我试图创建一个完整的路径,如果它不存在。

代码如下所示:

var fs = require('fs');
if (!fs.existsSync(newDest)) fs.mkdirSync(newDest); 

只要只有一个子目录(像'dir1'这样的newDest),这段代码就能很好地工作,但是当有一个目录路径('dir1/dir2')时,它就会失败 错误:ENOENT,没有这样的文件或目录

我希望能够用尽可能少的代码行创建完整的路径。

我读到fs上有一个递归选项,并尝试了这样做

var fs = require('fs');
if (!fs.existsSync(newDest)) fs.mkdirSync(newDest,'0777', true);

我觉得递归地创建一个不存在的目录应该这么简单。我是否遗漏了一些东西,或者我是否需要解析路径并检查每个目录,如果它不存在,则创建它?

我对Node很陌生。也许我使用的是旧版本的FS?


当前回答

该特性已在10.12.0版本中添加到node.js中,因此只需将选项{recursive: true}作为第二个参数传递给fs.mkdir()调用即可。 请参阅官方文档中的示例。

不需要外部模块或自己的实现。

其他回答

我对fs的递归选项有问题。mkdir,所以我做了一个函数,做以下工作:

Creates a list of all directories, starting with the final target dir and working up to the root parent. Creates a new list of needed directories for the mkdir function to work Makes each directory needed, including the final function createDirectoryIfNotExistsRecursive(dirname) { return new Promise((resolve, reject) => { const fs = require('fs'); var slash = '/'; // backward slashes for windows if(require('os').platform() === 'win32') { slash = '\\'; } // initialize directories with final directory var directories_backwards = [dirname]; var minimize_dir = dirname; while (minimize_dir = minimize_dir.substring(0, minimize_dir.lastIndexOf(slash))) { directories_backwards.push(minimize_dir); } var directories_needed = []; //stop on first directory found for(const d in directories_backwards) { if(!(fs.existsSync(directories_backwards[d]))) { directories_needed.push(directories_backwards[d]); } else { break; } } //no directories missing if(!directories_needed.length) { return resolve(); } // make all directories in ascending order var directories_forwards = directories_needed.reverse(); for(const d in directories_forwards) { fs.mkdirSync(directories_forwards[d]); } return resolve(); }); }

fs-extra添加了本地fs模块中不包含的文件系统方法。它是fs替换量的下降。

安装fs-extra

$ NPM install——保存fs-extra

const fs = require("fs-extra");
// Make sure the output directory is there.
fs.ensureDirSync(newDest);

有同步和异步选项。

https://github.com/jprichardson/node-fs-extra/blob/master/docs/ensureDir.md

使用reduce,我们可以验证每个路径是否存在,并在必要时创建它,而且我认为这样更容易遵循。编辑,谢谢@Arvin,我们应该使用路径。Sep来获得适当的平台特定路径段分隔符。

const path = require('path');

// Path separators could change depending on the platform
const pathToCreate = 'path/to/dir'; 
pathToCreate
 .split(path.sep)
 .reduce((prevPath, folder) => {
   const currentPath = path.join(prevPath, folder, path.sep);
   if (!fs.existsSync(currentPath)){
     fs.mkdirSync(currentPath);
   }
   return currentPath;
 }, '');

基于mouneer的零依赖回答,这里有一个初学者更友好的Typescript变体,作为一个模块:

import * as fs from 'fs';
import * as path from 'path';

/**
* Recursively creates directories until `targetDir` is valid.
* @param targetDir target directory path to be created recursively.
* @param isRelative is the provided `targetDir` a relative path?
*/
export function mkdirRecursiveSync(targetDir: string, isRelative = false) {
    const sep = path.sep;
    const initDir = path.isAbsolute(targetDir) ? sep : '';
    const baseDir = isRelative ? __dirname : '.';

    targetDir.split(sep).reduce((prevDirPath, dirToCreate) => {
        const curDirPathToCreate = path.resolve(baseDir, prevDirPath, dirToCreate);
        try {
            fs.mkdirSync(curDirPathToCreate);
        } catch (err) {
            if (err.code !== 'EEXIST') {
                throw err;
            }
            // caught EEXIST error if curDirPathToCreate already existed (not a problem for us).
        }

        return curDirPathToCreate; // becomes prevDirPath on next call to reduce
    }, initDir);
}

Windows的示例(没有额外的依赖和错误处理)

const path = require('path');
const fs = require('fs');

let dir = "C:\\temp\\dir1\\dir2\\dir3";

function createDirRecursively(dir) {
    if (!fs.existsSync(dir)) {        
        createDirRecursively(path.join(dir, ".."));
        fs.mkdirSync(dir);
    }
}

createDirRecursively(dir); //creates dir1\dir2\dir3 in C:\temp