谁能告诉我为什么这行不通?
>>> import mock
>>> @mock.patch('datetime.date.today')
... def today(cls):
... return date(2010, 1, 1)
...
>>> from datetime import date
>>> date.today()
datetime.date(2010, 12, 19)
也许有人能提出一个更好的办法?
谁能告诉我为什么这行不通?
>>> import mock
>>> @mock.patch('datetime.date.today')
... def today(cls):
... return date(2010, 1, 1)
...
>>> from datetime import date
>>> date.today()
datetime.date(2010, 12, 19)
也许有人能提出一个更好的办法?
当前回答
你可以用这个来模拟datetime:
在sources.py模块中:
import datetime
class ShowTime:
def current_date():
return datetime.date.today().strftime('%Y-%m-%d')
在您的tests.py中:
from unittest import TestCase, mock
import datetime
class TestShowTime(TestCase):
def setUp(self) -> None:
self.st = sources.ShowTime()
super().setUp()
@mock.patch('sources.datetime.date')
def test_current_date(self, date_mock):
date_mock.today.return_value = datetime.datetime(year=2019, month=10, day=1)
current_date = self.st.current_date()
self.assertEqual(current_date, '2019-10-01')
其他回答
对于那些在测试类中使用补丁程序的人,下面是我如何成功地修补datetime功能:
from datetime import datetime
import unittest
from unittest.mock import Mock, patch
# Replace with the proper path to the module you would
# like datetime to be mocked
from path.to.my_module
class MyTestCases(unittest.TestCase):
def setUp(self):
"""execute on class instantiation"""
# Record both times at the same moment
self.dt_now, self.dt_utcnow = datetime.now(), datetime.utcnow()
# After retrieving real (or hardcoded datetime values),
# proceed to mock them in desired module
self.patch_datetime_functions()
def patch_datetime_functions(self) -> None:
"""
Patch datetime.now() and datetime.utcnow() to prevent issues when
comparing expected dates
"""
# Create a patcher
self.patcher_dt = patch(
'path.to.my_module'
)
# Start but make sure cleanup always occurs
self.patcher_dt.start()
self.addCleanup(self.patcher_dt.stop)
# Perform the actual patch – use lambdas as mock functions
datetime_mock = Mock(wraps=datetime)
datetime_mock.now.return_value = self.dt_now
datetime_mock.utcnow.return_value = self.dt_utcnow
my_module.datetime = datetime_mock
# Here's what it will look like when testing:
def some_test(self):
curr_dt = self.dt_now
returned_dt = my_module.datetime.utcnow()
# Compare the dates
self.assertEqual(curr_dt, returned_dt,
'Datetime values should be equal'
)
在Daniel G的解决方案中补充一点:
from datetime import date
class FakeDate(date):
"A manipulable date replacement"
def __new__(cls, *args, **kwargs):
return date.__new__(date, *args, **kwargs)
这将创建一个类,当实例化时,该类将返回一个正常的datetime。对象,但也可以更改。
@mock.patch('datetime.date', FakeDate)
def test():
from datetime import date
FakeDate.today = classmethod(lambda cls: date(2010, 1, 1))
return date.today()
test() # datetime.date(2010, 1, 1)
几天前我遇到了同样的情况,我的解决方案是在模块中定义一个函数来测试和模拟:
def get_date_now():
return datetime.datetime.now()
今天我发现了《FreezeGun》,它似乎很好地解决了这个问题
from freezegun import freeze_time
import datetime
import unittest
@freeze_time("2012-01-14")
def test():
assert datetime.datetime.now() == datetime.datetime(2012, 1, 14)
另一种选择是使用 https://github.com/spulec/freezegun/
安装:
pip install freezegun
并使用它:
from freezegun import freeze_time
@freeze_time("2012-01-01")
def test_something():
from datetime import datetime
print(datetime.now()) # 2012-01-01 00:00:00
from datetime import date
print(date.today()) # 2012-01-01
它还会影响其他模块的方法调用中的其他datetime调用:
other_module.py:
from datetime import datetime
def other_method():
print(datetime.now())
main.py:
from freezegun import freeze_time
@freeze_time("2012-01-01")
def test_something():
import other_module
other_module.other_method()
最后:
$ python main.py
# 2012-01-01
一般来说,你会有datetime或datetime。将日期导入某个模块。模拟该方法的一种更有效的方法是在导入它的模块上修补它。例子:
a.py
from datetime import date
def my_method():
return date.today()
然后,对于您的测试,模拟对象本身将作为参数传递给测试方法。您将使用所需的结果值设置模拟,然后调用测试中的方法。然后您可以断言您的方法完成了您想要的。
>>> import mock
>>> import a
>>> @mock.patch('a.date')
... def test_my_method(date_mock):
... date_mock.today.return_value = mock.sentinel.today
... result = a.my_method()
... print result
... date_mock.today.assert_called_once_with()
... assert mock.sentinel.today == result
...
>>> test_my_method()
sentinel.today
警告一句。很有可能嘲讽得过火了。当您这样做时,它会使您的测试更长、更难理解,并且不可能维护。在模拟像datetime.date这样简单的方法之前。今天,问问自己是否真的需要嘲笑它。如果您的测试短小精干,并且在不模拟函数的情况下运行良好,那么您可能只看到了正在测试的代码的内部细节,而不是需要模拟的对象。