如何在node.js上移动文件(如mv命令shell) ?是否有任何方法,或者我应该读取一个文件,写到一个新文件,并删除旧文件?


当前回答

我将把所有涉及的函数(即重命名,复制,断开链接)彼此分离,以获得灵活性,并承诺一切,当然:

const renameFile = (path, newPath) => 
  new Promise((res, rej) => {
    fs.rename(path, newPath, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const copyFile = (path, newPath, flags) =>
  new Promise((res, rej) => {
    const readStream = fs.createReadStream(path),
      writeStream = fs.createWriteStream(newPath, {flags});

    readStream.on("error", rej);
    writeStream.on("error", rej);
    writeStream.on("finish", res);
    readStream.pipe(writeStream);
  });

const unlinkFile = path => 
  new Promise((res, rej) => {
    fs.unlink(path, (err, data) =>
      err
        ? rej(err)
        : res(data));
  });

const moveFile = (path, newPath, flags) =>
  renameFile(path, newPath)
    .catch(e => {
      if (e.code !== "EXDEV")
        throw new e;

      else
        return copyFile(path, newPath, flags)
          .then(() => unlinkFile(path));
    });

moveFile只是一个方便的函数,我们可以分别应用这些函数,例如,当我们需要更细粒度的异常处理时。

其他回答

如果您试图移动或重命名一个node.js源文件,请尝试https://github.com/viruschidai/node-mv。它将更新所有其他文件中对该文件的引用。

在下面URL的帮助下,您可以复制或移动您的文件CURRENT Source到Destination Source

https://coursesweb.net/nodejs/move-copy-file

/*********Moves the $file to $dir2 Start *********/ var moveFile = (file, dir2)=>{ //include the fs, path modules var fs = require('fs'); var path = require('path'); //gets file name and adds it to dir2 var f = path.basename(file); var dest = path.resolve(dir2, f); fs.rename(file, dest, (err)=>{ if(err) throw err; else console.log('Successfully moved'); }); }; //move file1.htm from 'test/' to 'test/dir_1/' moveFile('./test/file1.htm', './test/dir_1/'); /*********Moves the $file to $dir2 END *********/ /*********copy the $file to $dir2 Start *********/ var copyFile = (file, dir2)=>{ //include the fs, path modules var fs = require('fs'); var path = require('path'); //gets file name and adds it to dir2 var f = path.basename(file); var source = fs.createReadStream(file); var dest = fs.createWriteStream(path.resolve(dir2, f)); source.pipe(dest); source.on('end', function() { console.log('Succesfully copied'); }); source.on('error', function(err) { console.log(err); }); }; //example, copy file1.htm from 'test/dir_1/' to 'test/' copyFile('./test/dir_1/file1.htm', './test/'); /*********copy the $file to $dir2 END *********/

下面是一个使用util的例子。我如何移动文件a到不同的分区或设备在Node.js?

var fs = require('fs'),
    util = require('util');

var is = fs.createReadStream('source_file')
var os = fs.createWriteStream('destination_file');

util.pump(is, os, function() {
    fs.unlinkSync('source_file');
});

本地使用nodejs

var fs = require('fs')

var oldPath = 'old/path/file.txt'
var newPath = 'new/path/file.txt'

fs.rename(oldPath, newPath, function (err) {
  if (err) throw err
  console.log('Successfully renamed - AKA moved!')
})

(注意:“如果您正在跨分区或使用不支持移动文件的虚拟文件系统,这将不起作用。[…——Flavien Volken 15年9月2日12:50)

根据seppo0010的注释,我使用了重命名函数来完成此操作。

http://nodejs.org/docs/latest/api/fs.html#fs_fs_rename_oldpath_newpath_callback

fs。重命名(oldPath, newPath, callback) 新增于:v0.0.2 oldPath <String> | <Buffer> newPath <String> | <Buffer> . newPath <String> 回调函数> < 异步重命名(2)。除了可能的异常,没有参数 赋给完成回调函数。