在代码中从maven的pom.xml中检索版本号的最简单方法是什么,即以编程方式?


当前回答

在使用spring引导时,这个链接可能有用:https://docs.spring.io/spring-boot/docs/2.3.x/reference/html/howto.html#howto-properties-and-configuration

使用spring-boot-starter-parent,你只需要在你的应用配置文件中添加以下内容:

# get values from pom.xml
pom.version=@project.version@

之后的值是这样的:

@Value("${pom.version}")
private String pomVersion;

其他回答

为了补充@kieste所发布的内容,我认为如果使用Spring-boot,这是在代码中提供Maven构建信息的最佳方式:http://docs.spring.io/spring-boot/docs/current/reference/htmlsingle/#production-ready-application-info上的文档非常有用。

您只需要激活执行器,并在应用程序中添加所需的属性。属性或application.yml

Automatic property expansion using Maven

You can automatically expand info properties from the Maven project using resource filtering. If you use the spring-boot-starter-parent you can then refer to your Maven ‘project properties’ via @..@ placeholders, e.g.

project.artifactId=myproject
project.name=Demo
project.version=X.X.X.X
project.description=Demo project for info endpoint
info.build.artifact=@project.artifactId@
info.build.name=@project.name@
info.build.description=@project.description@
info.build.version=@project.version@

使用这个库可以获得简单的解决方案。向清单中添加您需要的任何内容,然后按字符串查询。

 System.out.println("JAR was created by " + Manifests.read("Created-By"));

http://manifests.jcabi.com/index.html

有时,当编写与项目版本相关的脚本时,Maven命令行就足够了,例如,通过URL从存储库检索工件:

mvn help:evaluate -Dexpression=project.version -q -DforceStdout

使用的例子:

VERSION=$( mvn help:evaluate -Dexpression=project.version -q -DforceStdout )
ARTIFACT_ID=$( mvn help:evaluate -Dexpression=project.artifactId -q -DforceStdout )
GROUP_ID_URL=$( mvn help:evaluate -Dexpression=project.groupId -q -DforceStdout | sed -e 's#\.#/#g' )
curl -f -S -O http://REPO-URL/mvn-repos/${GROUP_ID_URL}/${ARTIFACT_ID}/${VERSION}/${ARTIFACT_ID}-${VERSION}.jar

引言:因为我记得在几年前回答了这个问题后,我经常提到这个问题,展示了一个动态访问Maven POM信息的动态版本(例如,也在测试期间),今天我发现了一个类似的问题,涉及从另一个模块B访问模块a的Maven信息。

I thought about it for a moment and spontaneously had the idea to use a special annotation, applying it to a package declaration in package-info.java. I also created a multi-module example project on GitHub. I do not want to repeat the whole answer, so please see solution B in this answer. The Maven setup involves Templating Maven Plugin, but could also be solved in a more verbose way using a combination of resource filtering and adding generated sources directory to the build via Build Helper Maven. I wanted to avoid that, so I simply used Templating Maven.

    <build>
            <finalName>${project.artifactId}-${project.version}</finalName>
            <pluginManagement>
                <plugins>
                    <plugin>
                        <groupId>org.apache.maven.plugins</groupId>
                        <artifactId>maven-war-plugin</artifactId>
                        <version>3.2.2</version>
                        <configuration>
                            <failOnMissingWebXml>false</failOnMissingWebXml>
                            <archive>
                                <manifest>
                                    <addDefaultImplementationEntries>true</addDefaultImplementationEntries>
                                    <addDefaultSpecificationEntries>true</addDefaultSpecificationEntries>
                                </manifest>
                            </archive>
                        </configuration>
                    </plugin>
                 </plugins>
            </pluginManagement>
</build>

使用this.getClass().getPackage().getImplementationVersion()获取版本

PS别忘了补充:

<manifest>
    <addDefaultImplementationEntries>true</addDefaultImplementationEntries>
    <addDefaultSpecificationEntries>true</addDefaultSpecificationEntries>
</manifest>