如何搜索和替换文件中的文本?

如何使用python3搜索和替换文件中的文本?

这是我的代码:

import os
import sys
import fileinput

print ("Text to search for:")
textToSearch = input( "> " )

print ("Text to replace it with:")
textToReplace = input( "> " )

print ("File to perform Search-Replace on:")
fileToSearch  = input( "> " )
#fileToSearch = 'D:\dummy1.txt'

tempFile = open( fileToSearch, 'r+' )

for line in fileinput.input( fileToSearch ):
    if textToSearch in line :
        print('Match Found')
    else:
        print('Match Not Found!!')
    tempFile.write( line.replace( textToSearch, textToReplace ) )
tempFile.close()


input( '\n\n Press Enter to exit...' )

输入文件:

hi this is abcd hi this is abcd
This is dummy text file.
This is how search and replace works abcd

当我在上面的输入文件中搜索并将“ram”替换为“abcd”时，它就像一个咒语。但当我反过来做，即替换'abcd'由'ram'，一些垃圾字符被留在最后。

将'abcd'替换为'ram'

hi this is ram hi this is ram
This is dummy text file.
This is how search and replace works rambcd

当前回答

(pip install python-util)

from pyutil import filereplace

filereplace("somefile.txt","abcd","ram")

将所有出现的“abcd”替换为“ram”。该函数还通过指定regex=True来支持regex

from pyutil import filereplace

filereplace("somefile.txt","\\w+","ram",regex=True)

免责声明:我是作者(https://github.com/MisterL2/python-util)

2019-08-23 13:43:29

其他回答

正如michaelb958所指出的，不能用不同长度的数据替换现有的部分，因为这会使其余部分不合适。我不同意其他人建议你从一个文件读到另一个文件。相反，我将把文件读入内存，修复数据，然后在单独的步骤中将其写入相同的文件。

# Read in the file
with open('file.txt', 'r') as file :
  filedata = file.read()

# Replace the target string
filedata = filedata.replace('abcd', 'ram')

# Write the file out again
with open('file.txt', 'w') as file:
  file.write(filedata)

除非你有一个巨大的文件要处理，它太大了，无法一次性加载到内存中，或者你担心如果在向文件写入数据的第二步过程中中断，可能会导致数据丢失。

2013-06-17 06:29:50

您的问题源于读取和写入同一个文件。与其打开fileToSearch进行写入，不如打开一个实际的临时文件，然后在您完成并关闭tempFile之后，使用os。rename将新文件移动到fileToSearch上。

2013-06-17 05:43:36

我试过用readline代替read

with open('dummy.txt','r') as file:
    list = file.readlines()
print(f'before removal {list}')
for i in list[:]:
        list.remove(i)

print(f'After removal {list}')
with open('dummy.txt','w+') as f:
    for i in list:
        f.write(i)

2021-03-02 10:44:58

使用re.subn可以对替换过程进行更多的控制，例如将单词分成两行，区分大小写的匹配。此外，它返回匹配的数量，如果没有找到字符串，可以使用这些匹配来避免浪费资源。

import re

file = # path to file

# they can be also raw string and regex
textToSearch = r'Ha.*O' # here an example with a regex
textToReplace = 'hallo'

# read and replace
with open(file, 'r') as fd:
    # sample case-insensitive find-and-replace
    text, counter = re.subn(textToSearch, textToReplace, fd.read(), re.I)

# check if there is at least a  match
if counter > 0:
    # edit the file
    with open(file, 'w') as fd:
        fd.write(text)

# summary result
print(f'{counter} occurence of "{textToSearch}" were replaced with "{textToReplace}".')

一些正则表达式:

添加re.I标志，re.IGNORECASE的缩写形式，用于不区分大小写的匹配对于多行替换re.subn(r'\n*'.join(textToSearch)， textToReplace, fd.read()))，取决于数据也'\n{，1}'。注意，在这种情况下，textToSearch必须是纯字符串，而不是正则表达式!

2022-08-06 22:47:41

def findReplace(find, replace):

    import os 

    src = os.path.join(os.getcwd(), os.pardir) 

    for path, dirs, files in os.walk(os.path.abspath(src)):

        for name in files: 

            if name.endswith('.py'): 

                filepath = os.path.join(path, name)

                with open(filepath) as f: 

                    s = f.read()

                s = s.replace(find, replace) 

                with open(filepath, "w") as f:

                    f.write(s)

2018-06-20 10:06:18

如何搜索和替换文件中的文本?

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