我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
我继承了一个相当大的SQL Server数据库。考虑到它包含的数据,它似乎比我预期的要占用更多的空间。
是否有一种简单的方法来确定每个表占用的磁盘空间?
当前回答
我发现这个查询很容易使用和快速。
select schema_name(tab.schema_id) + '.' + tab.name as [table],
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind
on tab.object_id = ind.object_id
inner join sys.partitions (nolock) part
on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + '.' + tab.name
order by sum(spc.used_pages) desc
其他回答
这将为您提供每个表的大小和记录计数。
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
GO
-- Get a list of tables and their sizes on disk
ALTER PROCEDURE [dbo].[sp_Table_Sizes]
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
SET NOCOUNT ON;
DECLARE @table_name VARCHAR(500)
DECLARE @schema_name VARCHAR(500)
DECLARE @tab1 TABLE(
tablename VARCHAR (500) collate database_default
,schemaname VARCHAR(500) collate database_default
)
CREATE TABLE #temp_Table (
tablename sysname
,row_count INT
,reserved VARCHAR(50) collate database_default
,data VARCHAR(50) collate database_default
,index_size VARCHAR(50) collate database_default
,unused VARCHAR(50) collate database_default
)
INSERT INTO @tab1
SELECT Table_Name, Table_Schema
FROM information_schema.tables
WHERE TABLE_TYPE = 'BASE TABLE'
DECLARE c1 CURSOR FOR
SELECT Table_Schema + '.' + Table_Name
FROM information_schema.tables t1
WHERE TABLE_TYPE = 'BASE TABLE'
OPEN c1
FETCH NEXT FROM c1 INTO @table_name
WHILE @@FETCH_STATUS = 0
BEGIN
SET @table_name = REPLACE(@table_name, '[','');
SET @table_name = REPLACE(@table_name, ']','');
-- make sure the object exists before calling sp_spacedused
IF EXISTS(SELECT id FROM sysobjects WHERE id = OBJECT_ID(@table_name))
BEGIN
INSERT INTO #temp_Table EXEC sp_spaceused @table_name, false;
END
FETCH NEXT FROM c1 INTO @table_name
END
CLOSE c1
DEALLOCATE c1
SELECT t1.*
,t2.schemaname
FROM #temp_Table t1
INNER JOIN @tab1 t2 ON (t1.tablename = t2.tablename )
ORDER BY schemaname,t1.tablename;
DROP TABLE #temp_Table
END
与Marc_s的回答有一点不同,因为我经常回到这一页,按大多数第一行排序:
SELECT
t.NAME AS TableName,
s.Name AS SchemaName,
p.rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN
sys.indexes i ON t.OBJECT_ID = i.object_id
INNER JOIN
sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id
INNER JOIN
sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN
sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.NAME NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.OBJECT_ID > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
--p.rows DESC --Uncomment to order by amount rows instead of size in KB.
SUM(a.total_pages) DESC
exec sp_spaceused N'dbo.MyTable'
对于所有表,请使用。。(根据保罗的评论补充)
exec sp_MSForEachTable 'exec sp_spaceused [?]'
我发现这个查询很容易使用和快速。
select schema_name(tab.schema_id) + '.' + tab.name as [table],
cast(sum(spc.used_pages * 8)/1024.00 as numeric(36, 2)) as used_mb,
cast(sum(spc.total_pages * 8)/1024.00 as numeric(36, 2)) as allocated_mb
from sys.tables (nolock) tab
inner join sys.indexes (nolock) ind
on tab.object_id = ind.object_id
inner join sys.partitions (nolock) part
on ind.object_id = part.object_id and ind.index_id = part.index_id
inner join sys.allocation_units (nolock) spc
on part.partition_id = spc.container_id
group by schema_name(tab.schema_id) + '.' + tab.name
order by sum(spc.used_pages) desc
sp_spaceused可以获取表、索引视图或整个数据库使用的磁盘空间的信息。
例如:
USE MyDatabase; GO
EXEC sp_spaceused N'User.ContactInfo'; GO
这将报告ContactInfo表的磁盘使用情况信息。
要同时对所有表使用此选项:
USE MyDatabase; GO
sp_msforeachtable 'EXEC sp_spaceused [?]' GO
您还可以从SQL Server的右键单击“标准报告”功能中获取磁盘使用情况。要获取此报告,请从对象资源管理器中的服务器对象导航,向下移动到数据库对象,然后右键单击任何数据库。从出现的菜单中,选择“报告”,然后选择“标准报告”,再选择“磁盘分区使用情况:[DatabaseName]”。