明确一点,我并不是在寻找MIME类型。
假设我有以下输入:/path/to/file/foo.txt
我想要一种方法来分解这个输入,特别是扩展为.txt。在Java中有任何内置的方法来做到这一点吗?我希望避免编写自己的解析器。
明确一点,我并不是在寻找MIME类型。
假设我有以下输入:/path/to/file/foo.txt
我想要一种方法来分解这个输入,特别是扩展为.txt。在Java中有任何内置的方法来做到这一点吗?我希望避免编写自己的解析器。
当前回答
我的肮脏和可能最小的使用String.replaceAll:
.replaceAll("^.*\\.(.*)$", "$1")
请注意,第一个*是贪婪的,所以它会尽可能地抓取大多数可能的字符,然后只剩下最后一个点和文件扩展名。
其他回答
从文件名获取文件扩展名
/**
* The extension separator character.
*/
private static final char EXTENSION_SEPARATOR = '.';
/**
* The Unix separator character.
*/
private static final char UNIX_SEPARATOR = '/';
/**
* The Windows separator character.
*/
private static final char WINDOWS_SEPARATOR = '\\';
/**
* The system separator character.
*/
private static final char SYSTEM_SEPARATOR = File.separatorChar;
/**
* Gets the extension of a filename.
* <p>
* This method returns the textual part of the filename after the last dot.
* There must be no directory separator after the dot.
* <pre>
* foo.txt --> "txt"
* a/b/c.jpg --> "jpg"
* a/b.txt/c --> ""
* a/b/c --> ""
* </pre>
* <p>
* The output will be the same irrespective of the machine that the code is running on.
*
* @param filename the filename to retrieve the extension of.
* @return the extension of the file or an empty string if none exists.
*/
public static String getExtension(String filename) {
if (filename == null) {
return null;
}
int index = indexOfExtension(filename);
if (index == -1) {
return "";
} else {
return filename.substring(index + 1);
}
}
/**
* Returns the index of the last extension separator character, which is a dot.
* <p>
* This method also checks that there is no directory separator after the last dot.
* To do this it uses {@link #indexOfLastSeparator(String)} which will
* handle a file in either Unix or Windows format.
* <p>
* The output will be the same irrespective of the machine that the code is running on.
*
* @param filename the filename to find the last path separator in, null returns -1
* @return the index of the last separator character, or -1 if there
* is no such character
*/
public static int indexOfExtension(String filename) {
if (filename == null) {
return -1;
}
int extensionPos = filename.lastIndexOf(EXTENSION_SEPARATOR);
int lastSeparator = indexOfLastSeparator(filename);
return (lastSeparator > extensionPos ? -1 : extensionPos);
}
/**
* Returns the index of the last directory separator character.
* <p>
* This method will handle a file in either Unix or Windows format.
* The position of the last forward or backslash is returned.
* <p>
* The output will be the same irrespective of the machine that the code is running on.
*
* @param filename the filename to find the last path separator in, null returns -1
* @return the index of the last separator character, or -1 if there
* is no such character
*/
public static int indexOfLastSeparator(String filename) {
if (filename == null) {
return -1;
}
int lastUnixPos = filename.lastIndexOf(UNIX_SEPARATOR);
int lastWindowsPos = filename.lastIndexOf(WINDOWS_SEPARATOR);
return Math.max(lastUnixPos, lastWindowsPos);
}
学分
复制自Apache FileNameUtils Class - http://grepcode.com/file/repo1.maven.org/maven2/commons-io/commons-io/1.3.2/org/apache/commons/io/FilenameUtils.java#FilenameUtils.getExtension%28java.lang.String%29
下面是Java 8的另一个一行程序。
String ext = Arrays.stream(fileName.split("\\.")).reduce((a,b) -> b).orElse(null)
其工作原理如下:
使用"."将字符串拆分为字符串数组。 将数组转换为流 使用reduce获取流的最后一个元素,即文件扩展名
下面是一个正确处理.tar.gz的方法,即使是在目录名中有点的路径中:
private static final String getExtension(final String filename) {
if (filename == null) return null;
final String afterLastSlash = filename.substring(filename.lastIndexOf('/') + 1);
final int afterLastBackslash = afterLastSlash.lastIndexOf('\\') + 1;
final int dotIndex = afterLastSlash.indexOf('.', afterLastBackslash);
return (dotIndex == -1) ? "" : afterLastSlash.substring(dotIndex + 1);
}
创建afterLastSlash是为了更快地查找afterLastBackslash,因为如果字符串中有一些斜杠,它就不必搜索整个字符串。
原始String中的char[]被重用,没有在那里添加垃圾,JVM可能会注意到afterLastSlash立即是垃圾,以便将其放在堆栈而不是堆上。
private String getExtension(File file)
{
String fileName = file.getName();
String[] ext = fileName.split("\\.");
return ext[ext.length -1];
}
试试这个。
String[] extension = "adadad.adad.adnandad.jpg".split("\\.(?=[^\\.]+$)"); // ['adadad.adad.adnandad','jpg']
extension[1] // jpg