如何使用python3搜索和替换文件中的文本?
这是我的代码:
import os
import sys
import fileinput
print ("Text to search for:")
textToSearch = input( "> " )
print ("Text to replace it with:")
textToReplace = input( "> " )
print ("File to perform Search-Replace on:")
fileToSearch = input( "> " )
#fileToSearch = 'D:\dummy1.txt'
tempFile = open( fileToSearch, 'r+' )
for line in fileinput.input( fileToSearch ):
if textToSearch in line :
print('Match Found')
else:
print('Match Not Found!!')
tempFile.write( line.replace( textToSearch, textToReplace ) )
tempFile.close()
input( '\n\n Press Enter to exit...' )
输入文件:
hi this is abcd hi this is abcd
This is dummy text file.
This is how search and replace works abcd
当我在上面的输入文件中搜索并将“ram”替换为“abcd”时，它就像一个咒语。但当我反过来做，即替换'abcd'由'ram'，一些垃圾字符被留在最后。
将'abcd'替换为'ram'
hi this is ram hi this is ram
This is dummy text file.
This is how search and replace works rambcd
def word_replace(filename,old,new):
c=0
with open(filename,'r+',encoding ='utf-8') as f:
a=f.read()
b=a.split()
for i in range(0,len(b)):
if b[i]==old:
c=c+1
old=old.center(len(old)+2)
new=new.center(len(new)+2)
d=a.replace(old,new,c)
f.truncate(0)
f.seek(0)
f.write(d)
print('All words have been replaced!!!')
使用re.subn可以对替换过程进行更多的控制，例如将单词分成两行，区分大小写的匹配。此外，它返回匹配的数量，如果没有找到字符串，可以使用这些匹配来避免浪费资源。
import re
file = # path to file
# they can be also raw string and regex
textToSearch = r'Ha.*O' # here an example with a regex
textToReplace = 'hallo'
# read and replace
with open(file, 'r') as fd:
# sample case-insensitive find-and-replace
text, counter = re.subn(textToSearch, textToReplace, fd.read(), re.I)
# check if there is at least a match
if counter > 0:
# edit the file
with open(file, 'w') as fd:
fd.write(text)
# summary result
print(f'{counter} occurence of "{textToSearch}" were replaced with "{textToReplace}".')
一些正则表达式:
添加re.I标志，re.IGNORECASE的缩写形式，用于不区分大小写的匹配
对于多行替换re.subn(r'\n*'.join(textToSearch)， textToReplace, fd.read()))，取决于数据也'\n{，1}'。注意，在这种情况下，textToSearch必须是纯字符串，而不是正则表达式!
def findReplace(find, replace):
import os
src = os.path.join(os.getcwd(), os.pardir)
for path, dirs, files in os.walk(os.path.abspath(src)):
for name in files:
if name.endswith('.py'):
filepath = os.path.join(path, name)
with open(filepath) as f:
s = f.read()
s = s.replace(find, replace)
with open(filepath, "w") as f:
f.write(s)
正如michaelb958所指出的，不能用不同长度的数据替换现有的部分，因为这会使其余部分不合适。我不同意其他人建议你从一个文件读到另一个文件。相反，我将把文件读入内存，修复数据，然后在单独的步骤中将其写入相同的文件。
# Read in the file
with open('file.txt', 'r') as file :
filedata = file.read()
# Replace the target string
filedata = filedata.replace('abcd', 'ram')
# Write the file out again
with open('file.txt', 'w') as file:
file.write(filedata)
除非你有一个巨大的文件要处理，它太大了，无法一次性加载到内存中，或者你担心如果在向文件写入数据的第二步过程中中断，可能会导致数据丢失。
你可以在python中使用sed、awk或grep(有一些限制)。这里有一个非常简单的例子。它在文件中把香蕉变成香蕉牙膏。你可以编辑和使用它。(我测试过了…注意:如果你在Windows下测试，你应该先安装sed命令并设置路径)
import os
file="a.txt"
oldtext="Banana"
newtext=" BananaToothpaste"
os.system('sed -i "s/{}/{}/g" {}'.format(oldtext,newtext,file))
#print(f'sed -i "s/{oldtext}/{newtext}/g" {file}')
print('This command was applied: sed -i "s/{}/{}/g" {}'.format(oldtext,newtext,file))
如果你想直接在文件上看到结果，应用:"type" for windows/ "cat" for linux:
####FOR WINDOWS:
os.popen("type " + file).read()
####FOR LINUX:
os.popen("cat " + file).read()
正如Jack Aidley发布的和J.F. Sebastian指出的那样，这个代码是行不通的:
# Read in the file
filedata = None
with file = open('file.txt', 'r') :
filedata = file.read()
# Replace the target string
filedata.replace('ram', 'abcd')
# Write the file out again
with file = open('file.txt', 'w') :
file.write(filedata)`
但这段代码将工作(我已经测试过了):
f = open(filein,'r')
filedata = f.read()
f.close()
newdata = filedata.replace("old data","new data")
f = open(fileout,'w')
f.write(newdata)
f.close()
使用此方法，fileein和fileout可以是同一个文件，因为Python 3.3将在打开进行写入时覆盖该文件。
