有什么快速而简单的方法可以确保在给定时间内只有一个shell脚本实例在运行?


当前回答

试试下面的方法,

ab=`ps -ef | grep -v grep | grep -wc processname`

然后使用if循环将变量与1匹配。

其他回答

我使用一种简单的方法来处理过期的锁文件。

注意,上面的一些解决方案存储pid,忽略了pid可以环绕的事实。因此,仅仅检查是否有一个有效的进程与存储的pid是不够的,特别是对于长时间运行的脚本。

我使用noclobber来确保一次只能打开一个脚本并写入锁文件。此外,我在锁文件中存储了足够的信息来惟一地标识一个进程。我定义了一组数据来唯一地标识一个进程为pid、ppid、lstart。

当一个新脚本启动时,如果它未能创建锁文件,那么它将验证创建锁文件的进程是否仍然存在。如果不是,我们假设原始进程不体面地死亡,并留下一个过时的锁文件。然后,新脚本获得锁文件的所有权,一切又恢复正常了。

应该与跨多个平台的多个shell一起工作。快速、便携、简单。

#!/usr/bin/env sh
# Author: rouble

LOCKFILE=/var/tmp/lockfile #customize this line

trap release INT TERM EXIT

# Creates a lockfile. Sets global variable $ACQUIRED to true on success.
# 
# Returns 0 if it is successfully able to create lockfile.
acquire () {
    set -C #Shell noclobber option. If file exists, > will fail.
    UUID=`ps -eo pid,ppid,lstart $$ | tail -1`
    if (echo "$UUID" > "$LOCKFILE") 2>/dev/null; then
        ACQUIRED="TRUE"
        return 0
    else
        if [ -e $LOCKFILE ]; then 
            # We may be dealing with a stale lock file.
            # Bring out the magnifying glass. 
            CURRENT_UUID_FROM_LOCKFILE=`cat $LOCKFILE`
            CURRENT_PID_FROM_LOCKFILE=`cat $LOCKFILE | cut -f 1 -d " "`
            CURRENT_UUID_FROM_PS=`ps -eo pid,ppid,lstart $CURRENT_PID_FROM_LOCKFILE | tail -1`
            if [ "$CURRENT_UUID_FROM_LOCKFILE" == "$CURRENT_UUID_FROM_PS" ]; then 
                echo "Script already running with following identification: $CURRENT_UUID_FROM_LOCKFILE" >&2
                return 1
            else
                # The process that created this lock file died an ungraceful death. 
                # Take ownership of the lock file.
                echo "The process $CURRENT_UUID_FROM_LOCKFILE is no longer around. Taking ownership of $LOCKFILE"
                release "FORCE"
                if (echo "$UUID" > "$LOCKFILE") 2>/dev/null; then
                    ACQUIRED="TRUE"
                    return 0
                else
                    echo "Cannot write to $LOCKFILE. Error." >&2
                    return 1
                fi
            fi
        else
            echo "Do you have write permissons to $LOCKFILE ?" >&2
            return 1
        fi
    fi
}

# Removes the lock file only if this script created it ($ACQUIRED is set), 
# OR, if we are removing a stale lock file (first parameter is "FORCE") 
release () {
    #Destroy lock file. Take no prisoners.
    if [ "$ACQUIRED" ] || [ "$1" == "FORCE" ]; then
        rm -f $LOCKFILE
    fi
}

# Test code
# int main( int argc, const char* argv[] )
echo "Acquring lock."
acquire
if [ $? -eq 0 ]; then 
    echo "Acquired lock."
    read -p "Press [Enter] key to release lock..."
    release
    echo "Released lock."
else
    echo "Unable to acquire lock."
fi

下面是一个更优雅、更安全、更快速、更脏的方法,结合了上面提供的答案。

使用

包括sh_lock_functions.sh 使用sh_lock_init初始化 使用sh_acquire_lock进行锁定 使用sh_check_lock检查锁 使用sh_remove_lock解锁

