关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
关于使用fs.readdir进行异步目录搜索有什么想法吗?我意识到我们可以引入递归,并调用read目录函数来读取下一个目录,但我有点担心它不是异步的…
什么好主意吗?我已经看了node-walk,它很棒,但它不能像readdir那样只给我数组中的文件。虽然
寻找这样的输出…
['file1.txt', 'file2.txt', 'dir/file3.txt']
当前回答
下面是完整的工作代码。按您的要求。您可以递归地获取所有文件和文件夹。
var recur = function(dir) {
fs.readdir(dir,function(err,list){
list.forEach(function(file){
var file2 = path.resolve(dir, file);
fs.stat(file2,function(err,stats){
if(stats.isDirectory()) {
recur(file2);
}
else {
console.log(file2);
}
})
})
});
};
recur(path);
在路径中给出你想要搜索的目录路径,如"c:\test"
其他回答
递归-readdir模块具有此功能。
我必须将基于promise的砂光器库添加到列表中。
var sander = require('sander');
sander.lsr(directory).then( filenames => { console.log(filenames) } );
这是我如何使用nodejs的fs。递归搜索目录的Readdir函数。
const fs = require('fs');
const mime = require('mime-types');
const readdirRecursivePromise = path => {
return new Promise((resolve, reject) => {
fs.readdir(path, (err, directoriesPaths) => {
if (err) {
reject(err);
} else {
if (directoriesPaths.indexOf('.DS_Store') != -1) {
directoriesPaths.splice(directoriesPaths.indexOf('.DS_Store'), 1);
}
directoriesPaths.forEach((e, i) => {
directoriesPaths[i] = statPromise(`${path}/${e}`);
});
Promise.all(directoriesPaths).then(out => {
resolve(out);
}).catch(err => {
reject(err);
});
}
});
});
};
const statPromise = path => {
return new Promise((resolve, reject) => {
fs.stat(path, (err, stats) => {
if (err) {
reject(err);
} else {
if (stats.isDirectory()) {
readdirRecursivePromise(path).then(out => {
resolve(out);
}).catch(err => {
reject(err);
});
} else if (stats.isFile()) {
resolve({
'path': path,
'type': mime.lookup(path)
});
} else {
reject(`Error parsing path: ${path}`);
}
}
});
});
};
const flatten = (arr, result = []) => {
for (let i = 0, length = arr.length; i < length; i++) {
const value = arr[i];
if (Array.isArray(value)) {
flatten(value, result);
} else {
result.push(value);
}
}
return result;
};
假设在节点项目根目录中有一个名为“/database”的路径。一旦这个承诺被解决,它应该吐出'/database'下的每个文件的数组。
readdirRecursivePromise('database').then(out => {
console.log(flatten(out));
}).catch(err => {
console.log(err);
});
另一个答案,但这次使用的是TypeScript:
/** * Recursively walk a directory asynchronously and obtain all file names (with full path). * * @param dir Folder name you want to recursively process * @param done Callback function, returns all files with full path. * @param filter Optional filter to specify which files to include, * e.g. for json files: (f: string) => /.json$/.test(f) */ const walk = ( dir: string, done: (err: Error | null, results ? : string[]) => void, filter ? : (f: string) => boolean ) => { let results: string[] = []; fs.readdir(dir, (err: Error, list: string[]) => { if (err) { return done(err); } let pending = list.length; if (!pending) { return done(null, results); } list.forEach((file: string) => { file = path.resolve(dir, file); fs.stat(file, (err2, stat) => { if (stat && stat.isDirectory()) { walk(file, (err3, res) => { if (res) { results = results.concat(res); } if (!--pending) { done(null, results); } }, filter); } else { if (typeof filter === 'undefined' || (filter && filter(file))) { results.push(file); } if (!--pending) { done(null, results); } } }); }); }); };
异步
const fs = require('fs')
const path = require('path')
const readdir = (p, done, a = [], i = 0) => fs.readdir(p, (e, d = []) =>
d.map(f => readdir(a[a.push(path.join(p, f)) - 1], () =>
++i == d.length && done(a), a)).length || done(a))
readdir(__dirname, console.log)
Sync
const fs = require('fs')
const path = require('path')
const readdirSync = (p, a = []) => {
if (fs.statSync(p).isDirectory())
fs.readdirSync(p).map(f => readdirSync(a[a.push(path.join(p, f)) - 1], a))
return a
}
console.log(readdirSync(__dirname))
异步读
function readdir (currentPath, done, allFiles = [], i = 0) {
fs.readdir(currentPath, function (e, directoryFiles = []) {
if (!directoryFiles.length)
return done(allFiles)
directoryFiles.map(function (file) {
var joinedPath = path.join(currentPath, file)
allFiles.push(joinedPath)
readdir(joinedPath, function () {
i = i + 1
if (i == directoryFiles.length)
done(allFiles)}
, allFiles)
})
})
}
readdir(__dirname, console.log)
注意:两个版本都将跟随符号链接(与原始fs.readdir相同)