onLogout () { this.props.history.push(' /登录');//发送用户到登录页面 window.location.reload ();//刷新页面 ｝

对我来说，一个快速而简单的选择是使用还原复位。这是简单的，也有一些高级选项，为较大的应用程序。

在创建存储区中设置

import reduxReset from 'redux-reset'
// ...
const enHanceCreateStore = compose(
    applyMiddleware(...),
    reduxReset()  // Will use 'RESET' as default action.type to trigger reset
)(createStore)
const store = enHanceCreateStore(reducers)

在注销函数中调度您的“重置”

store.dispatch({
    type: 'RESET'
})

npm install redux-reset
import reduxReset from 'redux-reset'
...
const enHanceCreateStore = compose(
    applyMiddleware(...),
    reduxReset()  // Will use 'RESET' as default action.type to trigger reset
  )(createStore)
const store = enHanceCreateStore(reducers)

https://github.com/wwayne/redux-reset

对我来说，最好的工作是设置initialState而不是state:

  const reducer = createReducer(initialState,
  on(proofActions.cleanAdditionalInsuredState, (state, action) => ({
    ...initialState
  })),

我已经创建了清除状态的操作。因此，当我分派登出动作创建者时，我也分派动作来清除状态。

用户记录动作

export const clearUserRecord = () => ({
  type: CLEAR_USER_RECORD
});

注销操作创建器

export const logoutUser = () => {
  return dispatch => {
    dispatch(requestLogout())
    dispatch(receiveLogout())
    localStorage.removeItem('auth_token')
    dispatch({ type: 'CLEAR_USER_RECORD' })
  }
};

减速机

const userRecords = (state = {isFetching: false,
  userRecord: [], message: ''}, action) => {
  switch (action.type) {
    case REQUEST_USER_RECORD:
    return { ...state,
      isFetching: true}
    case RECEIVE_USER_RECORD:
    return { ...state,
      isFetching: false,
      userRecord: action.user_record}
    case USER_RECORD_ERROR:
    return { ...state,
      isFetching: false,
      message: action.message}
    case CLEAR_USER_RECORD:
    return {...state,
      isFetching: false,
      message: '',
      userRecord: []}
    default:
      return state
  }
};

我不确定这是否是最佳的?

只需将注销链接清除会话并刷新页面。您的商店不需要额外的代码。当您想要完全重置状态时，页面刷新是一种简单且易于重复的处理方法。