由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?


当前回答

我在我的snippet目录中创建了一个名为styles.js的文件,我认为它可以帮助任何想要导入单个文件的人。

这是对color.js的styles.js文件的一个小修改,帮助了我很多。

以下是该文件的内容:

// Original: https://github.com/Marak/colors.js/blob/master/lib/styles.js

const styleCodes = {
    // Reset all styles.
    reset: [0, 0],
    
    // Text styles.
    bold: [1, 22],
    dim: [2, 22],
    italic: [3, 23],
    underline: [4, 24],
    inverse: [7, 27],
    hidden: [8, 28],
    strikethrough: [9, 29],
    
    // Foregound classic colours.
    fgBlack: [30, 39],
    fgRed: [31, 39],
    fgGreen: [32, 39],
    fgYellow: [33, 39],
    fgBlue: [34, 39],
    fgMagenta: [35, 39],
    fgCyan: [36, 39],
    fgWhite: [37, 39],
    fgGray: [90, 39],
    
    // Foreground bright colours.
    fgBrightRed: [91, 39],
    fgBrightGreen: [92, 39],
    fgBrightYellow: [93, 39],
    fgBrightBlue: [94, 39],
    fgBrightMagenta: [95, 39],
    fgBrightCyan: [96, 39],
    fgBrightWhite: [97, 39],

    // Background basic colours.
    bgBlack: [40, 49],
    bgRed: [41, 49],
    bgGreen: [42, 49],
    bgYellow: [43, 49],
    bgBlue: [44, 49],
    bgMagenta: [45, 49],
    bgCyan: [46, 49],
    bgWhite: [47, 49],
    bgGray: [100, 49],
    bgGrey: [100, 49],
    
    // Background bright colours.
    bgBrightRed: [101, 49],
    bgBrightGreen: [102, 49],
    bgBrightYellow: [103, 49],
    bgBrightBlue: [104, 49],
    bgBrightMagenta: [105, 49],
    bgBrightCyan: [106, 49],
    bgBrightWhite: [107, 49],
};

// This object will contain the string representation for all style codes.
const styles = {};

// Loop over all the style codes and assign them to the `styles` object.
// 
// The a `styleCode` in the `styleCodes` object consists of two numbers:
// Index 0: The opening style code (In HTML this can be the opening <b> tag).
// Index 1: The closing style code (In HTML this can be the closing </b> tag).
for (let styleCode of Object.keys(styleCodes)) {
    styles[styleCode] = {
        open: `\x1B[${styleCodes[styleCode][0]}m`,
        close: `\x1B[${styleCodes[styleCode][1]}m`,
    };
}

module.exports = styles;

其实用起来很简单。

const styles = require("/path/to/styles.js");

// Let's say we've got an error:
const errorOpen = styles.bold.open + styles.bgRed.open + styles.fgWhite.open;
const errorClose = styles.reset.close; // Close everything
console.log(errorOpen, "ERROR", errorClose, ": Missing semicolon at line 9.");

其他回答

现在有两种方法来查看Node.js控制台的颜色变化。

一种是通过通用库,这些库可以用颜色标记装饰文本字符串,然后通过标准console.log输出。

今天的顶级图书馆:

粉笔 颜色 cli-color

另一种方法是修补现有的控制台方法。manakin就是这样一个库,它可以让你为所有的控制台方法(log, warn, error和info)自动设置标准颜色。

与通用颜色库的一个显著区别是-它可以全局或局部设置颜色,同时为每个Node.js控制台方法保持一致的语法和输出格式,然后使用这些方法而不必指定颜色,因为它们都是自动设置的。

由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?

针对你的问题,这里有一个最简单的解决方案:

var con = require('manakin').global;
con.log.color = 30; // Use black color for console.log

它将为应用程序中的每个console.log调用设置黑色。查看更多颜色代码。

manakin使用的默认颜色:

var colorSet = {
    Reset: "\x1b[0m",
    Red: "\x1b[31m",
    Green: "\x1b[32m",
    Yellow: "\x1b[33m",
    Blue: "\x1b[34m",
    Magenta: "\x1b[35m"
};

var funcNames = ["info", "log", "warn", "error"];
var colors = [colorSet.Green, colorSet.Blue, colorSet.Yellow, colorSet.Red];

for (var i = 0; i < funcNames.length; i++) {
    let funcName = funcNames[i];
    let color = colors[i];
    let oldFunc = console[funcName];
    console[funcName] = function () {
        var args = Array.prototype.slice.call(arguments);
        if (args.length) {
            args = [color + args[0]].concat(args.slice(1), colorSet.Reset);
        }
        oldFunc.apply(null, args);
    };
}

// Test:
console.info("Info is green.");
console.log("Log is blue.");
console.warn("Warn is orange.");
console.error("Error is red.");
console.info("--------------------");
console.info("Formatting works as well. The number = %d", 123);

最小的别名:

{
  const f = (color) => (...args) => {
    for (const x of [color, ...args, "\33[0m"]) console.log(x);
  };

  Object.assign(console, {
    black: f("\33[30m"),
    red: f("\33[31m"),
    green: f("\33[32m"),
    yellow: f("\33[33m"),
    blue: f("\33[34m"),
    magenta: f("\33[35m"),
    cyan: f("\33[36m"),
    white: f("\33[37m"),
  });
}

// Usage
console.blue("Blue world");

node-colorify

提供功能打印文本的颜色,也做文本格式,如粗体,闪烁等。

我发现上面的答案(https://stackoverflow.com/a/41407246/4808079)非常有用,但不完整。如果你只想给某样东西上色一次,我想这没问题,但我认为以可运行的函数形式共享它更适用于现实生活中的用例。

const Color = {
  Reset: "\x1b[0m",
  Bright: "\x1b[1m",
  Dim: "\x1b[2m",
  Underscore: "\x1b[4m",
  Blink: "\x1b[5m",
  Reverse: "\x1b[7m",
  Hidden: "\x1b[8m",
  
  FgBlack: "\x1b[30m",
  FgRed: "\x1b[31m",
  FgGreen: "\x1b[32m",
  FgYellow: "\x1b[33m",
  FgBlue: "\x1b[34m",
  FgMagenta: "\x1b[35m",
  FgCyan: "\x1b[36m",
  FgWhite: "\x1b[37m",
  FgGray: "\x1b[90m",
  
  BgBlack: "\x1b[40m",
  BgRed: "\x1b[41m",
  BgGreen: "\x1b[42m",
  BgYellow: "\x1b[43m",
  BgBlue: "\x1b[44m",
  BgMagenta: "\x1b[45m",
  BgCyan: "\x1b[46m",
  BgWhite: "\x1b[47m"
  BgGray: "\x1b[100m",
}

function colorString(color, string) {
  return `${color}${string}${Color.Reset}`;
}

function colorLog(color, ...args) {
  console.log(...args.map(
   (it) => typeof it === "string" ? colorString(color, string) : it
  ));
}

像这样使用它:

colorLog(Color.FgYellow, "Some Yellow text to console log", { someObj: true });

console.log([
  colorString(Color.FgRed, "red"),
  colorString(Color.FgGreen, "green"),
  colorString(Color.FgBlue, "blue"),
].join(", "));