由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?
当前回答
内联typescript解决方案
export const color = (function (colors) {
const fn = (code: number, str: string) => `\x1b[${code}m${str}\x1b[39m`;
const obj = { grey: fn.bind(null, 90) };
for (let i = 0; i < colors.length; i++) obj[colors[i]] = fn.bind(null, 30 + i);
return obj as { [K in typeof colors[any] | 'grey']: (str: string) => string };
})(['black', 'red', 'green', 'yellow', 'blue', 'magenta', 'cyan', 'white'] as const);
其他回答
如果你想改变颜色直接自己没有模块尝试
console.log('\x1b[36m', 'sometext' ,'\x1b[0m');
先\x1b[36m改变颜色为36,然后回到终端颜色0。
下面是ANSI颜色代码列表
node-colorify
提供功能打印文本的颜色,也做文本格式,如粗体,闪烁等。
我发现上面的答案(https://stackoverflow.com/a/41407246/4808079)非常有用,但不完整。如果你只想给某样东西上色一次,我想这没问题,但我认为以可运行的函数形式共享它更适用于现实生活中的用例。
const Color = {
Reset: "\x1b[0m",
Bright: "\x1b[1m",
Dim: "\x1b[2m",
Underscore: "\x1b[4m",
Blink: "\x1b[5m",
Reverse: "\x1b[7m",
Hidden: "\x1b[8m",
FgBlack: "\x1b[30m",
FgRed: "\x1b[31m",
FgGreen: "\x1b[32m",
FgYellow: "\x1b[33m",
FgBlue: "\x1b[34m",
FgMagenta: "\x1b[35m",
FgCyan: "\x1b[36m",
FgWhite: "\x1b[37m",
FgGray: "\x1b[90m",
BgBlack: "\x1b[40m",
BgRed: "\x1b[41m",
BgGreen: "\x1b[42m",
BgYellow: "\x1b[43m",
BgBlue: "\x1b[44m",
BgMagenta: "\x1b[45m",
BgCyan: "\x1b[46m",
BgWhite: "\x1b[47m"
BgGray: "\x1b[100m",
}
function colorString(color, string) {
return `${color}${string}${Color.Reset}`;
}
function colorLog(color, ...args) {
console.log(...args.map(
(it) => typeof it === "string" ? colorString(color, string) : it
));
}
像这样使用它:
colorLog(Color.FgYellow, "Some Yellow text to console log", { someObj: true });
console.log([
colorString(Color.FgRed, "red"),
colorString(Color.FgGreen, "green"),
colorString(Color.FgBlue, "blue"),
].join(", "));
在Node.js中有多个可用于格式化控制台文本的包。最流行的有:
粉笔, cli-color - 颜色- >编辑:颜色不再推荐,因为它有拒绝服务漏洞 详情见:https://snyk.io/blog/open-source-npm-packages-colors-faker/
用法:
粉笔:
const chalk = require('chalk');
console.log(chalk.red('Text in red'));
CLI-COLOR:
const clc = require('cli-color');
console.log(clc.red('Text in red'));
我在我的snippet目录中创建了一个名为styles.js的文件,我认为它可以帮助任何想要导入单个文件的人。
这是对color.js的styles.js文件的一个小修改,帮助了我很多。
以下是该文件的内容:
// Original: https://github.com/Marak/colors.js/blob/master/lib/styles.js
const styleCodes = {
// Reset all styles.
reset: [0, 0],
// Text styles.
bold: [1, 22],
dim: [2, 22],
italic: [3, 23],
underline: [4, 24],
inverse: [7, 27],
hidden: [8, 28],
strikethrough: [9, 29],
// Foregound classic colours.
fgBlack: [30, 39],
fgRed: [31, 39],
fgGreen: [32, 39],
fgYellow: [33, 39],
fgBlue: [34, 39],
fgMagenta: [35, 39],
fgCyan: [36, 39],
fgWhite: [37, 39],
fgGray: [90, 39],
// Foreground bright colours.
fgBrightRed: [91, 39],
fgBrightGreen: [92, 39],
fgBrightYellow: [93, 39],
fgBrightBlue: [94, 39],
fgBrightMagenta: [95, 39],
fgBrightCyan: [96, 39],
fgBrightWhite: [97, 39],
// Background basic colours.
bgBlack: [40, 49],
bgRed: [41, 49],
bgGreen: [42, 49],
bgYellow: [43, 49],
bgBlue: [44, 49],
bgMagenta: [45, 49],
bgCyan: [46, 49],
bgWhite: [47, 49],
bgGray: [100, 49],
bgGrey: [100, 49],
// Background bright colours.
bgBrightRed: [101, 49],
bgBrightGreen: [102, 49],
bgBrightYellow: [103, 49],
bgBrightBlue: [104, 49],
bgBrightMagenta: [105, 49],
bgBrightCyan: [106, 49],
bgBrightWhite: [107, 49],
};
// This object will contain the string representation for all style codes.
const styles = {};
// Loop over all the style codes and assign them to the `styles` object.
//
// The a `styleCode` in the `styleCodes` object consists of two numbers:
// Index 0: The opening style code (In HTML this can be the opening <b> tag).
// Index 1: The closing style code (In HTML this can be the closing </b> tag).
for (let styleCode of Object.keys(styleCodes)) {
styles[styleCode] = {
open: `\x1B[${styleCodes[styleCode][0]}m`,
close: `\x1B[${styleCodes[styleCode][1]}m`,
};
}
module.exports = styles;
其实用起来很简单。
const styles = require("/path/to/styles.js");
// Let's say we've got an error:
const errorOpen = styles.bold.open + styles.bgRed.open + styles.fgWhite.open;
const errorClose = styles.reset.close; // Close everything
console.log(errorOpen, "ERROR", errorClose, ": Missing semicolon at line 9.");
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