在PHP中找出一个数字/变量是奇数还是偶数的最简单最基本的方法是什么? 这和mod有关吗?
我试过一些剧本,但是…谷歌目前没有发送。
在PHP中找出一个数字/变量是奇数还是偶数的最简单最基本的方法是什么? 这和mod有关吗?
我试过一些剧本,但是…谷歌目前没有发送。
当前回答
$before = microtime(true);
$n = 1000;
$numbers = range(1,$n);
$cube_numbers = array_map('cube',$numbers);
function cube($n){
$msg ='even';
if($n%2 !=0){
$msg = 'odd';
}
return "The Number is $n is ".$msg;
}
foreach($cube_numbers as $cube){
echo $cube . "<br/>";
}
$after = microtime(true);
echo $after-$before. 'seconds';
其他回答
虽然所有的答案都是正确的,但简单的解决方法是:
$check = 9;
:
echo ($check & 1 ? 'Odd' : 'Even');
or:
echo ($check % 2 ? 'Odd' : 'Even');
工作得很好。
(bool)($number & 1)
or
(bool)(~ $number & 1)
我做了一些测试,发现在mod, is_int和&-操作符之间,mod是最快的,紧随其后的是&-操作符。 Is_int几乎比mod慢4倍。
I used the following code for testing purposes: $number = 13; $before = microtime(true); for ($i=0; $i<100000; $i++) { $test = ($number%2?true:false); } $after = microtime(true); echo $after-$before." seconds mod<br>"; $before = microtime(true); for ($i=0; $i<100000; $i++) { $test = (!is_int($number/2)?true:false); } $after = microtime(true); echo $after-$before." seconds is_int<br>"; $before = microtime(true); for ($i=0; $i<100000; $i++) { $test = ($number&1?true:false); } $after = microtime(true); echo $after-$before." seconds & operator<br>"; The results I got were pretty consistent. Here's a sample: 0.041879177093506 seconds mod 0.15969395637512 seconds is_int 0.044223070144653 seconds & operator
试试这个带有#Input字段的
<?php
//checking even and odd
echo '<form action="" method="post">';
echo "<input type='text' name='num'>\n";
echo "<button type='submit' name='submit'>Check</button>\n";
echo "</form>";
$num = 0;
if ($_SERVER["REQUEST_METHOD"] == "POST") {
if (empty($_POST["num"])) {
$numErr = "<span style ='color: red;'>Number is required.</span>";
echo $numErr;
die();
} else {
$num = $_POST["num"];
}
$even = ($num % 2 == 0);
$odd = ($num % 2 != 0);
if ($num > 0){
if($even){
echo "Number is even.";
} else {
echo "Number is odd.";
}
} else {
echo "Not a number.";
}
}
?>
<?php
// Recursive function to check whether
// the number is Even or Odd
function check($number){
if($number == 0)
return 1;
else if($number == 1)
return 0;
else if($number<0)
return check(-$number);
else
return check($number-2);
}
// Check the number odd or even
$number = 35;
if(check($number))
echo "Even";
else
echo "Odd";
?>
因此,输出将是Odd