有什么快速而简单的方法可以确保在给定时间内只有一个shell脚本实例在运行?


当前回答

下面是一个使用锁文件并将PID回显到锁文件中的实现。如果进程在删除pidfile之前被杀死,这可以起到保护作用:

LOCKFILE=/tmp/lock.txt
if [ -e ${LOCKFILE} ] && kill -0 `cat ${LOCKFILE}`; then
    echo "already running"
    exit
fi

# make sure the lockfile is removed when we exit and then claim it
trap "rm -f ${LOCKFILE}; exit" INT TERM EXIT
echo $$ > ${LOCKFILE}

# do stuff
sleep 1000

rm -f ${LOCKFILE}

这里的技巧是kill -0,它不传递任何信号,只是检查具有给定PID的进程是否存在。此外,调用trap将确保即使进程被杀死(kill -9除外),锁文件也会被移除。

其他回答

我对现有的答案有以下问题:

Some answers try to clean up lock files and then having to deal with stale lock files caused by e.g. sudden crash/reboot. IMO that is unnecessarily complicated. Let lock files stay. Some answers use script file itself $0 or $BASH_SOURCE for locking often referring to examples from man flock. This fails when script is replaced due to update or edit causing next run to open and obtain lock on the new script file even though another instance holding a lock on the removed file is still running. Few answers use a fixed file descriptor. This is not ideal. I do not want to rely on how this will behave e.g. opening lock file fails but gets mishandled and attempts to lock on unrelated file descriptor inherited from parent process. Another fail case is injecting locking wrapper for a 3rd party binary that does not handle locking itself but fixed file descriptors can interfere with file descriptor passing to child processes. I reject answers using process lookup for already running script name. There are several reasons for it, such as but not limited to reliability/atomicity, parsing output, and having script that does several related functions some of which do not require locking.

这个答案是:

rely on flock because it gets kernel to provide locking ... provided lock file is created atomically and not replaced. assume and rely on lock file being stored on the local filesystem as opposed to NFS. change lock file presence to NOT mean anything about a running instance. Its role is purely to prevent two concurrent instances creating file with same name and replacing another's copy. Lock file does not get deleted, it gets left behind and can survive across reboots. The locking is indicated via flock not via lock file presence. assume bash shell, as tagged by the question.

它不是一个联机程序,但是没有注释和错误消息,它足够小:

#!/bin/bash

LOCKFILE=/var/lock/TODO

set -o noclobber
exec {lockfd}<> "${LOCKFILE}" || exit 1
set +o noclobber # depends on what you need
flock --exclusive --nonblock ${lockfd} || exit 1

但我更喜欢注释和错误消息:

#!/bin/bash

# TODO Set a lock file name
LOCKFILE=/var/lock/myprogram.lock

# Set noclobber option to ensure lock file is not REPLACED.
set -o noclobber

# Open lock file for R+W on a new file descriptor
# and assign the new file descriptor to "lockfd" variable.
# This does NOT obtain a lock but ensures the file exists and opens it.
exec {lockfd}<> "${LOCKFILE}" || {
  echo "pid=$$ failed to open LOCKFILE='${LOCKFILE}'" 1>&2
  exit 1
}

# TODO!!!! undo/set the desired noclobber value for the remainder of the script
set +o noclobber

# Lock on the allocated file descriptor or fail
# Adjust flock options e.g. --noblock as needed
flock --exclusive --nonblock ${lockfd} || {
  echo "pid=$$ failed to obtain lock fd='${lockfd}' LOCKFILE='${LOCKFILE}'" 1>&2
  exit 1
}

# DO work here
echo "pid=$$ obtained exclusive lock fd='${lockfd}' LOCKFILE='${LOCKFILE}'"

# Can unlock after critical section and do more work after unlocking
#flock -u ${lockfd};
# if unlocking then might as well close lockfd too
#exec {lockfd}<&-

下面是一个使用锁文件并将PID回显到锁文件中的实现。如果进程在删除pidfile之前被杀死,这可以起到保护作用:

LOCKFILE=/tmp/lock.txt
if [ -e ${LOCKFILE} ] && kill -0 `cat ${LOCKFILE}`; then
    echo "already running"
    exit
fi

# make sure the lockfile is removed when we exit and then claim it
trap "rm -f ${LOCKFILE}; exit" INT TERM EXIT
echo $$ > ${LOCKFILE}

# do stuff
sleep 1000

rm -f ${LOCKFILE}

这里的技巧是kill -0,它不传递任何信号,只是检查具有给定PID的进程是否存在。此外,调用trap将确保即使进程被杀死(kill -9除外),锁文件也会被移除。

迟来的派对,使用来自@Majal的想法,这是我的脚本,只启动emacsclient GUI的一个实例。有了它,我可以设置快捷键打开或跳回相同的瘦弱。我有另一个脚本调用emacsclient在终端当我需要它。在这里使用emacsclient只是为了展示一个实际的例子,人们可以选择其他的东西。对于我的小脚本来说,这种方法足够快、足够好。告诉我哪里脏:)

#!/bin/bash

# if [ $(pgrep -c $(basename $0)) -lt 2 ]; then # this works but requires script name to be unique
if [ $(pidof -x "$0"|wc -w ) -lt 3 ]; then
    echo -e "Starting $(basename $0)"
    emacsclient --alternate-editor="" -c "$@"
else
    echo -e "$0 is running already"
fi

一些unix具有与前面提到的flock非常相似的lockfile。

从手册中:

Lockfile可以用来创建一个 或者更多的信号量文件。如果锁, 文件不能创建所有指定的 文件(在指定的顺序),它 等待睡眠时间(默认为8) 秒并重试最后一个文件 没有成功。您可以指定 直到重试的次数 返回失败。如果数字 重试次数为-1(默认值,即 -r-1)锁文件将永远重试。

已经回答了一百万次了,但是另一种方式,不需要外部依赖:

LOCK_FILE="/var/lock/$(basename "$0").pid"
trap "rm -f ${LOCK_FILE}; exit" INT TERM EXIT
if [[ -f $LOCK_FILE && -d /proc/`cat $LOCK_FILE` ]]; then
   // Process already exists
   exit 1
fi
echo $$ > $LOCK_FILE

每次它将当前PID($$)写入锁文件,并在脚本启动时检查进程是否正在使用最新的PID运行。