我有一个Python datetime对象,我想将其转换为unix时间,或自1970 epoch以来的秒/毫秒。
我怎么做呢?
我有一个Python datetime对象,我想将其转换为unix时间,或自1970 epoch以来的秒/毫秒。
我怎么做呢?
当前回答
from datetime import datetime
from calendar import timegm
# Note: if you pass in a naive dttm object it's assumed to already be in UTC
def unix_time(dttm=None):
if dttm is None:
dttm = datetime.utcnow()
return timegm(dttm.utctimetuple())
print "Unix time now: %d" % unix_time()
print "Unix timestamp from an existing dttm: %d" % unix_time(datetime(2014, 12, 30, 12, 0))
其他回答
在我看来,最简单的方法是
import datetime
epoch = datetime.datetime.utcfromtimestamp(0)
def unix_time_millis(dt):
return (dt - epoch).total_seconds() * 1000.0
下面是一个基于上面答案的函数
def getDateToEpoch(myDateTime):
res = (datetime.datetime(myDateTime.year,myDateTime.month,myDateTime.day,myDateTime.hour,myDateTime.minute,myDateTime.second) - datetime.datetime(1970,1,1)).total_seconds()
return res
你可以像这样包装返回值: 返回不带十进制值的字符串或只是int(不带str)
很多答案在python2中不起作用,或者没有从datetime中保存毫秒。这对我很有用
def datetime_to_ms_epoch(dt):
microseconds = time.mktime(dt.timetuple()) * 1000000 + dt.microsecond
return int(round(microseconds / float(1000)))
一段熊猫代码:
import pandas
def to_millis(dt):
return int(pandas.to_datetime(dt).value / 1000000)
这是另一种形式的解决方案与规范化的时间对象:
def to_unix_time(timestamp):
epoch = datetime.datetime.utcfromtimestamp(0) # start of epoch time
my_time = datetime.datetime.strptime(timestamp, "%Y/%m/%d %H:%M:%S.%f") # plugin your time object
delta = my_time - epoch
return delta.total_seconds() * 1000.0