我有一个Python datetime对象，我想将其转换为unix时间，或自1970 epoch以来的秒/毫秒。
我怎么做呢?
当前回答
import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000
其他回答
你可以用德罗宁去时空旅行!
import datetime
import delorean
dt = datetime.datetime.utcnow()
delorean.Delorean(dt, timezone="UTC").epoch
http://delorean.readthedocs.org/en/latest/quickstart.html
>>> import datetime
>>> # replace datetime.datetime.now() with your datetime object
>>> int(datetime.datetime.now().strftime("%s")) * 1000
1312908481000
或者时间模块的帮助(没有日期格式):
>>> import datetime, time
>>> # replace datetime.datetime.now() with your datetime object
>>> time.mktime(datetime.datetime.now().timetuple()) * 1000
1312908681000.0
得到了来自:http://pleac.sourceforge.net/pleac_python/datesandtimes.html的帮助
文档:
time.mktime datetime.timetuple
我是这样做的:
from datetime import datetime
from time import mktime
dt = datetime.now()
sec_since_epoch = mktime(dt.timetuple()) + dt.microsecond/1000000.0
millis_since_epoch = sec_since_epoch * 1000
import time
seconds_since_epoch = time.mktime(your_datetime.timetuple()) * 1000
很多答案在python2中不起作用，或者没有从datetime中保存毫秒。这对我很有用
def datetime_to_ms_epoch(dt):
microseconds = time.mktime(dt.timetuple()) * 1000000 + dt.microsecond
return int(round(microseconds / float(1000)))
