下面的异常是什么意思;我该怎么解决呢?
这是代码:
Toast toast = Toast.makeText(mContext, "Something", Toast.LENGTH_SHORT);
这是例外:
java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
at android.os.Handler.<init>(Handler.java:121)
at android.widget.Toast.<init>(Toast.java:68)
at android.widget.Toast.makeText(Toast.java:231)
当前回答
Toast.makeText()只能从Main/UI线程调用。loop . getmainlooper()帮助你实现它:
JAVA
new Handler(Looper.getMainLooper()).post(new Runnable() {
@Override
public void run() {
// write your code here
}
});
科特林
Handler(Looper.getMainLooper()).post {
// write your code here
}
这种方法的优点是您可以在没有活动或上下文的情况下运行UI代码。
其他回答
这是因为Toast.makeText()是从工作线程调用的。它应该像这样从主UI线程调用
runOnUiThread(new Runnable() {
public void run() {
Toast toast = Toast.makeText(mContext, "Something", Toast.LENGTH_SHORT);
}
});
Handler handler2;
HandlerThread handlerThread=new HandlerThread("second_thread");
handlerThread.start();
handler2=new Handler(handlerThread.getLooper());
现在handler2将使用一个不同于主线程的线程来处理消息。
要在线程中显示对话框或烤面包机，最简洁的方法是使用Activity对象。
例如:
new Thread(new Runnable() {
@Override
public void run() {
myActivity.runOnUiThread(new Runnable() {
public void run() {
myActivity.this.processingWaitDialog = new ProgressDialog(myActivity.this.getContext());
myActivity.this.processingWaitDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);
myActivity.this.processingWaitDialog.setMessage("abc");
myActivity.this.processingWaitDialog.setIndeterminate(true);
myActivity.this.processingWaitDialog.show();
}
});
expenseClassify.serverPost(
new AsyncOperationCallback() {
public void operationCompleted(Object sender) {
myActivity.runOnUiThread(new Runnable() {
public void run() {
if (myActivity.this.processingWaitDialog != null
&& myActivity.this.processingWaitDialog.isShowing()) {
myActivity.this.processingWaitDialog.dismiss();
myActivity.this.processingWaitDialog = null;
}
}
}); // .runOnUiThread(new Runnable()
...
在线程外部创建处理器
final Handler handler = new Handler();
new Thread(new Runnable() {
@Override
public void run() {
try{
handler.post(new Runnable() {
@Override
public void run() {
showAlertDialog(p.getProviderName(), Token, p.getProviderId(), Amount);
}
});
}
}
catch (Exception e){
Log.d("ProvidersNullExp", e.getMessage());
}
}
}).start();
我也遇到了同样的问题，下面是我的解决方法:
private final class UIHandler extends Handler
{
public static final int DISPLAY_UI_TOAST = 0;
public static final int DISPLAY_UI_DIALOG = 1;
public UIHandler(Looper looper)
{
super(looper);
}
@Override
public void handleMessage(Message msg)
{
switch(msg.what)
{
case UIHandler.DISPLAY_UI_TOAST:
{
Context context = getApplicationContext();
Toast t = Toast.makeText(context, (String)msg.obj, Toast.LENGTH_LONG);
t.show();
}
case UIHandler.DISPLAY_UI_DIALOG:
//TBD
default:
break;
}
}
}
protected void handleUIRequest(String message)
{
Message msg = uiHandler.obtainMessage(UIHandler.DISPLAY_UI_TOAST);
msg.obj = message;
uiHandler.sendMessage(msg);
}
要创建UIHandler，你需要执行以下操作:
HandlerThread uiThread = new HandlerThread("UIHandler");
uiThread.start();
uiHandler = new UIHandler((HandlerThread) uiThread.getLooper());
希望这能有所帮助。
