我试图在Java中反转一个int数组。
此方法不反转数组。
for(int i = 0; i < validData.length; i++)
{
int temp = validData[i];
validData[i] = validData[validData.length - i - 1];
validData[validData.length - i - 1] = temp;
}
有什么问题吗?
我试图在Java中反转一个int数组。
此方法不反转数组。
for(int i = 0; i < validData.length; i++)
{
int temp = validData[i];
validData[i] = validData[validData.length - i - 1];
validData[validData.length - i - 1] = temp;
}
有什么问题吗?
当前回答
for(int i=validData.length-1; i>=0; i--){
System.out.println(validData[i]);
}
其他回答
使用流来反转
这里已经有很多答案,主要集中在就地修改数组。但是为了完整起见,这里有另一种使用Java流来保留原始数组并创建一个新的反向数组的方法:
int[] a = {8, 6, 7, 5, 3, 0, 9};
int[] b = IntStream.rangeClosed(1, a.length).map(i -> a[a.length-i]).toArray();
这里是一个简单的实现,反转数组的任何类型,加上全/部分支持。
import java.util.logging.Logger;
public final class ArrayReverser {
private static final Logger LOGGER = Logger.getLogger(ArrayReverser.class.getName());
private ArrayReverser () {
}
public static <T> void reverse(T[] seed) {
reverse(seed, 0, seed.length);
}
public static <T> void reverse(T[] seed, int startIndexInclusive, int endIndexExclusive) {
if (seed == null || seed.length == 0) {
LOGGER.warning("Nothing to rotate");
}
int start = startIndexInclusive < 0 ? 0 : startIndexInclusive;
int end = Math.min(seed.length, endIndexExclusive) - 1;
while (start < end) {
swap(seed, start, end);
start++;
end--;
}
}
private static <T> void swap(T[] seed, int start, int end) {
T temp = seed[start];
seed[start] = seed[end];
seed[end] = temp;
}
}
下面是相应的单元测试
import static org.hamcrest.CoreMatchers.is;
import static org.junit.Assert.assertThat;
import org.junit.Before;
import org.junit.Test;
public class ArrayReverserTest {
private Integer[] seed;
@Before
public void doBeforeEachTestCase() {
this.seed = new Integer[]{1,2,3,4,5,6,7,8};
}
@Test
public void wholeArrayReverse() {
ArrayReverser.<Integer>reverse(seed);
assertThat(seed[0], is(8));
}
@Test
public void partialArrayReverse() {
ArrayReverser.<Integer>reverse(seed, 1, 5);
assertThat(seed[1], is(5));
}
}
public class TryReverse {
public static void main(String[] args) {
int [] array = {2,3,4,5,6,7,8,9};
reverse(array);
for(int i=0; i<array.length; ++i)
System.out.print(array[i] + " ");
}
public static void reverse (int [] array){
for(int start=0, end=array.length-1; start<=end; start++, end--){
int aux = array[start];
array[start]=array[end];
array[end]=aux;
}
}
}
试试这个程序在JAVA:-
import java.util.Scanner;
public class Rev_one_D {
static int row;
static int[] trans_arr = new int[row];
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
row = n;
int[] arr = new int[row];
for (int i = 0; i < row; i++) {
arr[i] = sc.nextInt();
System.out.print(arr[i] + " ");
System.out.println();
}
for (int i = 0; i < arr.length / 2; i++) {
int temp = arr[i];
arr[i] = arr[arr.length - i - 1];
arr[arr.length - i - 1] = temp;
}
for (int i = 0; i < row; i++) {
System.out.print(arr[i] + " ");
System.out.println();
}
}
}
试试下面的代码:
int arr[] = new int[]{1,2,3,4,5,6,7};
for(int i=0;i<arr.length/2;i++){
int temp = arr[i];
arr[i] = arr[(arr.length-1)-i];
arr[(arr.length-1)-i] = temp;
}
System.out.println(Arrays.toString(arr));