由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?


当前回答

内联typescript解决方案

export const color = (function (colors) {
    const fn = (code: number, str: string) => `\x1b[${code}m${str}\x1b[39m`;
    const obj = { grey: fn.bind(null, 90) };
    for (let i = 0; i < colors.length; i++) obj[colors[i]] = fn.bind(null, 30 + i);
    return obj as { [K in typeof colors[any] | 'grey']: (str: string) => string };
})(['black', 'red', 'green', 'yellow', 'blue', 'magenta', 'cyan', 'white'] as const);

其他回答

var to_rgb = function (_text, _r, _g, _b) {
    return "\x1b[38;2;" + _r + ";" + _g + ";" + _b + "m" + _text + "\x1b[0m";
};

此代码帮助设置前景色:\x1b[38;2;R;G;Bm

这在某些地方可能行不通

我重载了控制台方法。

var colors={
Reset: "\x1b[0m",
Red: "\x1b[31m",
Green: "\x1b[32m",
Yellow: "\x1b[33m"
};

var infoLog = console.info;
var logLog = console.log;
var errorLog = console.error;
var warnLog = console.warn;

console.info= function(args)
{
    var copyArgs = Array.prototype.slice.call(arguments);
    copyArgs.unshift(colors.Green);
    copyArgs.push(colors.Reset);
    infoLog.apply(null,copyArgs);
};

console.warn= function(args)
{
    var copyArgs = Array.prototype.slice.call(arguments);
    copyArgs.unshift(colors.Yellow);
    copyArgs.push(colors.Reset);
    warnLog.apply(null,copyArgs);
};
console.error= function(args)
{
    var copyArgs = Array.prototype.slice.call(arguments);
    copyArgs.unshift(colors.Red);
    copyArgs.push(colors.Reset);
    errorLog.apply(null,copyArgs);
};

// examples
console.info("Numeros",1,2,3);
console.warn("pares",2,4,6);
console.error("reiniciandooo");

输出为。

我创建了自己的模块StyleMe。我这样做,我可以用很少的打字做很多事情。例子:

var StyleMe = require('styleme');
StyleMe.extend() // extend the string prototype

console.log("gre{Hello} blu{world}!".styleMe()) // Logs hello world! with 'hello' being green, and 'world' being blue with '!' being normal.

它也可以被嵌套:

console.log("This is normal red{this is red blu{this is blue} back to red}".styleMe())

或者,如果你不想扩展字符串原型,你可以选择其他3个选项:

console.log(styleme.red("a string"))
console.log("Hello, this is yellow text".yellow().end())
console.log(styleme.style("some text","red,bbl"))

paint-console

简单的可着色原木。支持检查对象和单行更新 这个包只是重新油漆控制台。

安装

npm install paint-console

使用

require('paint-console');

console.info('console.info();');
console.warn('console.warn();');
console.error('console.error();');
console.log('console.log();');

demo

Reset: "\x1b[0m"
Bright: "\x1b[1m"
Dim: "\x1b[2m"
Underscore: "\x1b[4m"
Blink: "\x1b[5m"
Reverse: "\x1b[7m"
Hidden: "\x1b[8m"

FgBlack: "\x1b[30m"
FgRed: "\x1b[31m"
FgGreen: "\x1b[32m"
FgYellow: "\x1b[33m"
FgBlue: "\x1b[34m"
FgMagenta: "\x1b[35m"
FgCyan: "\x1b[36m"
FgWhite: "\x1b[37m"
FgGray: "\x1b[90m"

BgBlack: "\x1b[40m"
BgRed: "\x1b[41m"
BgGreen: "\x1b[42m"
BgYellow: "\x1b[43m"
BgBlue: "\x1b[44m"
BgMagenta: "\x1b[45m"
BgCyan: "\x1b[46m"
BgWhite: "\x1b[47m"
FgGray: "\x1b[100m"

例如,如果你想有一个昏暗的红色文本和蓝色背景,你可以在Javascript中这样做:

console.log("\x1b[2m", "\x1b[31m", "\x1b[44m", "Sample Text", "\x1b[0m");

颜色和效果的顺序似乎不是那么重要,但总是记得在最后重置颜色和效果。