脚本文件

sh_lock_functions.sh

#!/bin/bash

function sh_lock_init {
    sh_lock_scriptName=$(basename $0)
    sh_lock_dir="/tmp/${sh_lock_scriptName}.lock" #lock directory
    sh_lock_file="${sh_lock_dir}/lockPid.txt" #lock file
}

function sh_acquire_lock {
    if mkdir $sh_lock_dir 2>/dev/null; then #check for lock
        echo "$sh_lock_scriptName lock acquired successfully.">&2
        touch $sh_lock_file
        echo $$ > $sh_lock_file # set current pid in lockFile
        return 0
    else
        touch $sh_lock_file
        read sh_lock_lastPID < $sh_lock_file
        if [ ! -z "$sh_lock_lastPID" -a -d /proc/$sh_lock_lastPID ]; then # if lastPID is not null and a process with that pid exists
            echo "$sh_lock_scriptName is already running.">&2
            return 1
        else
            echo "$sh_lock_scriptName stopped during execution, reacquiring lock.">&2
            echo $$ > $sh_lock_file # set current pid in lockFile
            return 2
        fi
    fi
    return 0
}

function sh_check_lock {
    [[ ! -f $sh_lock_file ]] && echo "$sh_lock_scriptName lock file removed.">&2 && return 1
    read sh_lock_lastPID < $sh_lock_file
    [[ $sh_lock_lastPID -ne $$ ]] && echo "$sh_lock_scriptName lock file pid has changed.">&2  && return 2
    echo "$sh_lock_scriptName lock still in place.">&2
    return 0
}

function sh_remove_lock {
    rm -r $sh_lock_dir
}

使用的例子

sh_lock_usage_example.sh

#!/bin/bash
. /path/to/sh_lock_functions.sh # load sh lock functions

sh_lock_init || exit $?

sh_acquire_lock
lockStatus=$?
[[ $lockStatus -eq 1 ]] && exit $lockStatus
[[ $lockStatus -eq 2 ]] && echo "lock is set, do some resume from crash procedures";

#monitoring example
cnt=0
while sh_check_lock # loop while lock is in place
do
    echo "$sh_scriptName running (pid $$)"
    sleep 1
    let cnt++
    [[ $cnt -gt 5 ]] && break
done

#remove lock when process finished
sh_remove_lock || exit $?

exit 0

特性

使用文件、目录和进程id的组合来锁定,以确保进程尚未运行 您可以检测脚本是否在删除锁之前停止(例如。进程终止,关闭,错误等) 您可以检查锁文件,并在丢失锁时使用它来触发进程关闭 Verbose,输出错误消息,以便于调试

又快又脏?

#!/bin/sh

if [ -f sometempfile ]
  echo "Already running... will now terminate."
  exit
else
  touch sometempfile
fi

..do what you want here..

rm sometempfile

试试下面的方法,

ab=`ps -ef | grep -v grep | grep -wc processname`

然后使用if循环将变量与1匹配。

在脚本的开头添加这一行

[ "${FLOCKER}" != "$0" ] && exec env FLOCKER="$0" flock -en "$0" "$0" "$@" || :

这是人类群体的样板代码。

如果需要更多的日志记录,可以使用这个

[ "${FLOCKER}" != "$0" ] && { echo "Trying to start build from queue... "; exec bash -c "FLOCKER='$0' flock -E $E_LOCKED -en '$0' '$0' '$@' || if [ \"\$?\" -eq $E_LOCKED ]; then echo 'Locked.'; fi"; } || echo "Lock is free. Completing."

使用flock工具设置和检查锁。 这段代码通过检查FLOCKER变量来检测它是否第一次运行,如果它没有设置为脚本名称,那么它会尝试再次递归地使用flock启动脚本,并初始化FLOCKER变量,如果FLOCKER设置正确,那么在前一次迭代中flock成功,可以继续。如果锁繁忙,它将失败,并使用可配置的退出代码。

它似乎不能在Debian 7上工作,但似乎可以在实验util-linux 2.25包上再次工作。上面写着“羊群:……文本文件繁忙”。可以通过禁用脚本上的写权限来覆盖它。