由于眼睛的问题,我不得不将控制台背景色改为白色,但字体是灰色的,它使消息无法阅读。我怎样才能改变呢?


当前回答

var to_rgb = function (_text, _r, _g, _b) {
    return "\x1b[38;2;" + _r + ";" + _g + ";" + _b + "m" + _text + "\x1b[0m";
};

此代码帮助设置前景色:\x1b[38;2;R;G;Bm

这在某些地方可能行不通

其他回答

另一种方法是使用一个简单的ANSI代码生成器。

您不需要安装软件包 不需要搜索颜色代码,只需点击按钮

GIF演示

你可以在https://console-colors.vercel.app/上使用它

公共存储库:https://github.com/alecshoppe/console-colors

这在一定程度上取决于你所在的平台。最常见的方式 要做到这一点,需要打印ANSI转义序列。举个简单的例子, 下面是blender构建脚本中的一些python代码:

// This is a object for use ANSI escape to color the text in the terminal
const bColors = {
    HEADER    : '\033[95m',
    OKBLUE    : '\033[94m',
    OKGREEN   : '\033[92m',
    WARNING   : '\033[93m',
    FAIL      : '\033[91m',
    ENDC      : '\033[0m', 
    BOLD      : '\033[1m',   
    UNDERLINE : '\033[4m'
}

要使用这样的代码,可以执行如下操作

console.log(`${bColors.WARNING} My name is sami ${bColors.ENDC}`)

我不想要任何依赖于此,只有这些在OS x上为我工作。所有其他示例从这里的答案给了我八进制文字错误。

Reset = "\x1b[0m"
Bright = "\x1b[1m"
Dim = "\x1b[2m"
Underscore = "\x1b[4m"
Blink = "\x1b[5m"
Reverse = "\x1b[7m"
Hidden = "\x1b[8m"

FgBlack = "\x1b[30m"
FgRed = "\x1b[31m"
FgGreen = "\x1b[32m"
FgYellow = "\x1b[33m"
FgBlue = "\x1b[34m"
FgMagenta = "\x1b[35m"
FgCyan = "\x1b[36m"
FgWhite = "\x1b[37m"
FgGray = "\x1b[90m"

BgBlack = "\x1b[40m"
BgRed = "\x1b[41m"
BgGreen = "\x1b[42m"
BgYellow = "\x1b[43m"
BgBlue = "\x1b[44m"
BgMagenta = "\x1b[45m"
BgCyan = "\x1b[46m"
BgWhite = "\x1b[47m"
BgGray = "\x1b[100m"

来源:https://coderwall.com/p/yphywg/printing-colorful-text-in-terminal-when-run-node-js-script

对于一个不影响String对象的内置方法的流行替代颜色,我推荐使用cli-color。

包括颜色和可链接样式,如粗体、斜体和下划线。

有关此类别中各个模块的比较,请参见这里。

var colorSet = {
    Reset: "\x1b[0m",
    Red: "\x1b[31m",
    Green: "\x1b[32m",
    Yellow: "\x1b[33m",
    Blue: "\x1b[34m",
    Magenta: "\x1b[35m"
};

var funcNames = ["info", "log", "warn", "error"];
var colors = [colorSet.Green, colorSet.Blue, colorSet.Yellow, colorSet.Red];

for (var i = 0; i < funcNames.length; i++) {
    let funcName = funcNames[i];
    let color = colors[i];
    let oldFunc = console[funcName];
    console[funcName] = function () {
        var args = Array.prototype.slice.call(arguments);
        if (args.length) {
            args = [color + args[0]].concat(args.slice(1), colorSet.Reset);
        }
        oldFunc.apply(null, args);
    };
}

// Test:
console.info("Info is green.");
console.log("Log is blue.");
console.warn("Warn is orange.");
console.error("Error is red.");
console.info("--------------------");
console.info("Formatting works as well. The number = %d", 123);