我定义了两个TextInput字段如下:
<TextInput
style = {styles.titleInput}
returnKeyType = {"next"}
autoFocus = {true}
placeholder = "Title" />
<TextInput
style = {styles.descriptionInput}
multiline = {true}
maxLength = {200}
placeholder = "Description" />
但在按下键盘上的“next”按钮后，我的react-native应用程序并没有跳转到第二个TextInput字段。我怎样才能做到呢?
谢谢!
当前回答
在React Native的GitHub问题上尝试这个解决方案。
https://github.com/facebook/react-native/pull/2149#issuecomment-129262565
你需要为TextInput组件使用ref道具。 然后你需要创建一个函数，该函数在onSubmitEditing道具上被调用，将焦点移动到第二个TextInput引用上。
var InputScreen = React.createClass({
_focusNextField(nextField) {
this.refs[nextField].focus()
},
render: function() {
return (
<View style={styles.container}>
<TextInput
ref='1'
style={styles.input}
placeholder='Normal'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('2')}
/>
<TextInput
ref='2'
style={styles.input}
keyboardType='email-address'
placeholder='Email Address'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('3')}
/>
<TextInput
ref='3'
style={styles.input}
keyboardType='url'
placeholder='URL'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('4')}
/>
<TextInput
ref='4'
style={styles.input}
keyboardType='numeric'
placeholder='Numeric'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('5')}
/>
<TextInput
ref='5'
style={styles.input}
keyboardType='numbers-and-punctuation'
placeholder='Numbers & Punctuation'
returnKeyType='done'
/>
</View>
);
}
});
其他回答
设置第二个TextInput焦点，当前一个TextInput的onSubmitEditing被触发时。
试试这个
为第二个TextInput添加一个引用 Ref ={(input) => {this。secondTextInput =输入;}} 绑定焦点函数到第一个TextInput的onSubmitEditing事件。 onSubmitEditing={() => {this.secondTextInput.focus();}} 记住将blurOnSubmit设置为false，以防止键盘闪烁。 blurOnSubmit ={假}
当一切都完成后，它应该看起来像这样。
<TextInput
placeholder="FirstTextInput"
returnKeyType="next"
onSubmitEditing={() => { this.secondTextInput.focus(); }}
blurOnSubmit={false}
/>
<TextInput
ref={(input) => { this.secondTextInput = input; }}
placeholder="secondTextInput"
/>
下面是如何为reactjs的电话代码输入实现这一点
import React, { useState, useRef } from 'react';
function Header(props) {
const [state , setState] = useState({
phone_number:"",
code_one:'',
code_two:'',
code_three:'',
code_four:'',
submitted:false,
})
const codeOneInput = useRef(null);
const codeTwoInput = useRef(null);
const codeThreeInput = useRef(null);
const codeFourInput = useRef(null);
const handleCodeChange = (e) => {
const {id , value} = e.target
if(value.length < 2){
setState(prevState => ({
...prevState,
[id] : value
}))
if(id=='code_one' && value.length >0){
codeTwoInput.current.focus();
}
if(id=='code_two' && value.length >0){
codeThreeInput.current.focus();
}
if(id=='code_three' && value.length >0){
codeFourInput.current.focus();
}
}
}
const sendCodeToServer = () => {
setState(prevState => ({
...prevState,
submitted : true,
}))
let codeEnteredByUser = state.code_one + state.code_two + state.code_three + state.code_four
axios.post(API_BASE_URL, {code:codeEnteredByUser})
.then(function (response) {
console.log(response)
})
}
return(
<>
<div className="are">
<div className="POP-INN-INPUT">
<input type="text" id="code_one" ref={codeOneInput} value={state.code_one} onChange={handleCodeChange} autoFocus/>
<input type="text" id="code_two" ref={codeTwoInput} value={state.code_two} onChange={handleCodeChange}/>
<input type="text" id="code_three" ref={codeThreeInput} value={state.code_three} onChange={handleCodeChange}/>
<input type="text" id="code_four" ref={codeFourInput} value={state.code_four} onChange={handleCodeChange}/>
</div>
<button disabled={state.submitted} onClick={sendCodeToServer}>
</div>
</>
)
}
export default
在React Native的GitHub问题上尝试这个解决方案。
https://github.com/facebook/react-native/pull/2149#issuecomment-129262565
你需要为TextInput组件使用ref道具。 然后你需要创建一个函数，该函数在onSubmitEditing道具上被调用，将焦点移动到第二个TextInput引用上。
var InputScreen = React.createClass({
_focusNextField(nextField) {
this.refs[nextField].focus()
},
render: function() {
return (
<View style={styles.container}>
<TextInput
ref='1'
style={styles.input}
placeholder='Normal'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('2')}
/>
<TextInput
ref='2'
style={styles.input}
keyboardType='email-address'
placeholder='Email Address'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('3')}
/>
<TextInput
ref='3'
style={styles.input}
keyboardType='url'
placeholder='URL'
returnKeyType='next'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('4')}
/>
<TextInput
ref='4'
style={styles.input}
keyboardType='numeric'
placeholder='Numeric'
blurOnSubmit={false}
onSubmitEditing={() => this._focusNextField('5')}
/>
<TextInput
ref='5'
style={styles.input}
keyboardType='numbers-and-punctuation'
placeholder='Numbers & Punctuation'
returnKeyType='done'
/>
</View>
);
}
});
RN没有某种类型的Tabindex系统，这很令人恼火。
一个功能性组件，对于我的用例，我有一个字符串id数组用于输入，我遍历并显示每个文本输入。下面的代码将自动跳过所有这些，阻止键盘在字段之间消失/重新出现，并在结束时解散它，还在键盘上显示适当的“动作”按钮。
Typescript, Native Base。
const stringFieldIDs = [ 'q1', 'q2', 'q3' ]; export default () => { const stringFieldRefs = stringFieldIDs.map(() => useRef < any > ()); const basicStringField = (id: string, ind: number) => { const posInd = stringFieldIDs.indexOf(id); const isLast = posInd === stringFieldIDs.length - 1; return ( < Input blurOnSubmit = { isLast } ref = { stringFieldRefs[posInd] } returnKeyType = { isLast ? 'done' : 'next' } onSubmitEditing = { isLast ? undefined : () => stringFieldRefs[posInd + 1].current._root.focus() } /> ); }; return stringFieldIDs.map(basicStringField); };
我就是这样做到的。下面的例子使用了React 16.3中引入的React. createref () API。
class Test extends React.Component {
constructor(props) {
super(props);
this.secondTextInputRef = React.createRef();
}
render() {
return(
<View>
<TextInput
placeholder = "FirstTextInput"
returnKeyType="next"
onSubmitEditing={() => { this.secondTextInputRef.current.focus(); }}
/>
<TextInput
ref={this.secondTextInputRef}
placeholder = "secondTextInput"
/>
</View>
);
}
}
我想这对你有帮助。