反应

onKeyPress(event) { 
        let self = this;
        self.setState({
            capsLock: isCapsLockOn(self, event)
        });
    }

    onKeyUp(event) { 
        let self = this;
        let key = event.key;
        if( key === 'Shift') {
            self.shift = false;
        }
    }

    <div>
     <input name={this.props.name} onKeyDown={(e)=>this.onKeyPress(e)} onKeyUp={(e)=>this.onKeyUp(e)} onChange={this.props.onChange}/>
                {this.capsLockAlert()}
</div>

function isCapsLockOn(component, event) {
        let key = event.key;
        let keyCode = event.keyCode;

        component.lastKeyPressed = key;

        if( key === 'Shift') {
            component.shift = true;
        } 

        if (key === 'CapsLock') {
            let newCapsLockState = !component.state.capsLock;
            component.caps = newCapsLockState;
            return newCapsLockState;
        } else {
            if ((component.lastKeyPressed !== 'Shift' && (key === key.toUpperCase() && (keyCode >= 65 && keyCode <= 90)) && !component.shift) || component.caps ) {
                component.caps = true;
                return true;
            } else {
                component.caps = false;
                return false;
            }
        }
    }

你可以试试。增加了一个工作示例。当焦点在输入上时，打开caps lock使led变成红色或绿色。(还没有在mac/linux上测试)

注意:两个版本都适用于我。感谢您在评论中提出建设性意见。

旧版本:https://jsbin.com/mahenes/edit?js,output

另外，这是一个修改后的版本(有人能在mac上测试并确认吗)

新版本:https://jsbin.com/xiconuv/edit?js,output

新版本:

function isCapslock(e) {
  const IS_MAC = /Mac/.test(navigator.platform);

  const charCode = e.charCode;
  const shiftKey = e.shiftKey;

  if (charCode >= 97 && charCode <= 122) {
    capsLock = shiftKey;
  } else if (charCode >= 65 && charCode <= 90
    && !(shiftKey && IS_MAC)) {
    capsLock = !shiftKey;
  }

  return capsLock;
}

旧版本:

function isCapslock(e) {
  e = (e) ? e : window.event;

  var charCode = false;
  if (e.which) {
    charCode = e.which;
  } else if (e.keyCode) {
    charCode = e.keyCode;
  }

  var shifton = false;
  if (e.shiftKey) {
    shifton = e.shiftKey;
  } else if (e.modifiers) {
    shifton = !!(e.modifiers & 4);
  }

  if (charCode >= 97 && charCode <= 122 && shifton) {
    return true;
  }

  if (charCode >= 65 && charCode <= 90 && !shifton) {
    return true;
  }

  return false;
}

对于国际字符，可以根据需要为以下键添加额外的检查。你必须获得你感兴趣的字符的键码范围，可能是通过使用一个键映射数组，它将保存你正在寻址的所有有效用例键…

大写字母A-Z或'Ä'， 'Ö'， 'Ü'， 小写字母a-Z或0-9或'ä'， 'ö'， 'ü'

上面的键只是示例表示。

显示大写锁定状态的变量:

let isCapsLockOn = false;

document.addEventListener( 'keydown', function( event ) {
  var caps = event.getModifierState && event.getModifierState( 'CapsLock' );
  if(isCapsLockOn !== caps) isCapsLockOn = caps;
});

document.addEventListener( 'keyup', function( event ) {
  var caps = event.getModifierState && event.getModifierState( 'CapsLock' );
  if(isCapsLockOn !== caps) isCapsLockOn = caps;
});

适用于所有浏览器=> canIUse

还有另一个版本，清晰而简单，处理移位的capsLock，并且不受ascii限制，我认为:

document.onkeypress = function (e)
{
    e = e || window.event;
    if (e.charCode === 0 || e.ctrlKey || document.onkeypress.punctuation.indexOf(e.charCode) >= 0)
        return;
    var s = String.fromCharCode(e.charCode); // or e.keyCode for compatibility, but then have to handle MORE non-character keys
    var s2 = e.shiftKey ? s.toUpperCase() : s.toLowerCase();
    var capsLockOn = (s2 !== s);
    document.getElementById('capslockWarning').style.display = capsLockOn ? '' : 'none';
}
document.onkeypress.punctuation = [33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,91,92,93,94,95,96,123,124,125,126];

编辑:意义上的capsLockOn被逆转，多，固定。

编辑#2:在进一步检查之后，我做了一些更改，不幸的是，代码更详细了一些，但它可以适当地处理更多的操作。

Using e.charCode instead of e.keyCode and checking for 0 values skips a lot of non-character keypresses, without coding anything specific to a given language or charset. From my understanding, it's slightly less compatible, so older, non-mainstream, or mobile browsers may not behave as this code expects, but it's worth it, for my situation anyway. Checking against a list of known punctuation codes prevents them from being seen as false negatives, since they're not affected by caps lock. Without this, the caps lock indicator gets hidden when you type any of those punctuation characters. By specifying an excluded set, rather than an included one, it should be more compatible with extended characters. This is the ugliest, special-casiest bit, and there's some chance that non-Western languages have different enough punctuation and/or punctuation codes to be a problem, but again it's worth it IMO, at least for my situation.

Javascript代码

<script type="text/javascript">
   function isCapLockOn(e){
   kc = e.keyCode?e.keyCode:e.which;
   sk = e.shiftKey?e.shiftKey:((kc == 16)?true:false);
   if(((kc >= 65 && kc <= 90) && !sk)||((kc >= 97 && kc <= 122) && sk))
       document.getElementById('alert').style.visibility = 'visible';
   else
       document.getElementById('alert').style.visibility = 'hidden';
   }
</script>

现在我们需要使用Html来关联这个脚本

<input type="password" name="txtPassword" onkeypress="isCapLockOn(event)" />
<div id="alert" style="visibility:hidden">Caps Lock is on.</div> 

jQuery:

$('some_element').keypress(function(e){
       if(e.keyCode == 20){
             //caps lock was pressed
       }
});

这个jQuery插件(代码)实现了与Rajesh的回答相同的想法，更简洁一点。