我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
其他回答
当处理多个分区和/或筛选索引时,Marc_s的答案给出了错误的结果。它也不区分数据和索引的大小,这通常是非常相关的。一些建议的修复方法并不能解决核心问题,或者根本就是错误的。
以下查询解决了所有这些问题。
SELECT
[object_id] = t.[object_id]
,[schema_name] = s.[name]
,[table_name] = t.[name]
,[index_name] = CASE WHEN i.[type] in (0,1,5) THEN null ELSE i.[name] END -- 0=Heap; 1=Clustered; 5=Clustered Columnstore
,[object_type] = CASE WHEN i.[type] in (0,1,5) THEN 'TABLE' ELSE 'INDEX' END
,[index_type] = i.[type_desc]
,[partition_count] = p.partition_count
,[row_count] = p.[rows]
,[data_compression] = CASE WHEN p.data_compression_cnt > 1 THEN 'Mixed'
ELSE ( SELECT DISTINCT p.data_compression_desc
FROM sys.partitions p
WHERE i.[object_id] = p.[object_id] AND i.index_id = p.index_id
)
END
,[total_space_MB] = cast(round(( au.total_pages * (8/1024.00)), 2) AS DECIMAL(36,2))
,[used_space_MB] = cast(round(( au.used_pages * (8/1024.00)), 2) AS DECIMAL(36,2))
,[unused_space_MB] = cast(round(((au.total_pages - au.used_pages) * (8/1024.00)), 2) AS DECIMAL(36,2))
FROM sys.schemas s
JOIN sys.tables t ON s.schema_id = t.schema_id
JOIN sys.indexes i ON t.object_id = i.object_id
JOIN (
SELECT [object_id], index_id, partition_count=count(*), [rows]=sum([rows]), data_compression_cnt=count(distinct [data_compression])
FROM sys.partitions
GROUP BY [object_id], [index_id]
) p ON i.[object_id] = p.[object_id] AND i.[index_id] = p.[index_id]
JOIN (
SELECT p.[object_id], p.[index_id], total_pages = sum(a.total_pages), used_pages = sum(a.used_pages), data_pages=sum(a.data_pages)
FROM sys.partitions p
JOIN sys.allocation_units a ON p.[partition_id] = a.[container_id]
GROUP BY p.[object_id], p.[index_id]
) au ON i.[object_id] = au.[object_id] AND i.[index_id] = au.[index_id]
WHERE t.is_ms_shipped = 0 -- Not a system table
作为marc_s答案(已被接受的答案)的一个简单扩展,它被调整为返回列计数并允许过滤:
SELECT *
FROM
(
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
COUNT(DISTINCT c.COLUMN_NAME) as ColumnCount,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
(SUM(a.used_pages) * 8) AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
INNER JOIN
INFORMATION_SCHEMA.COLUMNS c ON t.NAME = c.TABLE_NAME
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
) AS Result
WHERE
RowCounts > 1000
AND ColumnCount > 10
ORDER BY
UsedSpaceKB DESC
从使用OSQL的命令提示符:
OSQL -E -d <*databasename*> -Q "exec sp_msforeachtable 'sp_spaceused [?]'" > result.txt
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
CAST(ROUND(((SUM(a.total_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS TotalSpaceMB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
CAST(ROUND(((SUM(a.used_pages) * 8) / 1024.00), 2) AS NUMERIC(36, 2)) AS UsedSpaceMB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB,
CAST(ROUND(((SUM(a.total_pages) - SUM(a.used_pages)) * 8) / 1024.00, 2) AS NUMERIC(36, 2)) AS UnusedSpaceMB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
TotalSpaceMB DESC, t.Name
如果您只关心数据库中的空浪费空间,而不关心单个表,则可以考虑以下问题:
如果数据库经历了大量的数据插入和删除,可能与ETL情况类似,这将导致数据库中有太多未使用的空间,因为文件组会自动增长,但不会自动收缩。
您可以通过使用数据库的财产页面来查看是否是这种情况。您可以收缩(右键单击数据库>任务>收缩)并收回一些空间。但是,如果根本原因仍然存在,则数据库将增长(并花费额外的时间尝试增长,直到增长到足够的速度,所以不要这样做)