我们可以使用arrayOf(), intArrayOf(), charArrayOf(), booleanArrayOf(), longArrayOf()函数来创建数组。
例如:
var Arr1 = arrayOf(1,10,4,6,15)
var Arr2 = arrayOf<Int>(1,10,4,6,15)
var Arr3 = arrayOf<String>("Surat","Mumbai","Rajkot")
var Arr4 = arrayOf(1,10,4, "Ajay","Prakesh")
var Arr5: IntArray = intArrayOf(5,10,15,20)
对于二维数组:
val rows = 3
val cols = 3
val value = 0
val array = Array(rows) { Array<Int>(cols) { value } }
您可以将元素类型更改为您想要的任何类型(String, Class,…),并将值更改为相应的默认值。
Kotlin有专门的类来表示基本类型的数组,没有装箱开销。例如- IntArray, ShortArray, ByteArray等。我需要说明,这些类与父Array类没有继承关系,但它们具有相同的方法和属性集。它们中的每一个都有相应的工厂函数。所以,要在Kotlin中初始化一个数组,你只需要键入以下内容:
val myArr: IntArray = intArrayOf(10, 20, 30, 40, 50)
...或者这样:
val myArr = Array<Int>(5, { i -> ((i + 1) * 10) })
myArr.forEach { println(it) } // 10, 20, 30, 40, 50
现在你可以使用它:
myArr[0] = (myArr[1] + myArr[2]) - myArr[3]
你可以这样做:
val numbers = intArrayOf(10, 20, 30, 40, 50)
or
val numbers = arrayOf<Int>(10, 20, 30, 40, 50)
also
val numbers = arrayOf(10, 20, 30, 40, 50)
你可以试试这个:
var a = Array<Int>(5){0}